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kherson [118]
2 years ago
7

A certain reaction has a 73.6% yield. if 53.8 grams of the product were predicted by stoichiometry to be made, what would the ac

tual yield be?
Chemistry
1 answer:
krok68 [10]2 years ago
5 0
Actual yield and theoretical yield are usually different.
the percentage yield of product = actual yield / theoretical yield x 100%
the theoretical yield is 53.8 g 
and percentage yield - 73.6 %
from the theoretical yield only 73.6 % of that amount is in the actual yield 
therefore actual yield is 73.6 % of 53.8 g
actual yield - 53.8 x 73.6% = 39.6 g
actual yield is 39.6 g
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<u>Answer:</u> The wavelength of light is 1.094\times 10^{-6}m

<u>Explanation:</u>

To calculate the wavelength of light, we use Rydberg's Equation:

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Where,

\lambda = Wavelength of radiation

R_H = Rydberg's Constant  = 1.097\times 10^7m^{-1}

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n_i = Initial energy level = 6

Putting the values in above equation, we get:

\frac{1}{\lambda }=1.097\times 10^7m^{-1}\left(\frac{1}{3^2}-\frac{1}{6^2} \right )\\\\\lambda =\frac{1}{914617m^{-1}}=1.094\times 10^{-6}m

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6 0
2 years ago
Calculate the amount of heat necessary to raise the temperature of 135.0 g of water from 50.4°F to 85.0°F. The specific heat of
MAXImum [283]

Here we have to calculate the heat required to raise the temperature of water from 85.0 ⁰F to 50.4 ⁰F.

10.857 kJ heat will be needed to raise the temperature from 50.4 ⁰F to 85.0 ⁰F

The amount of heat required to raise the temperature can be obtained from the equation H = m×s×(t₂-t₁).

Where H = Heat, s  =specific gravity = 4.184 J/g.⁰C, m = mass = 135.0 g, t₁ (initial temperature) = 50.4 ⁰F or 10.222 ⁰C and t₂ (final temperature) = 85.0⁰F or 29.444 ⁰C.

On plugging the values we get:

H = 135.0 g × 4.184 J/g.⁰C×(29.444 - 10.222) ⁰C

Or, H = 10857.354 J or 10.857 kJ.

Thus 10857.354 J or 10.857 kJ heat will be needed to raise the temperature.

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2 years ago
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Answer:

Explanation:

N₂       + 3H₂     =     2 NH₃

1 vol                         2 vol

786 liters               1572 liters

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We shall find this volume at NTP

volume V₂ = ?

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Rate of production of ammonia = .23 kg /s .

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8 0
2 years ago
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