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artcher [175]
2 years ago
13

How many significant figures the measurement have 56.0g 0.0004m 1003ml 0.0350s

Chemistry
1 answer:
Setler [38]2 years ago
7 0
In order to do this, we have to first know the significant figure rules.
<span>Rule #1: All non-zero digits are significant. (1234)
 Rule #2: Zeros in front of a number are not significant. (0.093)
 Rule #3: Zeros between non-zero digits are significant. (78309)
 Rule #4: Zeros at the end of a number are significant if there is a decimal point in the number. (0.05470)

So by going by the rules, 56.0g has three sig figs, because there is a decimal point.
0.0004m only has one sig fig, according to Rule #2.
1003ml has 4 sig figs, because the zeroes are wedged in the two sig fig numbers.
And lastly, 0.0350s has 3 sig figs because the number after a decimal point counts.

</span>
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Answer:

2

Explanation:

Data:

[H⁺] = 0.01 mol·L⁻¹

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2 years ago
Draw a lewis structure for so2 in which all atoms obey the octet rule. show formal charges. do not consider ringed structures.
Aleonysh [2.5K]
Formal charge = valence electron - bonds - dots.
double bonded oxygen = 6-2-
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Functional group and bond hybridization of vanillin
lana66690 [7]

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See attached figure for the structure.

Vanillin have 3 functional groups:

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3) ether group: R-O-R, were hydrogen is bounded through sigma bonds to carbons

Now for the hybridization we have:

The carbon atoms involved in the benzene ring and the red carbon atom (from the aldehyde group) have a <u>sp²</u> hybridization because they are involved in double bonds.

The carbon atom from the methoxy group (R-O-CH₃) and the blue oxygen's have a  <u>sp³</u>  hybridization because they are involved only in single bonds.

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2 years ago
Chandra forms her question: "What is the effect of soda on plant growth?" What would be a good hypothesis for this question?
ratelena [41]

Soda provides nutritional value that helps plants grow.

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I just did this question and that’s what was right.

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A food product is being frozen in a system capable of removing 6000 kJ of thermal energy. The product has a specifi c heat of 4
lapo4ka [179]

Answer : The exit temperature of the product is, -35.2^oC

Explanation :

Total heat = Heat lost by liquid + Latent heat of fusion + Heat lost by frozen

Q=m\times c_1\times (T_2-T_1)+m\times L_f+m\times c_2\times (T_4-T_3)

where,

Q =  Total heat = 6000 kJ

m = mass of product = 15 kg

c_1 = specific heat of liquid = 4kJ/kg^oC

L_f = latent heat of fusion = 275kJ/kg

c_2 = specific heat of frozen = 2.5kJ/kg^oC

T_1 = initial temperature of liquid = 2^oC

T_2 = final temperature of liquid = 10^oC

T_3 = initial temperature of frozen = ?

T_4 = final temperature of frozen = 2^oC

Now put all the given value in the above expression, we get:

6000kJ=[15kg\times 4kJ/kg^oC\times (10-2)^oC]+[15kg\times 275kJ/kg]+[15kg\times 2.5kJ/kg^oC\times (2-T_3)^oC]

T_3=-35.2^oC

Thus, the exit temperature of the product is, -35.2^oC

7 0
2 years ago
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