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nirvana33 [79]
2 years ago
5

Suppose that one of millikan's oil drops has a charge of −4.8×10−19

Chemistry
2 answers:
svlad2 [7]2 years ago
8 0

The best and correct option is c

Vanyuwa [196]2 years ago
8 0

<u>Answer:</u> The number of excess electrons that the drop contains are 3.

<u>Explanation:</u>

We are given:

Charge on millikan's oil drops = 4.8\times 10^{-19}C

To calculate the number of excess electrons, we divide the charge on millikan's oil drop by the change on 1 electron.

\text{Excess electrons}=\frac{\text{Charge on millikan's oil drop}}{\text{Charge on 1 electron}}

We know that:

Charge on 1 electron = 1.60\times 10^{-19}C

Putting values in above equation, we get:

\text{Excess electrons}=\frac{4.8\times 10^{-19}C}{1.60\times 10^{-19}C}\\\\\text{Excess electrons}=3

Hence, the number of excess electrons that the drop contains are 3.

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What is the molality of sodium chloride in solution that is 13.0% by mass sodium chloride and that has a density of 1.10 g/ml?
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Answer is: molality od sodium chloride is 2,55 mol/kg.
V(solution) = 100 ml.
m(solution) = d(solution) · V(solution).
m(solution) = 1,10 g/ml · 100 ml.
m(solution) = 110 g.
ω(NaCl) = 13,0% = 0,13.
m(NaCl) = ω(NaCl) · m(solution).
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2 years ago
A sample of an unknown compound with a mass of 0.847 g has the following composition: 50.51 % fluorine and 49.49 % iron. When th
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This is determined because even when the compound is decomposed, due to conservative law of mass, the decomposition process do not affect the amount of matter, so the mass of the elements remain even if they are separated from the original molecule.

At the end, the sum of the elements masses should be the total mass of the compound.

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We have to know the number of Na⁺ ions in the unit cell.

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