Answer:
2
Explanation:
Data:
[H⁺] = 0.01 mol·L⁻¹
Calculation:
pH = -log[H₃O⁺] = -log(0.01) = -log(1) - log(10⁻²) = -0 - (-2) = 0 + 2 = 2
2.10098*10^47 atoms
Because no. Of atoms = no. Of moles * avogadros no
Answer:

Explanation:
Hello!
In this case, since the applied current for the 50.0 mins provides the following charge to the system:

As 1 mole of electrons carries a charge of 1 faraday, or 96,485 coulombs, we can compute the moles of electrons involved during the reduction:

Then the reduction of Ga³⁺ to Ga involves the transference of three electrons, we are able to compute the moles and therefore the mass of deposited gallium:

Best regards!