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rjkz [21]
2 years ago
6

Silver nitrate and aluminum chloride react with each other by exchanging anions: 3agno3 (aq) + alcl3 (aq) → al(no3)3 (aq) + 3agc

l (s) what mass in grams of agcl is produced when 4.22 g of agno3 react with 7.73 g of alcl3?
Chemistry
2 answers:
lions [1.4K]2 years ago
5 0
Silver nitrate and aluminum chloride react with each other by exchanging anions: 3agno3 (aq) + alcl3 (aq) → al(no3)3 (aq) + 3agcl (s) what mass in grams of agcl is produced when 4.22 g of agno3 react with 7.73 g of alcl3?
Delvig [45]2 years ago
5 0

Answer: 3.6 grams

Explanation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

\text{Number of moles of silver nitrate}=\frac{4.22g}{170g/mol}=0.025moles

\text{Number of moles of aluminium chloride}=\frac{7.73g}{133g/mol}=0.06moles

3AgNO_3(aq)+AlCl_3(aq)\rightarrow Al(NO)_3)_3(aq)+3AgCl(s)

According to stoichiometry:

3 mole of AgNO_3 react with 1 mole of AlCl_3

0.025 moles of AgNO_3 react with =\frac{1}{3}\times 0.025=8.3\times 10^{-3}moles of AlCl_3

Thus AgNO_3 is the limiting reagent as it limits the formation of product and AlCl_3 is the excess reagent.

3 moles of AgNO_3 produce = 3 moles of AgCl

0.025 moles of AgNO_3 produce =\frac{3}{3}\times 0.025=0.025moles of AgCl

Mass of AgCl produced=moles\times {\text {Molar mass}}=0.025\times 143=3.6g

Thus 3.6 g of AgCl is produced.

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