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butalik [34]
2 years ago
12

A certain alcoholic beverage contains only ethanol (C2H6O) and water. When a sample of this beverage undergoes combustion, the e

thanol burns but the water simply evaporates and is collected along with the water produced by combustion. The combustion reaction is: C2H6O(l) + 3O2(g) → 2CO2(g) + 3H2O(g) when a 10.00 g sample of this beverage is burned, 11.27 g of water is collected. a) What is the mass of ethanol in the original sample? Enter a numerical answer in grams.
Chemistry
1 answer:
Archy [21]2 years ago
7 0

Answer:

9.606 g

Explanation:

Step 1: Write the balanced combustion reaction

C₂H₆O(l) + 3 O₂(g) → 2 CO₂(g) + 3 H₂O(g)

Step 2: Calculate the moles corresponding to 11.27 g of H₂O

The molar mass of H₂O is 18.02 /mol.

11.27 g × (1 mol/18.02 g) = 0.6254 mol

Step 3: Calculate the moles of C₂H₆O that formed 0.6254 moles of H₂O

The molar ratio of C₂H₆O to H₂O is 1:3. The moles of C₂H₆O are 1/3 × 0.6254 mol = 0.2085 mol

Step 4: Calculate the mass corresponding to 0.2085 moles of C₂H₆O

The molar mass of C₂H₆O is 46.07 g/mol.

0.2085 mol × 46.07 g/mol = 9.606 g

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The metallic radius of a potassium atom is 231 pm. What is the volume of a potassium atom in cubic meters?
Sauron [17]
1 pm = 10∧-10 cm
Therefore, 230 pm is equivalent to 2.3 ×10∧-8 cm.
Atom is in the shape of a sphere,
The volume of a sphere is given by 4/3πr³
Thus, volume of the atom = 4/3π( 2.3 ×10∧-8)³
                                          = 4/3 (3.142 ×12.167×10∧-24
                                           = 5.096 ×10∧-23 cm³
but 1m³= 1000000cm³
Therefore, the volume of the atom = 5.096 ×10∧-29 m³
8 0
2 years ago
which diagram best illustrates the ion-molecule attractions that occur when the ions of NaCl(s) are added to water
tatuchka [14]
Diagram is on the picture below.
Answer is: 1).
Sodium chloride is ionic compound and in the water dissociate in sodium cation (positive charge) and chloride anion (negative charge). Water is polar compound, oxagan has negative charge and hydrogen charge. Positive interact witn negative charge and negative with positive charge.

8 0
2 years ago
Consider the following reaction: CO2(g)+CCl4(g)⇌2COCl2(g) Calculate ΔG for this reaction at25 ∘C under these conditions: PCO2PCC
Salsk061 [2.6K]

<u>Answer:</u> The \Delta G for the reaction is 54.6 kJ/mol

<u>Explanation:</u>

For the given balanced chemical equation:

CO_2(g)+CCl_4(g)\rightleftharpoons 2COCl_2(g)

We are given:

\Delta G^o_f_{CO_2}=-394.4kJ/mol\\\Delta G^o_f_{CCl_4}=-62.3kJ/mol\\\Delta G^o_f_{COCl_2}=-204.9kJ/mol

  • To calculate \Delta G^o_{rxn} for the reaction, we use the equation:

\Delta G^o_{rxn}=\sum [n\times \Delta G_f(product)]-\sum [n\times \Delta G_f(reactant)]

For the given equation:

\Delta G^o_{rxn}=[(2\times \Delta G^o_f_{(COCl_2)})]-[(1\times \Delta G^o_f_{(CO_2)})+(1\times \Delta G^o_f_{(CCl_4)})]

Putting values in above equation, we get:

\Delta G^o_{rxn}=[(2\times (-204.9))-((1\times (-394.4))+(1\times (-62.3)))]\\\Delta G^o_{rxn}=46.9kJ=46900J

Conversion factor used = 1 kJ = 1000 J

  • The expression of K_p for the given reaction:

K_p=\frac{(p_{COCl_2})^2}{p_{CO_2}\times p_{CCl_4}}

We are given:

p_{COCl_2}=0.760atm\\p_{CO_2}=0.140atm\\p_{CCl_4}=0.180atm

Putting values in above equation, we get:

K_p=\frac{(0.760)^2}{0.140\times 0.180}\\\\K_p=22.92

  • To calculate the Gibbs free energy of the reaction, we use the equation:

\Delta G=\Delta G^o+RT\ln K_p

where,

\Delta G = Gibbs' free energy of the reaction = ?

\Delta G^o = Standard gibbs' free energy change of the reaction = 46900 J

R = Gas constant = 8.314J/K mol

T = Temperature = 25^oC=[25+273]K=298K

K_p = equilibrium constant in terms of partial pressure = 22.92

Putting values in above equation, we get:

\Delta G=46900J+(8.314J/K.mol\times 298K\times \ln(22.92))\\\\\Delta G=54659.78J/mol=54.6kJ/mol

Hence, the \Delta G for the reaction is 54.6 kJ/mol

7 0
2 years ago
A sample of 0.300 mg pure chromium was added to excess hydrochloric acid to form a 10.0 mL aqueous solution of a chromium (III)
DerKrebs [107]

extinction coefficient (ε) = 347 L·mol⁻¹·cm⁻¹

Explanation:

The chemical reaction between chromium (Cr) and hydrochloric acid (HCl):

2 Cr + 6 HCl → 2 CrCl₃ + 3 H₂

number of moles = mass / molar weight

number of moles of Cr = 0.3 × 10⁻³ (g) / 52 (g/mole)

number of moles of Cr = 5.77 × 10⁻⁶ moles

From the chemical reaction we see that 2 moles of Cr will produce 2 moles of CrCl₃ so 5.77 × 10⁻⁶ moles of Cr will produce 5.77 × 10⁻⁶ moles of CrCl₃.

molar concentration = number of moles / volume (L)

molar concentration of CrCl₃ = 5.77 × 10⁻⁶ / 10 × 10⁻³

molar concentration of CrCl₃ = 5.77 × 10⁻⁴ moles / L

Now we need to transform percent transmittance (%T) in absorbance (A) using the following formula:

A = 2 - log (%T)

A = 2 - log (62.5)

A = 2 - 1.8

A = 0.2

We know that absorbance (A) is defined in respect with extinction coefficient (ε), cell length (l) and concentration (c):

A = εlc

ε = A / lc

ε = 0.2 / (1 × 5.77 × 10⁻⁴)

ε = 0.0347 × 10⁴

ε = 347 L·mol⁻¹·cm⁻¹

Learn more about:

molar concentration

brainly.com/question/13971392

#learnwithBrainly

7 0
2 years ago
3. A mass of 0.15 ounces is equal to how many grams?
garik1379 [7]

Answer:

Option C = 4.25 g

Explanation:

Ounce and grams are unit of mass. Ounce is larger unit while gram is smaller unit. The one ounce is consist of 28.35 g or we can say that one ounce is equal to 28.35 g. In order to convert the given ounce value into grams the value is multiply with 28.35 g.

Given data:

Mass = 0.15 ounce

Mass in gram = ?

Solution:

One ounce is equal to 28.35 g, so

0.15 × 28.35 = 4.25 g

5 0
2 years ago
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