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Volgvan
2 years ago
10

Which of the following statements is true of an aqueous solution of sodium chloride? A]One that has 30.0 grams of NaCl dissolved

in 100 grams of water is more concentrated than one that has 15.0 grams of NaCl dissolved in 100 grams of water. B]One that has 30.0 grams of NaCl dissolved in 100 grams of water is more dilute than one that has 15.0 grams of NaCl dissolved in 100 grams of water. C[One that has 30.0 grams of NaCl dissolved in 100 grams of water would have the same molarity as one that has 15.0 grams of NaCl dissolved in 100 grams of water. D]One that has 30.0 grams of NaCl dissolved in 100 grams of water has less solute than one that has 15.0 grams of NaCl dissolved in 100 grams of water.
Chemistry
2 answers:
andrew11 [14]2 years ago
3 0
<span>One that has 30.0 grams of NaCl dissolved in 100 grams of water is more concentrated than one that has 15.0 grams of NaCl dissolved in 100 grams of water. A is the correct answer.</span>
garri49 [273]2 years ago
3 0

Answer: Option (A) is the correct answer.

Explanation:

When 30 g of NaCl is dissolven in 100 g of water then it means NaCl is the solute and water is the solvent.

More is the amount of solute present in a solution more concentrated the solution will be.

For example, an aqueous solution with 30.0 grams of NaCl dissolved in 100 grams of water is more concentrated than one that has 15.0 grams of NaCl dissolved in 100 grams of water.

Whereas molarity is the number of moles present in a liter of solution.

Also,    Molarity = \frac{mass}{\text{molar mass} \times Volume}

As molar mass of NaCl is 58.44 g/mol. Therefore, assuming volume as 1 L then molarity of a solution containing 30 g of NaCl is as follows.

        Molarity = \frac{mass}{\text{molar mass} \times Volume}

                       = \frac{30 g}{58.44 g/mol \times 1 L}

                       = 0.513 M

Whereas molarity of a solution containing 15 g of NaCl is as follows.

           Molarity = \frac{mass}{\text{molar mass} \times Volume}

                       = \frac{15 g}{58.44 g/mol \times 1 L}

                       = 0.256 M

This shows that molarity of both the solutions is not the same.

Thus, we can conclude that the statement one that has 30.0 grams of NaCl dissolved in 100 grams of water is more concentrated than one that has 15.0 grams of NaCl dissolved in 100 grams of water, is true of an aqueous solution of sodium chloride.

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Andrej [43]
The way to working out the numbers is to increase the measure of HNO3 required by the molarity to discover what number of moles you require: 0.115. You ought to have the capacity to make sense of the recipe weight H is 1, N is 14, O is 16. The result of the quantity of moles duplicated by the recipe weight ought to give an esteem in grams. You can utilize the thickness to change over to a volume of HNO3 to add to the right volume of water.
6 0
2 years ago
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What is the name of the functional group that is attached to this hydrocarbon? The first and last of a chain of three carbons ar
disa [49]

Answer:

Ketone

Explanation:

As you are stating here, we have a carbonated chain of three carbons, and the first and last has 3 Hydrogens, then this means that we have CH₃ . The center carbon is a carbon double bonded to oxygen.

In general terms this belongs to the carbonyl group. However, this alone does not represent a functional group, but when it's in a chain with other radycals or chains, it becomes a functional group.

In this case, the molecule you are talking here is the following:

CH₃ - CO - CH₃

This molecule is known as the Acetone, and has the general form of:

R - CO - R'

Which belongs to a ketone as a functional group.

4 0
1 year ago
If 25 g of NH3, and 96 g of H2S react according to the following reaction, what is the
jeyben [28]

25 g of NH₃ will produce 47.8 g of (NH₄)₂S​

<u>Explanation:</u>

2 NH₃ + H₂S ----> (NH₄)₂S​

Molecular weight of NH₃ = 17 g/mol

Molecular weight of (NH₄)₂S​ = 68 g/mol

According to the balanced reaction:

2 X 17 g of NH₃ produces 68 g of (NH₄)₂S​

1 g of NH₃ will produce \frac{68}{34} g of (NH₄)₂S​

25g of NH₃ will produce \frac{65}{34} X 25 g of (NH₄)₂S​

                                     = 47.8 g of (NH₄)₂S​

Therefore, 25 g of NH₃ will produce 47.8 g of (NH₄)₂S​

4 0
2 years ago
a 75.0 liter canister contains 15.82 moles of argon at a pressure of 546.8 kilopascals. What is the temperature of the canister?
abruzzese [7]

Pressure of argon = 546.8 kPa

Conversion factor: 1 atm = 101.325 kPa

Pressure of argon = 546.8 kPa x 1 atm/101.325 kPa = 5.4 atm

Moles of argon = 15.82

Volume of argon = 75.0 L

According to Ideal gas law,

PV = nRT

where P is the pressure, V is the volume , n is the number of moles, R is the universal gas constant, and T is the temperature

T = PV/nR = (5.4 atm x 75.0 L) / (15.82 x 0.0821 L.atm.mol⁻¹K⁻¹)

T = 311.82 K

Hence the temperature of the canister is 311.82 K.

4 0
2 years ago
The volume of a gas at 7.00°c is 49.0 ml. if the volume increases to 74.0 ml and the pressure is constant, what will the tempera
marshall27 [118]
Using charles law
v1/t1=v2/t2
v1=49ml
v2=74
t1=7+273=280k
t2=?
49/280=74/t2
0.175=74/t2  cross multiply
0.175t2=74
t2=74/0.175
t2=422k or 149celcius
8 0
1 year ago
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