Answer:
2
Explanation:
Data:
[H⁺] = 0.01 mol·L⁻¹
Calculation:
pH = -log[H₃O⁺] = -log(0.01) = -log(1) - log(10⁻²) = -0 - (-2) = 0 + 2 = 2
Formal charge = valence electron - bonds - dots.
double bonded oxygen = 6-2-
4 so it is 0
single bonded oxygen = 6-1-6 so it is -1
sulfur = 6-3-2 so it is +1
Vanillin is the common name for 4-hydroxy-3-methoxy-benzaldehyde.
See attached figure for the structure.
Vanillin have 3 functional groups:
1) aldehyde group: R-HC=O, in which the carbon is double bonded to oxygen
2) phenolic hydroxide group: R-OH, were the hydroxyl group is bounded to a carbon from the benzene ring
3) ether group: R-O-R, were hydrogen is bounded through sigma bonds to carbons
Now for the hybridization we have:
The carbon atoms involved in the benzene ring and the red carbon atom (from the aldehyde group) have a <u>sp²</u> hybridization because they are involved in double bonds.
The carbon atom from the methoxy group (R-O-CH₃) and the blue oxygen's have a <u>sp³</u> hybridization because they are involved only in single bonds.
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Explanation:
I just did this question and that’s what was right.
Answer : The exit temperature of the product is, 
Explanation :
Total heat = Heat lost by liquid + Latent heat of fusion + Heat lost by frozen

where,
Q = Total heat = 6000 kJ
m = mass of product = 15 kg
= specific heat of liquid = 
= latent heat of fusion = 
= specific heat of frozen = 
= initial temperature of liquid = 
= final temperature of liquid = 
= initial temperature of frozen = ?
= final temperature of frozen = 
Now put all the given value in the above expression, we get:
![6000kJ=[15kg\times 4kJ/kg^oC\times (10-2)^oC]+[15kg\times 275kJ/kg]+[15kg\times 2.5kJ/kg^oC\times (2-T_3)^oC]](https://tex.z-dn.net/?f=6000kJ%3D%5B15kg%5Ctimes%204kJ%2Fkg%5EoC%5Ctimes%20%2810-2%29%5EoC%5D%2B%5B15kg%5Ctimes%20275kJ%2Fkg%5D%2B%5B15kg%5Ctimes%202.5kJ%2Fkg%5EoC%5Ctimes%20%282-T_3%29%5EoC%5D)

Thus, the exit temperature of the product is, 