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maksim [4K]
2 years ago
9

Jason is preparing curry from an Indian cookbook his British brother-in-law gee him for his birthday. Unfortunately, the British

cookbook is written with units he does not typically use, so he must do some conversions before getting to work in the kitchen *) The recipe calls for 450 g of diced chicken. How many pounds of chicken should he defrost? b) The recipe calls for 125 g of diced onions. How many 4 oz onions should he dice? c) The recipe calls for 100 mL of coconut milk. How many cups should he add
Chemistry
1 answer:
Marina CMI [18]2 years ago
6 0

Answer:

0.99 pounds

2,000 oz

0.423 cups

Explanation:

In order  to convert this units we need to look up their equivalences.

1 g equals 0,0022 pounds approximately

Then we need to cross-multiply:

\frac{1 g}{0.0022 pounds} = \frac{450 g}{ Xpounds} \\x = \frac{450 g x 0.0022 pounds}{1 g}

450 g equals 0.99 pounds approximately

We can do the same calculation for the other 2 ingredients

1 g equals 16 oz

Then (125 g x 16 oz) / 1 oz = 2,000 oz  (or 500 4 oz)

1 cup equals 236.59 ml

Then (100 ml x 1 cup)/ 236.59 = 0.423 cups

You might be interested in
A. The measured pH of a 0.100 M HCl solution at 25 degrees Celsius is 1.092. From this information, calculate the activity coeff
ra1l [238]

Answer:

activity coefficient \mathbf{\gamma =0.809}

activity coefficient \mathbf{\gamma = 0.791}

The change in pH in part A = 0.092

The change in pH in part B =  0.102

Explanation:

From the given information:

pH of HCl solution = 1.092

Activity of the pH solution [a] = 10^{-1.092}

[a] = 0.0809 M

Recall that [a] = \gamma × C

where;

\gamma  = activity coefficient

C = concentration

Making the activity coefficient the subject of the formula, we have:

\gamma = \dfrac{[a]}{C}

\gamma = \dfrac{0.0809 \ M}{0.100  \ M}

\mathbf{\gamma =0.809}

B.

The pH of a solution of HCl and KCl = 2.102

[a] = 10^{-2.102}

[a] = 0.00791 M

activity coefficient \gamma = \dfrac{0.00791 \ M}{0.01 \ M}

\mathbf{\gamma = 0.791}

C. The change in pH in part A = 1.091 - 1.0 = 0.092

The change in pH in part B = 2.102 -2.00 = 0.102

3 0
2 years ago
Label each statement with its corresponding type of scientific knowledge. law theory fact hypothesis The melting point of ice is
EleoNora [17]

Answer:

Follows are the solution to this question:

Explanation:

  • Fact: In this, the ice is melted at 0 ° C.  
  • law: It is used to repeated experiments consistently showed which objects marked to both the contrary attract each law.  
  • Hypothesis: If carbohydrates and nitrogen are combined at 1500 ° C, they interact with one another.    
  • Theory: Protons, nuclei, or ions are made of Atoms. As these molecules could not be seen explicitly, such legal structure several experimental observations.
3 0
2 years ago
At 10°c one volume of water dissolves 3.10 volumes of chlorine gas at 1.00 atm pressure. what is the henry's law constant of cl2
s344n2d4d5 [400]
Answer is:  0,133 mol/ l· atm.
T(chlorine) = 10°C = 283K.
p(chlorine) = 1 atm.
V(chlorine) = 3,10 l.
R - gas constant, R = 0.0821 atm·l/mol·K. 
Ideal gas law: p·V = n·R·T
n(chlorine) = p·V ÷ R·T.
n(chlorine) = 1atm · 3,10l ÷ 0,0821 atm·l/mol·K · 283K = 0,133mol.
Henry's law: c = p·k.
k - <span>Henry's law constant.
</span>c - solubility of a gas at a fixed temperature in a particular solvent.
c = 0,133 mol/l.
k = 0,133 mol/l ÷ 1 atm = 0,133 mol/ l· atm.

4 0
2 years ago
Which describes any compound that has at least one element from group 17?
Contact [7]
The answer is HALIDE.
6 0
2 years ago
Picric acid has been used in the leather industry and in etching copper. However, its laboratory use has been restricted because
olchik [2.2K]

Answer:

0.3023 M

Explanation:

Let Picric acid = H_{picric}

So,  H_{picric}     +       H_2}O          ⇄      H_3}O^+     +     Picric^-

The ICE table can be given as:

                          H_{picric}     +       H_2}O          ⇄      H_3}O^+     +     Picric^-

Initial:                0.52                                               0                  0

Change:             - x                                                 + x                 + x

Equilibrium:      0.52 - x                                        + x                 + x

Given that;

acid dissociation constant  (K_a) = 0.42

K_a = \frac{[H_3O^+][Picric^-]}{H_{picric}}

0.42 = \frac{[x][x]}{0.52-x}}

0.42 = \frac{[x]^2}{0.52-x}}

0.42(0.52-x) = x²

0.2184 - 0.42x = x²

x²  + 0.42x - 0.2184 = 0                   -------------------- (quadratic equation)

Using the quadratic formula;

\frac{-b+/-\sqrt{b^2-4ac} }{2a}    ;     ( where +/-  represent ± )

= \frac{-0.42+/-\sqrt{(0.42)^2-4(1)(-0.2184)} }{2*1}

= \frac{-0.42+/-\sqrt {0.1764+0.8736} }{2}

= \frac{-0.42+\sqrt {1.0496} }{2}     OR   \frac{-0.42-\sqrt {1.0496} }{2}

= \frac{-0.42+1.0245}{2}       OR    \frac{-0.42-1.0245}{2}

= \frac{0.6045}{2}                 OR    -\frac{1.4445}{2}

= 0.30225          OR     - 0.72225

So, we go by the +ve integer that says:

x =  0.30225

x = [ H_3}O^+ ] = [   Picric^- ] =  0.3023  M

∴  the value of  [H3O+] for an 0.52 M solution of picric acid  = 0.3023 M     (to 4 decimal places).

6 0
2 years ago
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