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stich3 [128]
1 year ago
15

The atmosphere supports a column of mercury that is 748 mm in height. What is atmospheric pressure in torr? Convert this pressur

e to atmospheres.
Chemistry
1 answer:
gulaghasi [49]1 year ago
7 0

Answer:

748 torr

Explanation:

mmHg and torr are equivalent so, you'll have 748 torr.

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Eugenol is a molecule that contains the phenolic functional group. Which option properly identifies the phenol in eugenol
givi [52]

Answer:

Explanation:

Hello,

Among the options given on the attached document, since phenolic functional group is characterized by a benzene ring bonded with a hydroxyl group (C₆H₅OH) we can see that the first option correctly points out such description. Thus, answer is on the second attached picture. Other options are related with other sections found in eugenol that are not phenolic.

Best regards.

3 0
2 years ago
What are three limitations of current cloaking technology.
kirill [66]

Explanation:

1.undetectable to electromagnetic waves

2.hiding an object from an illumination containing diffre t wave lengths become difficult as the object sizes grow.

3. reduce the scattering by two orders.

4 0
1 year ago
Earth’s early atmosphere was very different from our current atmosphere. Explain the presence or absence of gases in our current
Ivanshal [37]

Answer:

heavier gases - sank to the surface

lighter gases - escaped into space

oxygen - produced through photosynthesis

carbon dioxide - released by volcanoes

Explanation:

Since the formation of the atmosphere on Earth, there has been constant changes in it, gradually leading to the atmosphere that we have nowadays. In the distant past, the atmosphere was much different, and it took lot of time for it to become what it is. The volcanoes with their activity contributed to constant release of carbon dioxide, resulting in the greenhouse effect. The organisms that are able to perform photosynthesis started to release lot of oxygen into the atmosphere, thus setting up better living conditions. The gravity of our planet contributed to the vertical distribution of the gasses, with the heavier being lower, and the lighter ones being further up or released into space.

4 0
2 years ago
In a car piston shown above, the pressure of the compressed gas (red) is 5.00 atm. If the area of the piston is 0.0760 m^2. What
Shkiper50 [21]

Answer:

38503.5N

Explanation:

Data obtained from the question include:

P (pressure) = 5.00 atm

Now, we need to convert 5atm to a number in N/m2 in order to obtain the desired result of force in Newton (N). This is illustrated below:

1 atm = 101325N/m2

5 atm = 5 x 101325 = 506625N/m^2

A (area of piston) = 0.0760 m^2

Pressure is force per unit area. Mathematically it is written as

P = F/A

F = P x A

F = 506625 x 0.0760

F = 38503.5N

Therefore, the force exerted on the piston is 38503.5N

6 0
2 years ago
Suppose you wanted to make a buffer of exactly ph 7.00 using kh2po4 and na2hpo4. if the final solution was 0.10 m in kh2po4, wha
OleMash [197]

Answer:- 0.138 M

Solution:- The buffer pH is calculated using Handerson equation:

pH=pKa+log(\frac{base}{acid})

KH_2PO_4 acts as a weak acid and Na_2HPO_4 as a base which is pretty conjugate base of the weak acid we have.

The acid hase two protons(hydrogen) where as the base has only one proton. So, we could write the equation as:

H_2PO_4^-\rightleftharpoons H^++HPO_4^-^2

Phosphoric acid gives protons in three steps. So, the above equation is the second step as the acid has only two protons and the base has one proton.

So, we will use the second pKa value. The acid concentration is given as 0.10 M and we are asked to calculate the concentration of the base to make a buffer of exactly pH 7.00.

Let's plug in the values in the equation:

7.00=6.86+log(\frac{base}{0.10})

7.00-6.86=log(\frac{base}{0.10})

0.14=log(\frac{base}{0.10})

Taking antilog:

10^0^.^1^4=\frac{base}{0.10}

1.38=\frac{base}{0.10}

On cross multiply:

[base] = 1.38(0.10)

[base] = 0.138

So, the concentration of the base that is Na_2HPO_4 required to make the buffer is 0.138M.

5 0
2 years ago
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