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tester [92]
2 years ago
5

How many moles of N2 are essential for generating 0.08 moles of Li3N in the given reaction?6Li N2 2Li3N

Chemistry
2 answers:
r-ruslan [8.4K]2 years ago
6 0

<u>Ans: 0.04 moles of N2 are essential to produce 0.08 moles of Li3N</u>

<u>Given :</u>

Moles of Li3N generated = 0.08 moles

<u>To determine:</u>

Moles of N2 required

<u>Explanation:</u>

The chemical reaction is:

6Li + N2 → 2Li3N

Based on the reaction stoichiometry:

1 mole of N2 produces 2 moles of Li3N

Therefore, moles of N2 required to produce 0.08 moles of Li3N is:

= \frac{0.08 moles Li3N * 1 mole N2}{2 moles Li3N} \\\\= 0.04 moles N2

jeka57 [31]2 years ago
3 0
<span>08 moles Li3N * 1mole N2/2moles Li3N = 0.04 </span>
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The correct option is B.

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The Molecule of Sodium Formate along with Formal Charges (in blue) and lone pair electrons (in red) is attached below.

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5 0
2 years ago
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<span>We have the grams of the product, so we need the moles in order to calculate the molar weight. We us PV=nRT for this, assuming standard temperature and pressure. </span>
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I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
</span>
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