Why did the use of steam during the industrial revolution lead to an interest in understanding the atom?

Which statement is correct? Salts are formed by the reaction of bases with water. Most salts are ionic and are soluble in water.

Studentka2010 [4]

Salts are formed by the reaction of bases with water. - FALSE
Most salts are ionic and are soluble in water. - TRUE
Most salts are insoluble in water and lack electrical charges. - FALSE
Solutions of salt and water do not conduct electricity. - FALSE

:)

3 0

2 years ago

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Why do the deprotonated organic acid (RCO2-) and protonated organic base (RNH3+) go into the aqueous layer?

rodikova [14]

Answer:

The deprotonated organic acid (RCO2-) and protonated organic base (RNH3+) go into the aqueous layer because Organic compounds that are neither acids or bases do not react with either NaOH or HCl and, therefore remain more soluble in the organic solvent and are not extracted.

Explanation:

4 0

2 years ago

Two students are given different samples of a substance and are instructed to determine the properties of the substance. Which s

olga_2 [115]

Mass because it is an extensive property

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2 years ago

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What is the theoretical yield of aluminum that can be produced by the reaction of 60.0 g of aluminum oxide with 30.0 g of carbon

Ulleksa [173]

Answer:

Theoretical yield = 31.8 g

Explanation:

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

For $Al_2O_3$

Mass of $Al_2O_3$ = 60.0 g

Molar mass of $Al_2O_3$ = 101.96128 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles= \frac{60.0\ g}{101.96128\ g/mol}$

$Moles_{Al_2O_3}= 0.5885\ mol$

Given: For $C$

Given mass = 30.0 g

Molar mass of $C$ = 12.0107 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles= \frac{30.0\ g}{12.0107\ g/mol}$

$Moles_{C}= 2.4978\ mol$

According to the given reaction:

$Al_2O_3+3C\rightarrow 2Al+3CO$

1 mole of aluminium oxide react with 3 moles of carbon

0.5885 mole of aluminium oxide react with $3\times 0.5885$ moles of carbon

Moles of carbon = 1.7655 moles

Available moles of carbon = 2.4978 moles

Limiting reagent is the one which is present in small amount. Thus, aluminium oxide is limiting reagent.

The formation of the product is governed by the limiting reagent. So,

1 mole of aluminium oxide on reaction forms 2 moles of aluminium.

0.5885 mole of aluminium oxide on reaction forms $2\times 0.5885$ moles of aluminium.

Moles of aluminium = 1.177 moles

Molar mass of aluminium = 26.981539 g/mol

Mass of sodium sulfate = Moles × Molar mass = 1.177 × 26.981539 g = 31.8 g

Theoretical yield = 31.8 g

3 0

2 years ago

Question14 of 20If 5.15 g FeCl3 is dissolved in enough water to make exactly 150.0 mL of solution, what is the molar concentrati

Serhud [2]

Answer: 0.635 M

Explanation:

Molarity : It is defined as the number of moles of solute present per liter of the solution.

Formula used :

$Molarity=\frac{n\times 1000}{V_s}$

where,

n= Moles= $\frac{\text{Given mass}}{\text{Molar mass}}=\frac{5.15g}{162.4g/mol}=0.0317moles$

$V_s$ = volume of solution = 150 ml

$Molarity=\frac{0.0317\times 1000}{150ml}=0.2114M$

$FeCl_3\rightarrow Fe^{3+}+3Cl^-$

as 1 mole of $FeCl_3$ gives 3 moles of $Cl^-$ ions

Thus molarity of $Cl^-$ = $3\times 0.2114=0.635M$

Molarity of $Cl^-$ = 0.635 M

8 0

2 years ago