Answer:
QED, EDQ, DQE, EQD, DEQ, QDE
Explanation:
The structure of all possible peptides that contain the given amino acids are :
QED, EDQ, DQE, EQD, DEQ, QDE
where : Asp is represented by the letter code D
Glu is represented by the letter code E
Gln is represented by the letter code Q
Note : when three amino acids combine they form what is known as tripeptide ( i.e. contains two peptide linkages ) while a peptide linkage is been formed by the combination of a carboxyl group of an amino acid and the amino group of different amino acid
In the given experiment, the effect of different colors of light on photoelectric cell is determined. The photocell is placed in a circuit that clicks when current passes through it. For each color of light falling on the photocell the number of clicks is measured which gives an idea of the amount of current passing through the cell. Here the independent variable is the color of light. as to change the color of light coming from a common source, different color of cellophane is placed on the same flashlight. The dependent variable is the number of clicks per minute or the current passing through the cell.
Therefore the correct answer will be,
1.The color of the light after it has passed through the cellophane
Answer:
9.96*10^21
Explanation:
Molar mass of K2O=29*2+16
= 74g per mol
number of moles in the sample= 1.224/ 74
=0.1654
Number of particles in 1 mole=6.0221409*10^23
Number of particles= 0.01654*6.0221409*10^23
=9.96*10^21
The oxidizing agent is the one that is reduced in the reaction. In this reaction, the charge of Cu falls from +2 to zero charge (neutral atom in the right side). Hence, CuO is the oxidizing agent. The reducing agent, the one being oxidized is carbon from zero charge to +4. The answer is CuO.
Answer:
240.5g
Explanation:
steps:
given/ 1 - 2.5mol LiBr / 1
Multiplication - 78g/ 1 mol ( 78 comes from the formula weight of LiBr )
answer- 240.5g
