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Troyanec [42]
1 year ago
6

Which of the following describes the effect of boiling and freezing? which of the following describes the effect of boiling and

freezing? boiling and freezing both denatured amylase. boiling denatured the enzyme, but freezing had no effect. freezing denatured the enzyme, but boiling had no effect. boiling and freezing had no effect on amylase?
Chemistry
1 answer:
Natali5045456 [20]1 year ago
7 0

Boiling denatures the enzyme, but freezing has no effect.

At high temperatures (even if it’s not boiling, about 60°C is enough) hydrogen bonds and other interactions between different amino acids of an enzyme are broken. This is not degradation, no bonds are broken – only interactions (London, Van der Waals, etc). This makes the protein to denature, which means it will lose its 3D shape and become linear – no longer globular: it only preserves its primary structure. This makes the enzyme to become useless: it can’t make the substrate become product anymore. So the activity becomes practically zero.

Freezing DOES make a change in enzyme activity, but for other reasons which are not denaturing (the enzyme has the same structure as before):

-Concentration: Now some of the water has become ice and you have 2 phases, which are the solution and the ice. So the solution has less water, and so a higher concentration. Higher concentration means… higher activity! So it has the same structure, but it works more.

-Cell disruption: Membranes are broken and this will release molecules that used to be stored in an organelle. Sometimes this makes the enzyme find the substrate – so it actually increases activity! As I said for concentration, this means the enzyme has the same structure but it works more.


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After a certain pesticide compound is applied to crops, its decomposition is a first-order reaction with a half-life of 56 days.
Anna35 [415]

The rate constant, k, for the decomposition reaction :  k = 0.0124 / days

<h3>Further explanation</h3>

Given

The half-life of 56 days

Required

The rate constant, k

Solution

For first-order, rate law : ln[A]=−kt+ln[A]o

The half-life :  the time required to reduce to half of its initial value.

The half life :

t1/2 = (ln 2) / k

k = (ln 2) / t1/2

k = 0.693 / 56 days

k = 0.0124 / days

8 0
2 years ago
A compound of barium and oxygen was dissolved in hydrochloric acid to give a solution of barium ion, which was then precipitated
n200080 [17]

Answer:

The empiricial formula of the compound is BaO2

Explanation:

<u>Step 1:</u> Data given

Barium and oxygen dissolved in hydrochloric acid gives a solution of barium ion. This was precipitated with an excess of potassium chromate and gives barium chromate.

The original compound weighs 1.345g and gives 2.012g of BaCrO4

<u>Step 2: </u>Calculate moles of BaCrO4

moles of BaCrO4 = mass of BaCrO4 / molar mass of BaCrO4

moles of BaCrO4 = 2.012g / 253.37 g/mol = 0.0079 moles

<u>Step 3</u>: Calculate moles of Ba

Mole ratio for Ba and BaCrO4 is 1:1 so this means for 0.0079 moles of BaCrO4, there are 0.0079 moles of Ba-ion

<u>Step 4:</u> Calculate mass of Ba-ion

Mass of Ba = Moles of Ba / Molar mass of Ba

Mass of Ba = 0.0079 moles * 137.327g/mole = 1.085 g Ba

<u>Step 5:</u> Mass of oxygen

Since the original compound has barium and oxygen, the mass of oxygen is the difference between the original mass and the mass of the Ba-ion

1.345 g - (1.085 g Ba) = 0.260 g O

<u>Step 6:</u> Calculate moles of Oxygen

moles oxygen = mass of oxygen / Molar mass of oxygen

moles oxygen = 0.260g / 16g/mole = 0.01625 moles O

We divide the number of moles by the smallest number of moles which is 0.0079

Ba → 0.0079/0.0079 = 1

O → 0.01625 / 0.0079 ≈ 2

(1.091 g Ba) / (137.3277 g Ba/mol) = 0.00794450 mol Ba

(0.254 g O) / (15.99943 g O/mol) = 0.0158756 mol O

This gives us the empirical formula of BaO2 for this compound

7 0
2 years ago
How many kilograms are in 4 moles of Na2CO3?
castortr0y [4]
First you need to find the amount of mass of Na2CO3 in one moles
(Use periodic chart)

Na= 22.99 x 2 = 45.98
C = 12.01
O = 16.00 x 4 = 64.00

Add the molar masses together to get 121.99

To find how many grams are in 4 moles, times 121.99 by 4
This gives you 487.96

But the questions asks for the answer to be in kilograms nor grams, to change into kilograms divide by 1000
This gets you the answer: 0.49 kg

6 0
2 years ago
Why are salt and sugar both able to dissolve in water, even though the solutes have different types of chemical bonding?
Rama09 [41]

Answer:

ions are surrounded by hydrogen ends with positive partial charge. In this way the salt is dissolved in water. Sugar is a molecular compound formed by covalent bonds. In a polar covalent bond, electrons are shared unevenly

Explanation:

5 0
2 years ago
Missy Mae is given an unknown white ionic solid which contains one of the cations Na+, K+, Ca2+ and one of the anions Cl-, NO3-
topjm [15]

Answer:

NaNO₃

KNO₃

Ca(NO₃)₂

Explanation:

The possible cations for the salt. = Na⁺ , K⁺ , Ca²⁺

The anion for which the formula has to written = NO₃⁻

The salt is of white color.

The possible salts may be:

<u>NaNO₃ </u>

<u>KNO₃</u>

<u>Ca(NO₃)₂</u>

Missy Mae can have one of these salts.

The color of NaNO₃ is from transparent to white.

The color of KNO₃ is white.

The color of NaNO₃ is from white to light grey.

7 0
2 years ago
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