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alexandr1967 [171]
2 years ago
12

In a fixed cylinder are 3moles of oxygen gas at 300Kelvin and 1.25atm. What is the volume of the container?

Chemistry
1 answer:
vladimir2022 [97]2 years ago
6 0

Answer:

The volume of the container is 59.112 L

Explanation:

Given that,

Number of moles of Oxygen, n = 3

Temperature of the gas, T = 300 K

Pressure of the gas, P = 1.25 atm

We need to find the volume of the container. For a gas, we know that,

PV = nRT

V is volume

R is gas constant, R =  0.0821 atm-L/mol-K

So,

V=\dfrac{nRT}{P}\\\\V=\dfrac{3\ mol\times 0.0821\ L-atm/mol-K \times 300\ K}{1.25\ atm}\\\\V=59.112\ L

So, the volume of the container is 59.112 L

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How many Ca2+ ions are in a sample of CaSO4 having a total mass of 68.07 g?
harkovskaia [24]

Answer:

There are  

17.01

Explanation:

The chemical formula for calcium phosphate is  

Ca

3

(PO

4

)

2

. This means that in one mole of calcium phosphate, there are three calcium ions and two phosphate ions.

6 0
1 year ago
Air in a 0.3 m3 cylinder is initially at a pressure of 10 bar and a temperature of 330K. The cylinder is to be emptied by openin
sergiy2304 [10]

Answer:

(a) Temperature = 330 K, and mass = 0.321 kg

(b) T₂ = 171.56 K, mass = 0.32223 kg

Explanation:

For a constant temperature process we have

p₁v₁ = p₂v₂

Where p₁ = initial pressure = 10 bar = 1000000 Pa

p₂ = final pressure = 1 atm = 101325 Pa

v₁ initial volume = 0.3 m³

v₂ = final volume = unknown

From the relation we have v₂ = 2.96 m³

Therefore at constant temperature 2.93 m³ - 0.3 m³ or 2.66 m³ will be expelled from the container

Temperature = 330 K, and mass =

Also from the relation p1v1 = mRT1

We have, (1000000×0.3)/(8314×330) = 109..337 mole

For air mass

Mass = 3.171 kg

After opening we have

p2v2/(RT1) = n2 = 11.07 mol or 0.321 kg

or

(b) This is said to be adiabatic condition hence

Here

But cp = 29 (J/mol K).

and p₁v₁ = RT₁ therefore R = 1000000*0.3/330 = 909.1 J/mol·K

And For perfect gas γ = 1.4

Hence T₂ = 171.56 K

γ =cp/cv therefore cv=cp/γ = 29/1.4 = 20.714 (J/mol K). and R =cp-cv = 8.29 J/mol·K

Therefore p1v1/(RT1) = 109.66 moles and we have

p2v2/(R×T2) = 11.11 mole left

For air that is 0.32223 kg

5 0
2 years ago
The gas described in parts a and b has a mass of 1.66 g. the sample is most likely which monatomic gas?
nordsb [41]
Mass of the gas m = 1.66 
The calculated temperature T = 273 + 20 = 293
 We have to calculate molar mass to determine the gas
 Molar Mass = mRT / PV
 M = (1.66 x 8.314 x 293) / (101.3 x 1000 x 0.001)
 M = 4043.76 / 101.3 = 39.92 g/mol
 So this gas has to be Argon Ar based on the molar mass.

7 0
1 year ago
Read 2 more answers
Iodine is blue-black, crystalline, and solid. It sublimes to a violet-colored gas and reacts with aluminum and many other metals
Pepsi [2]

Answer:

  • blue-black PHYSICAL PROPERTY
  • crystalline PHYSICAL PROPERTY
  • solid PHYSICAL PROPERTY
  • sublimes to a violet-colored gas PHYSICAL PROPERTY
  • reacts with aluminum and many other metals CHEMICAL PROPERTY

Explanation:

Chemical properties are visible through chemical reactions, in which the chemical identity changes to form new substances. On the other hand, physical properties are evident without a change in the identity of a substance.

<em />

<em>Which of these five properties are physical and which are chemical?</em>

  • blue-black PHYSICAL PROPERTY
  • crystalline PHYSICAL PROPERTY
  • solid PHYSICAL PROPERTY
  • sublimes to a violet-colored gas PHYSICAL PROPERTY
  • reacts with aluminum and many other metals CHEMICAL PROPERTY
4 0
1 year ago
2. The diagram below shows steps in the exothermic chemical reaction of bromomethane with
vovangra [49]

Answer:

Here's what I get  

Explanation:

1. Balanced equation

HQ⁻ + CH₃-Br ⟶ HQ-CH₃ + Br⁻

(I must use HQ because the Brainly Editor thinks the O makes a forbidden word)

2. Mechanism

HQ⁻ + CH₃-Br ⟶[HQ···CH₃···Br]⁻⟶ HQ-CH₃ + Br⁻

        A                           C                         B

The hydroxide ion attacks the back side of the carbon atom in the bromomethane (A).

At the same time as the Q-H bond starts to form, the C-Br bond starts to break.

At the half-way point, we have a high-energy intermediate (C) with partially formed C-O and C-Br bonds.

As the reaction proceeds further, the Br atom drops off to form the products — methanol and bromide ion (B).

3. Energy diagram

See the diagram below.

 

8 0
2 years ago
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