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Troyanec [42]
2 years ago
6

Which of the following describes the effect of boiling and freezing? which of the following describes the effect of boiling and

freezing? boiling and freezing both denatured amylase. boiling denatured the enzyme, but freezing had no effect. freezing denatured the enzyme, but boiling had no effect. boiling and freezing had no effect on amylase?
Chemistry
1 answer:
Natali5045456 [20]2 years ago
7 0

Boiling denatures the enzyme, but freezing has no effect.

At high temperatures (even if it’s not boiling, about 60°C is enough) hydrogen bonds and other interactions between different amino acids of an enzyme are broken. This is not degradation, no bonds are broken – only interactions (London, Van der Waals, etc). This makes the protein to denature, which means it will lose its 3D shape and become linear – no longer globular: it only preserves its primary structure. This makes the enzyme to become useless: it can’t make the substrate become product anymore. So the activity becomes practically zero.

Freezing DOES make a change in enzyme activity, but for other reasons which are not denaturing (the enzyme has the same structure as before):

-Concentration: Now some of the water has become ice and you have 2 phases, which are the solution and the ice. So the solution has less water, and so a higher concentration. Higher concentration means… higher activity! So it has the same structure, but it works more.

-Cell disruption: Membranes are broken and this will release molecules that used to be stored in an organelle. Sometimes this makes the enzyme find the substrate – so it actually increases activity! As I said for concentration, this means the enzyme has the same structure but it works more.


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How many moles of tungsten (W,183.85 g/lol are in 415 grams of tungsten?
vladimir1956 [14]

Given mass of tungsten, W = 415 g

Molar mass of tungsten, W = 183.85 g/mol

Calculating moles of tungsten from mass and molar mass:

415 g * \frac{1 mol}{183.85 g} = 2.26 mol W

7 0
2 years ago
Give four different chemical meanings for the word element and an example of each
Naddika [18.5K]

Answer ;

-An element is a substance containing only one type of atom, for example; H2 or 02  (consisting of atoms that all have the same number of protons).

-Microscopic, single atom of that element

-Macroscopic, sample of that element large enough to weigh on a balance

- A substance that cannot be broken down chemically; e.g; sodium metal,

Explanation;

-An element is a substance whose atoms all have the same number of protons: another way of saying this is that all of a particular element's atoms have the same atomic number. Elements are chemically the simplest substances and hence cannot be broken down using chemical reactions.

-An element is uniquely determined by the number of protons in the nuclei of its atoms.

3 0
2 years ago
Find the enthalpy of neutralization of HCl and NaOH. 87 cm3 of 1.6 mol dm-3 hydrochloric acid was neutralized by 87 cm3 of 1.6 m
Vesna [10]

Answer : The correct option is, (A) -101.37 KJ

Explanation :

First we have to calculate the moles of HCl and NaOH.

\text{Moles of HCl}=\text{Concentration of HCl}\times \text{Volume of solution}=1.6mole/L\times 0.087L=0.1392mole

\text{Moles of NaOH}=\text{Concentration of NaOH}\times \text{Volume of solution}=1.6mole/L\times 0.087L=0.1392mole

The balanced chemical reaction will be,

HCl+NaOH\rightarrow NaCl+H_2O

From the balanced reaction we conclude that,

As, 1 mole of HCl neutralizes by 1 mole of NaOH

So, 0.1392 mole of HCl neutralizes by 0.1392 mole of NaOH

Thus, the number of neutralized moles = 0.1392 mole

Now we have to calculate the mass of water.

As we know that the density of water is 1 g/ml. So, the mass of water will be:

The volume of water = 87ml+87ml=174ml

\text{Mass of water}=\text{Density of water}\times \text{Volume of water}=1g/ml\times 174ml=174g

Now we have to calculate the heat absorbed during the reaction.

q=m\times c\times (T_{final}-T_{initial})

where,

q = heat absorbed = ?

c = specific heat of water = 4.18J/g^oC

m = mass of water = 174 g

T_{final} = final temperature of water = 317.4 K

T_{initial} = initial temperature of metal = 298 K

Now put all the given values in the above formula, we get:

q=174g\times 4.18J/g^oC\times (317.4-298)K

q=14110.008J=14.11KJ

Thus, the heat released during the neutralization = -14.11 KJ

Now we have to calculate the enthalpy of neutralization.

\Delta H=\frac{q}{n}

where,

\Delta H = enthalpy of neutralization = ?

q = heat released = -14.11 KJ

n = number of moles used in neutralization = 0.1392 mole

\Delta H=\frac{-14.11KJ}{0.1392mole}=-101.37KJ/mole

Therefore, the enthalpy of neutralization is, -101.37 KJ

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<span>Grapefruit juice is approximately pH 3, andtomato juice is approximately pH 4. A glass of grapefruit juice contains _3_ H+ as a glass of tomato juice.</span><span>
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If you want us to explain it further please provide a picture.

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