Answer:
1.The diagram is attached
2.sodium alginate is a polymer which can be extracted from brown seaweed and is used for defloculating, gelling and thickening
Used also in dermatological preparation
Used in adhensive paste
Hybridization in ozone, O3......
<span>...O = O ........ 1 lone pair on central O, 2 lone pairs on terminal O </span>
<span>../ </span>
<span>O .................. 3 lone pairs on terminal O </span>
<span>I didn't show the second of two resonance structures in which the single and double bonds are reversed. In reality, both bonds are identical have a bond order of 1.5 due to delocalized pi-bonding. </span>
<span>The central atom exhibits sp2 hybridization since there is trigonal planar electron pair geometry. The notion of hybrid orbitals was "invented" by Linus Pauling in the 1930's as a way of explaining the geometry of molecules, primarily the geometry of carbon compounds. </span>
<span>If the electron pair geometry is linear, the hybridization is sp. </span>
<span>If the electron pair geometry is trigonal planar, the hybridization is sp2. </span>
<span>If the electron pair geometry is tetrahedral, the hybridization is sp3. </span>
<span>The notion that there is sp3d and sp3d2 because of d-orbital participation has been debunked. Chemists know today that there is no d-orbital involvement in hypervalent molecules regardless of what some out-of-date textbooks and some teachers' dusty old notes may say. Instead, the best explanation involves 3-center, 4-electron bonding.</span>
I would he would try to enter as the tide is rising, and leave as the tide is falling. Those things happen at all different times of day during a month. Hope it helps!!
Answer:
C3H8 + 5O2 ====> 3CO2 + 4H20
Answer:
Before we start answering, the appropiate equation for the energy of an ionic bond should be written:

Where A1+, B2- are the charges of the ions and Ro is the interionic distance (the sum of the radii of the anion and cation). C is a constant depending on the ionic structure.
Explanation:
Examining the equation above, we have the following scenarios:
a) Doubling the radius of A1 would mean a decrease on the energy of the ionic bond.
b) Tripling the charge of A1 would also triple the energy of the ionic bond
c)Doubling the charges on A1 and B2 would quadruple the energy of the ionic bond.
d)Decreasing the radii of A1 and B2 to half their original values would double the energy of the energy bond.