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ohaa [14]
1 year ago
9

How many simple distillation columns are required to purify a stream containing five components into five 'pure"products? Sketch

all possible sequences.

Chemistry
1 answer:
Nitella [24]1 year ago
3 0

Answer: one simple distillation column is required to separate the stream into five pure products. With four different flat bottom flask, for collection of the distilled products

Explanation: simple distillation works with the difference in boiling points of the liquid to be separated. For the separation of five different constituent to be possible, we have to know the boiling points of the constituents.

For your understanding, let's define constituents in the liquid to be A, B, C, D, E. And the boiling points increases respectively. Start by heating the liquid to the boiling point of A to extract A. After a while check if the constituents A is still dropping in the flat bottom flask, if it has stopped dropping, it simply means that we have extracted all A constituents in the liquid, label the Flask A. Get another flask to extract constituent B.

Heat the mixture to the boiling point of B, after a while check if constituent B is still dropping in the flat bottom flask, if it has stopped dropping,it means that we have extracted all B constituent in the liquid, label the Flask B. Get another flask for C.

Repeat the same process for C and D.

After Extracting D we don't need to distillate E because we already have a pure form of E inside to the conical flask.

SEE PICTURE TO UNDERSTAND WHAT A SIMPLE DISTILLATION LOOKS LIKE

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Caffeine, a molecule found in coffee, tea, and certain soft drinks, contains C, H, O, and N. Combustion of 10.0 g of caffeine pr
denis-greek [22]

Answer:

194 g/mol.

Explanation:

Hello,

In this case, one first must compute the mass of each element as shown below:

C=18.13gCO_2*\frac{12gC}{44gCO_2} =4.945gC\\H=4.639gH_2O*\frac{2.016gH}{18.0152gH_2O}=0.519gH\\N=2.885gN_2\\O=10.0g-4.945g-0.519g-2.885g=1.651gO

Next, the corresponding moles:

C=4.945gC*\frac{1molC}{12gC}=0.412mol\\H=0.519gH*\frac{1molH}{1gH}=0.519mol\\N=2.885gN*\frac{1molN}{14gN}=0.206molN\\O=1.648gO*\frac{1molO}{16gO} =0.103molO

Then, each element's subscripts is found to be:

C=\frac{0.412}{0.103}=4\\H=\frac{0.519}{0.103}=5\\N=\frac{0.206}{0.103} =2\\O=\frac{0.103}{0.103}=1

Therefore, the empirical formula is:

C_4H_5N_2O

Nonetheless, it has a molar mass of 97bg/mol, thereby, by multiplying such formula by 2 one gets:

C_8H_10N_4O_2

Which has a molar mass of 194 g/mol being correctly contained in the given interval.

Best regards.

8 0
2 years ago
Valence bond theory predicts that bromine will use _____ hybrid orbitals in brf5.
koban [17]

Answer:

the correct answer is (sp3d2) (d)

Explanation:

5 0
2 years ago
Here is a sketch of a 2px orbital: This sketch is about 800pm wide. The coordinate ( x , y , and z ) axes are also shown. You ca
amid [387]
<span><u>PA to PB 100 pm to the left of the nucleus, along the -x axis.</u>
<u>100 pm below the nucleus along the -z axis.</u>

PAPB 100 pm in front of the nucleus, along the -y axis. 100 pm behind the nucleus, along the +y axis.

PAPB 100 pm to the right of the nucleus, along the +x axis. 100 pm above the nucleus, along the +z axis. </span>
7 0
1 year ago
Glucose has a molecular mass of 180 daltons. to make a 2-molar (2 m) solution of glucose, __________.
aksik [14]

The molality of a substance is the moles of the substance present in 1000mL or 1L or 1Kg of water. 1L of water is equivalent to 1Kg of water as the density of water is 1g/mL. The molecular mass of a substance is represent the amount of the substance present in 1 mole of the compound. Here the molar mass of glucose is 180 daltons thus 1 mole of glucose is equivalent to 180 daltons. To prepare 1 molar glucose solution 180 daltons of glucose have to dissolve in 1L of water. So to prepare 2 molar glucose solution (180×2) = 360 daltons of glucose have to dissolve in 1000mL or 1L or 1Kg of water.

6 0
2 years ago
The net ionic equation for formation of an aqueous solution of NiI 2 accompanied by evolution of CO 2 gas via mixing solid NiCO
Naily [24]

Answer:NiCO_3(s)+2H^+(aq)\rightarrow Ni^{2+}(aq)+CO_2(g)+H_2O(l)

Explanation:

Spectator ions are defined as the ions which does not get involved in a chemical equation or they are ions which are found on both the sides of the chemical reaction present in ionic form.

The balanced chemical equation will be:

NiCO_3(s)+2HI(aq)\rightarrow NiI_2(aq)+CO_2(g)+H_2O(l)

The total ionic chemical equation will be:

NiCO_3(s)+2H^+(aq)+2I^-(aq)\rightarrow Ni^{2+}(aq)+2I^-(aq)+CO_2(g)+H_2O(l)

The ions which are present on both the sides of the equation are iodide ions and hence are not involved in net ionic equation.

NiCO_3(s)+2H^+(aq)\rightarrow Ni^{2+}(aq)+CO_2(g)+H_2O(l)

6 0
2 years ago
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