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Feliz [49]
2 years ago
7

In the same condition, what happens to the net force acting on the rope?

Chemistry
1 answer:
Cerrena [4.2K]2 years ago
3 0

Answer:

Explained below

Explanation:

Newton's law of inertia states that An object at rest will remain continue at rest or if in motion, will continue in motion unless in both cases it is acted upon by a net external force.

Now, If two forces on the rope are equal and opposite forces, then the net force on the rope will be zero and it will not move. Thus,balance force is present in the rope and the rope will remain at rest since the net force is zero or it will continue in motion if already in motion without stopping since net force is zero

However, if the forces are acting in the same direction, it will result in an unbalanced force which means that the net force will be equal to the sum of the two forces and this will result in a stronger force than even the 2 individual forces and consequently it will cause the rope at rest to move, or if the rope is in motion, it will cause it to stop.

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Choose the answer in which the three atoms and/or ions are listed in order of increasing EXPECTED size (smallest particle listed
svp [43]

Answer:

Ar < Cl - < S2-

Explanation:

All the species written above are isoelectronic. This means that they all possess the same number of electrons. All the species above possess 18 electrons, the noble gas electron configuration.

However, for isoelectronic species, the greater the atomic number of the specie, the smaller it is. This is because, greater atomic number implies that their are more protons in the nucleus exerting a greater attractive force on the electrons thereby making the specie smaller in size due to high electrostatic attraction.

8 0
2 years ago
In a study of the decomposition of the compound XX via the reaction
Leya [2.2K]

Answer:

( About ) 0.03232 M

Explanation:

Based on the units for this reaction it should be a second order reaction, and hence you would apply the integrated rate law equation "1 / [X] = kt + 1 / [X_o]"

This formula would be true for the following information -

{ X_o = the initial concentration of X, k = rate constant, [ X ] = the concentration after a certain time ( which is what you need to determine ), and t = time in minutes }

________

Therefore, all we have left to do is plug in the known values. The initial concentration of X is 0.467 at a time of 0 minutes, as you can tell from the given data. This is not relevant to the time needed in the formula, as we need to calculate the concentration of X after 18 minutes ( time = 18 minutes ). And of course k, the rate constant = 1.6

1 / [X] = ( 1.6 )( 18 minutes ) + 1 / ( 0.467 ) - Now let's solve for X

1 / [X] = 28.8 + 1 / ( 0.467 ),

1 / [X] = 28.8 + 2.1413...,

1 / [X] = 31,

[X] = 1 / 31 = ( About ) 0.03232 M

Now for this last bit here you probably are wondering why 1 / 31 is not 0.03232, rather 0.032258... Well, I did approximate one of the numbers along the way ( 2.1413... ) and took the precise value into account on my own and solved a bit more accurately. So that is your solution! The concentration of X after 18 minutes is about 0.03232 M

3 0
2 years ago
How much silver can be produced from 125g of Ag2S
rosijanka [135]

Answer:

108.9g of Silver can be produced from 125g of Ag2S

Explanation:

The compound Ag2S shows that two atoms of Silver Ag, combined with an atom of Sulphur S to form Ag2S. We can as well say the combination ration of Silver to Sulphur is 2:1

•Now we need to calculate the molecular weight of this compound by summing up the molar masses of each element in the compound.

•Molar mass of Silver Ag= 107.9g/mol

•Molar mass of Sulphur S= 32g/mol

•Molecular weight of Ag2S= (2×107.9g/mol) + 32g/mol

•Molecular weight of Ag2S= 215.8g/mol + 32g/mol= 247.8g/mol

•From our calculations, we know that 215.8g/mol of Ag is present in 247.8g/mol of Ag2S

If 247.8g Ag2S produced 215.8g Ag

125g Ag2S will produce xg Ag

cross multiplying we have

xg= 215.8g × 125g / 247.8g

xg= 26975g/247.8

xg= 108.85g

Therefore, 108.9g of Silver can be produced from 125g of Ag2S

3 0
2 years ago
Read 2 more answers
Imagine you are a lab technician, and a colleague informs you there have been problems with the 25.0-mL samples you have been pr
stiks02 [169]

Answer:

22.5mL is the volume of the water

Explanation:

When the graduated cylinder is  in the 25.0mL mark, the mass of this volume is 22.4g. To convert this mass to volume we need to use density, as follows:

22.4g × (1mL / 0.99704g) = 22.5mL is the volume of the water.

That means the cylinder is uncalibrated in 2.5mL when the cylinder is in the 25.0mL mark

7 0
2 years ago
A running track measures 1056 ft per lap. To run 15.0 km, how many laps should you run?
Neporo4naja [7]

Answer:

46.6 laps

Explanation:

Step 1: Given data

  • Length of the lap (l): 1056 ft
  • Total distance to be run (d): 15.0 km

Step 2: Convert "l" to km

We will use the conversion factor 1 km = 3280.84 ft.

1056 ft × (1 km / 3280.84 ft) = 0.3219 km

Step 3: Calculate the number of laps that you should run

We will use the following expression.

laps = d/l

laps = 15.0 km/(0.3219 km/lap)

laps = 46.6 laps

7 0
2 years ago
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