Question

How many moles of N2 are essential for generating 0.08 moles of Li3N in the given reaction?6Li N2 2Li3N

Answer 1

Ans: 0.04 moles of N2 are essential to produce 0.08 moles of Li3N

Given :

Moles of Li3N generated = 0.08 moles

To determine:

Moles of N2 required

Explanation:

The chemical reaction is:

6Li + N2 → 2Li3N

Based on the reaction stoichiometry:

1 mole of N2 produces 2 moles of Li3N

Therefore, moles of N2 required to produce 0.08 moles of Li3N is:

$= \frac{0.08 moles Li3N * 1 mole N2}{2 moles Li3N} \\\\= 0.04 moles N2$

Answer 2

08 moles Li3N * 1mole N2/2moles Li3N = 0.04