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nirvana33 [79]
2 years ago
5

Suppose that one of millikan's oil drops has a charge of −4.8×10−19

Chemistry
2 answers:
svlad2 [7]2 years ago
8 0

The best and correct option is c

Vanyuwa [196]2 years ago
8 0

<u>Answer:</u> The number of excess electrons that the drop contains are 3.

<u>Explanation:</u>

We are given:

Charge on millikan's oil drops = 4.8\times 10^{-19}C

To calculate the number of excess electrons, we divide the charge on millikan's oil drop by the change on 1 electron.

\text{Excess electrons}=\frac{\text{Charge on millikan's oil drop}}{\text{Charge on 1 electron}}

We know that:

Charge on 1 electron = 1.60\times 10^{-19}C

Putting values in above equation, we get:

\text{Excess electrons}=\frac{4.8\times 10^{-19}C}{1.60\times 10^{-19}C}\\\\\text{Excess electrons}=3

Hence, the number of excess electrons that the drop contains are 3.

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