Which of the following statements is true of an aqueous solution of sodium chloride? A]One that has 30.0 grams of NaCl dissolved
2 answers:
Answer: Option (A) is the correct answer.
Explanation:
When 30 g of NaCl is dissolven in 100 g of water then it means NaCl is the solute and water is the solvent.
More is the amount of solute present in a solution more concentrated the solution will be.
For example, an aqueous solution with 30.0 grams of NaCl dissolved in 100 grams of water is more concentrated than one that has 15.0 grams of NaCl dissolved in 100 grams of water.
Whereas molarity is the number of moles present in a liter of solution.
Also, Molarity =
As molar mass of NaCl is 58.44 g/mol. Therefore, assuming volume as 1 L then molarity of a solution containing 30 g of NaCl is as follows.
Molarity =
=
= 0.513 M
Whereas molarity of a solution containing 15 g of NaCl is as follows.
Molarity =
=
= 0.256 M
This shows that molarity of both the solutions is not the same.
Thus, we can conclude that the statement one that has 30.0 grams of NaCl dissolved in 100 grams of water is more concentrated than one that has 15.0 grams of NaCl dissolved in 100 grams of water, is true of an aqueous solution of sodium chloride.
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</span><span>Note: MnO2 (Manganese Dioxide) is not part of the reaction. A catalyst lowers the activation energy and increases both forward and reverse reactions at equal rates.
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molar mass of KClO3 = 122.5
Moles of KClO3 = 3.45 / 122.55 = 0.028
Moles of O2 produce =
= 0.042 moles
molar mass of O2 = 32
so, mass of O2 = 32 x 0.042 = 1.35 g
</span><span>Note: MnO2 (Manganese Dioxide) is not part of the reaction. A catalyst lowers the activation energy and increases both forward and reverse reactions at equal rates.
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molar mass of KClO3 = 122.5
Moles of KClO3 = 3.45 / 122.55 = 0.028
Moles of O2 produce =
= 0.042 moles
molar mass of O2 = 32
so, mass of O2 = 32 x 0.042 = 1.35 g
Explanation:
The given data is as follows.
Moles of propylene = 100 moles, = 300 K
= 800 K,
,
of propylene = 100 J/mol
Now, we assume the following assumptions:
Since, it is a compression process therefore, work will be done on the system. And, work done will be equal to the heat energy liberating without any friction.
W =
=
= 5 MJ
Thus, we can conclude that a minimum of 5 MJ work is required without any friction.