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2 years ago

Which of these facts best illustrates why regulation of alcohol consumption is necessary

Chemistry

1 answer:

exis [7]2 years ago

4 0

So that people don’t break laws or drive under the influence.

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A heat pump is used to heat a house in the winter and to cool it in the summer. During the winter, the outside air serves as a l

elixir [45]

Answer:

$T_{C}$ = -4.2°C

$T_{H}$ = 49.4°C

Explanation:

A Carnot cycle is known as an ideal cycle in thermodynamic. Therefore, in theory, we have:

| $\frac{Q_{C} }{Q_{H} }$ | = $\frac{T_{C} }{T_{H} }$

Similarly,

| $Q_{H}$ | = | $Q_{C}$ | + | $W_{S}$ |

During winter, the value of | $T_{H}$ | = 20°C = 273.15 + 20 = 293.15 K and | $W_{S}$ | = 1.5 kW. Therefore,

| $Q_{H}$ | = 0.75( $T_{H}$ - $T_{C}$ )

Similarly,

| $\frac{W_{S} }{Q_{H} }$ | = 1 - $\frac{T_{C} }{T_{H} }$

1.5/0.75*(293.15- $T_{C}$ ) = 1 - ( $T_{C}$ /293.15

Further simplification,

$T_{C}$ = -4.2°C

During summer, $T_{C}$ = 25°C = 273.15+25 = 298.15 K, and | $W_{S}$ | = 1.5 kW. Therefore,

| $Q_{C}$ | = 0.75( $T_{H}$ - $T_{C}$ )

Similarly,

| $\frac{W_{S} }{Q_{C} }$ | = $\frac{T_{H} }{T_{C} }$ - 1

1.5/0.75*( $T_{H}$ - 298.15) = ( $T_{H}$ /298.15

Further simplification,

$T_{H}$ = 49.4°C

4 0

2 years ago

What number will go in the _?_ below to balance the equation?

Ulleksa [173]

Answer:

Option F 6 will be the answer.

5 0

2 years ago

Samples of three different compounds were analyzed and the masses of each element were determined. Compound Mass N (g) Mass O (g

schepotkina [342]

Answer is: c. N2O, N2O4, N2O5.

Law of multiple proportions or Dalton's Law said that the ratios of the masses of the second element which combine with a fixed mass of the first element will be ratios of small whole numbers.

1) NO; m(N) : m(O) = 14 : 16 = 7 : 8.

2) N₂O; m(N) : m(O) = 2·14 : 16 = 7 : 4.

3) NO₂; m(N) : m(O) = 14 : 2·16 = 7 : 16.

4) N₂O₅; m(N) : m(O) = (2·14) : (5·16) = 7 : 20.

5) NO₄; m(N) : m(O) = 14 : (4·16) = 7 : 32.

6) N₂O₄; m(N) : m(O) = (2·14) : (4·16) = 7 : 16.

A) m(N) : m(O) = 5.6 g : 3.2 g /÷3.2

m(N) : m(O) = 1.75 : 1 /×4.

m(N) : m(O) = 7 : 4.

B) m(N) : m(O) = 3.5 g : 8.0 g /÷3.5

m(N) : m(O) = 1 : 2.285/ ×7.

m(N) : m(O) = 7 : 16.

C) m(N) : m(O) = 1.4 g : 4.0 g / ÷ 1.4.

m(N) : m(O) = 1 : 2857/ ×7.

m(N) : m(O) = 7 : 20.

6 0

2 years ago

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How many moles of lead (ii) chromate are in 51 grams of this substance? answer in units of mol?

maria [59]

Mass of lead (II) chromate is 51 g. The molecular formula is $PbCrO_{4}$ and its molar mass is 323.2 g/mol

Number of moles can be calculated using the following formula:

$n=\frac{m}{M}$

Here, m is mass and M is molar mass.

Putting the values,

$n=\frac{(51 g}{323.1937 g/mol}=0.1578 mol$

Therefore, number of moles of lead (II) chromate will be 0.1578 mol.

5 0

2 years ago

Calculate the average time it took the car to travel 0.25 What is the average time it took the car to travel 0.25

DedPeter [7]

Answer:

Explanation:

idk why all u guys like trump who do.. hes just a big pain in the a*s.

8 1

2 years ago

Read 2 more answers