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1 year ago

A grapefruit has a weight on earth of 4.9 newtons. what is grapefruit's mass

1 answer:

7 0

The force of gravity is the force with which massively large objects such as the earth attracts another object towards itself. All objects of the earth exert a gravity that is directed towards the center of the earth. Therefore, the force of gravity of the earth is equal to the mass of the object times acceleration due to gravity.

F = ma 
4.9N = m (9.8 m/s^2), note that N (newtons) = kg-m/s^2 
m = 0.5 kg
The mass of the object is 0.5kg.

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The density of o2 gas at 16 degrees Celsius and 1.27atm is?

velikii [3]

Answer:

The density of O₂ gas is 1.71 $\frac{g}{L}$

Explanation:

Density is a quantity that allows you to measure the amount of mass in a given volume of a substance. So density is defined as the quotient between the mass of a body and the volume it occupies:

$density=\frac{mass}{volume}$

An ideal gas is characterized by three state variables: absolute pressure (P), volume (V), and absolute temperature (T). The relationship between them constitutes the ideal gas law, an equation that relates the three variables if the amount of substance, number of moles n, remains constant and where R is the molar constant of the gases:

P * V = n * R * T

So, you can get:

$\frac{n}{V} =\frac{P}{R*T}$

The relationship between number of moles and mass is:

$n=\frac{mass}{molar mass}$

Replacing:

$\frac{\frac{mass}{molar mass} }{V} =\frac{P}{R*T}$

$\frac{mass}{V*Molar mass} =\frac{P}{R*T}$

So:

$\frac{mass}{V} =\frac{P*molar mass}{R*T}$

Knowing that 1 mol of O has 16 g, the molar mass of O₂ gas is 32 $\frac{g}{mol}$ .

Then:

$\frac{mass}{V} =\frac{P*molar mass of O_{2} }{R*T}$

In this case you know:

P=1.27 atm
molar mass of O₂= 32 $\frac{g}{mol}$ .

R= 0.0821 $\frac{atm*L}{mol*K}$

T= 16 °C= 289 °K (0°C= 273°K)

Replacing:

$density=\frac{mass}{V} =\frac{1.27atm*32\frac{g}{mol} }{0.0821\frac{atm*L}{mol*K} *289 K}$

Solving:

density= 1.71 $\frac{g}{L}$

The density of O₂ gas is 1.71 $\frac{g}{L}$

3 0

1 year ago

Plzzz help...

Anna [14]

Answer:

just answer this and you will have yours

Explanation:Find the area of a circle with a diameter of \color{green}{16}16start color green, 16, end color green.

Either enter an exact answer in terms of \piπpi or use 3.143.143, point, 14 for \piπpi and enter your answer as a decimal.

8 0

1 year ago

Be sure to answer all parts. The sulfate ion can be represented with four S―O bonds or with two S―O and two S═O bonds. (a) Which

VMariaS [17]

Answer:

a) Representation - (in attachment)

b) Tetrahedral geometry and

c) $sp^{3}$ hybrid orbitals invovle sigma bonding.

$\pi$ orbitals are formed by the overlapping of d-orbitals of sulfur with p-orbitals of oxygen.

Explanation:

Representation in attachment.

The overall charge in the both structures are -2. The structure (b) is favored by the resonance structures since the formal charge with in the species are remained.

Therefore, structure (b) is the better representation of sulfate ion.

In sulfate ion, sulfur atom is attached with four different oxygen atoms. According to the VSEPR theory , the sufate ion has tetrahedral geometry.

There is four sigma bonds and zero lone pairs present on the central metal atom.

Hence, the hybridization of the sulfur atom is $sp^{3}$

The s and p orbitals of sulfur invovles hybridization and form sigma bonds.The orbitals of sulfur involves $\pi$ bonding.

Therefore, $\pi$ bonds are formed by the overlapping of d-orbitals of sulfur with p-orbitals of oxygen.

5 0

2 years ago

What is the percent yield of sodium hydroxide in the given reaction? The reaction was performed using 45 g NaHCO3 and 18 g NaOH

Vlada [557]

Answer:

The percent yield = 83.33 %

Explanation:

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

For $NaHCO_3$ :-

Mass of water = 45 g

Molar mass of $NaHCO_3$ = 84.007 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles= \frac{45\ g}{84.007\ g/mol}$

$Moles\ of\ NaHCO_3= 0.54\ mol$

For $NaOH$ :-

Given mass = 18 g

Molar mass of NaOH = 39.997 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles= \frac{18\ g}{39.997\ g/mol}$

$Moles\ of\ NaOH= 0.45\ mol$

According to the given reaction:

$NaHCO_3\rightarrow NaOH+CO_2$

1 mole of $NaHCO_3$ on reaction forms 1 mole of $NaOH$

Thus,

0.54 mole of $NaHCO_3$ on reaction forms 0.54 mole of $NaOH$

Moles of $NaOH$ formed = 0.54 moles

Moles of $NaOH$ actually formed = 0.45 moles

The expression for the calculation of the percentage yield for a chemical reaction is shown below as:-

$\%\ yield =\frac {Experimental\ yield}{Theoretical\ yield}\times 100$

Given , Values from the question:-

Theoretical yield = 0.54 moles

Experimental yield = 0.45 moles

Applying the values in the above expression as:-

$\%\ yield =\frac{0.45}{0.54}\times 100$

$\%\ yield =83.33\ \%$

The percent yield = 83.33 %

7 0

1 year ago

Consider the following redox reaction: Ag⁺(aq) + Fe²⁺(aq) ⇌ Ag(s) + Fe³⁺(aq). How many moles of electrons are exchanged?

Kisachek [45]

Answer:

1 mol of electron is exchanged. The mol of electrons that is released by the iron, is gained by the silver.

Explanation:

We need to determine the half reactions:

Ag⁺ → Ag

These is the reduction reaction, where Silver decreases the oxidation state. It gained 1 mol of e⁻

Fe²⁺ → Fe³⁺

In this case, iron increases the oxidation state, from +2 to +3. It has released 1 mol of electrons. This is the oxidation reaction.

The complete redox is:

Ag⁺ + 1e⁻ → Ag

Fe²⁺ → Fe³⁺ + 1e⁻

Ag⁺(aq) + 1e⁻ + Fe²⁺(aq) ⇌ Ag(s) + Fe³⁺(aq) + 1e⁻

The electrons will be cancelled.

5 0

2 years ago