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2 years ago

Mica and feldspar are chemically weathered into:

Chemistry

2 answers:

timofeeve [1]2 years ago

7 0

Answer:

sand grains and clay minerals.

Explanation:

Mica is a sheet of silicate minerals from a group of minerals that are closely related in chemical structure. Feldspar are a group of minerals that usually form rocks. Which is why they take up about 41% of the Earth's crust. When both of these are chemically weathered they create sand grains and clay minerals.

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

**Image 1 is Mica , and Image 2 is Feldspar**

Elina [12.6K]2 years ago

4 0

The answer would A. Sand grain I got 100 on the sedimentary assignment.

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Which of the following concerning second ionization energies is true?

Dennis_Churaev [7]

Answer:

Explanation:

The fact is that the both elements belong to different groups in the periodic table. Mg is in group 12 while Al is in group 13. The outer most electron configuration for Mg2+=[Ne]3s0

Al+= [Ne]3s13p0

It is evident that in Al+, the second electron is to be removed from a filled 3s subshell which is energetically unfavourable. Unlike In Mg2+ where the two electrons are removed. There is always a tendency towards a quick loss of all the valence electrons in the valence shell. It will be more difficult to remove an electron from a filled shell.

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2 years ago

The specific heat capacity of a pure substance can be found by dividing the heat needed to change the temperature of a sample of

mrs_skeptik [129]

Answer:

The answers to your questions are given below.

Explanation:

Data obtained from the question include:

Mass (M) = 420.0 g

Temperature change (ΔT) = 43.8 °C

Specific heat capacity (C) = 3.52 J/g °C

Heat needed (Q) =...?

The heat needed for the temperature change can be obtained by using the following formula:

Q = MCΔT

Where:

Q is the heat needed measured in joule (J).

M is the mass of substance measured in grams (g)

C is the specific heat capacity of the substance with unit J/g °C.

ΔT is the temperature change measured in degree celsius (°C).

Thus, we can calculate the heat needed to change the temperature as follow:

Q = MCΔT

Q = 420 x 3.52 x 43.8

Q = 64753.92 J

Therefore, the heat needed to cause the temperature change is 64753.92 J

4 0

2 years ago

To burn 1 molecule of C5H12 to form CO2 and H2O (complete combustion), how many molecules of O2 are required?

viva [34]

C5H12 + 8 O2 → 5 CO2 + 6 H2O

8 molecules of O2 are required.

5 0

2 years ago

Read 2 more answers

A 500 mL sample of a 0.100 M formate buffer, pH 3.75, is treated with 5 mL of 1.00 M KOH. What is the pH following this addition

lubasha [3.4K]

Answer: The pH of the solution after addition of KOH is 3.84

Explanation:

We are given:

pH of buffer = 3.75

$pK_a$ of formic acid = 3.75

Using Henderson-Hasselbalch equation for formate buffer:

$pH=pK_a+\log(\frac{[HCOO-]}{[HCOOH]})$

Putting values in above equation, we get:

$3.75=3.75+\log(\frac{[HCOO-]}{[HCOOH]})\\\\\log(\frac{[HCOO-]}{[HCOOH]})=0\\\\\frac{[HCOO-]}{[HCOOH]}=1$

$[HCOO-]=[HCOOH]$

We are given:

Concentration of formate buffer = 0.100 M

$[HCOO-]+[HCOOH]=0.1$

$[HCOO-]=[HCOOH]=0.05M$

As, the volume of buffer is the same. So, the concentration is taken as number of moles of formate ions as well as formic acid

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in mL)}}$

Molarity of KOH = 1.00 M

Volume of solution = 5 mL

Putting values in above equation, we get:

$1.00M=\frac{\text{Moles of KOH}\times 1000}{5mL}\\\\\text{Moles of KOH}=0.005mol$

The chemical reaction for formic acid and KOH follows the equation:

$HCOOH+KOH\rightarrow HCOO^-+H_2O$

Initial: 0.05 0.005 0.05

Final: 0.045 - 0.055

Volume of solution = 500 + 5 = 505 mL = 0.505 L (Conversion factor: 1 L = 1000 mL)

To calculate the pH of acidic buffer, we use the equation given by Henderson Hasselbalch:

$pH=pK_a+\log(\frac{[salt]}{[acid]})$

$pH=pK_a+\log(\frac{[HCOO^-]}{[HCOOH]})$

We are given:

$pK_a$ = negative logarithm of acid dissociation constant of formic acid = 3.75

$[HCOO^-]=\frac{0.055}{0.505}$

$[HCOOH]=\frac{0.045}{0.505}$

pH = ?

Putting values in above equation, we get:

$pH=3.75+\log(\frac{0.055/0.505}{0.045/0.505})\\\\pH=3.84$

Hence, the pH of the solution after addition of KOH is 3.84

3 0

2 years ago

If you have 2.41 × 1024 atoms of copper, how many moles of copper do you have? If you have 2.41 atoms of copper, how many moles

Bogdan [553]

Answer:

4.00 moles

Explanation:

Avogadro´s number is 6.022 x 10²³ molecules, atoms, particles, etc.

Here we are talking of atoms of copper, so 1 mol of copper is equal to 6.022 x 10²³ atoms, and we only need to setup the proportion to find the number of mol in 2.41 x 10²⁴ atoms. ( Think of it like a dozen, avogadro´s is 6.022 x 10²³ )

( 1 mol copper/ 6.022 x 10²³ atoms of copper ) x 2.41 x 10²⁴ atoms

= 4.00 moles

4 0

2 years ago