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e-lub [12.9K]
1 year ago
7

Both hydrogen sulfide (H2S) and ammonia (NH3)

Chemistry
2 answers:
sveticcg [70]1 year ago
6 0

Answer:

The molar mass of H2S is greater than the molar mass of NH3, making the velocity and effusion rate of NH3 particles faster. Effusion rate is inversely proportional to molar mass. NH3 will have a higher average molecule velocity, so it will diffuse faster and will reach the other side of the room more quickly.

Explanation:

faust18 [17]1 year ago
4 0

Answer: The molar mass of H2S is greater than the molar mass of NH3, making the velocity and effusion rate of NH3 particles faster.

Effusion rate is inversely proportional to molar mass.

NH3 will have a higher average molecule velocity, so it will diffuse faster and will reach the other side of the room more quickly.

Explanation: change up your response a bit

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Answer:

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2 years ago
What is the density of 2.5 g of gaseous sulfur held at 130. kPa and 10.0 degrees Celsius?
worty [1.4K]
Use ideal gas equation: pV = nRT

Now pass n to mass: n = mass / MM .... [MM is the  molar mass]

pV = [mass/MM]*RT =>mass/V = [p*MM] / RT  and mass / V = density

p= 130 kPa = 130,000 Pa = 130,00 joule / m^3
T = 10.0 ° + 273.15 = 283.15 k
MM of sulfur (S) = 32 g/mol  = 32000 kg/mol

density = 130,000 Pa * 32000kg/mol / [8.31 joule / mol*k * 283.15 k] = 1.77*10^6 kg/m^3 = 1.77 g/L  ≈ 1.8 g/L

Then, I do not get any of the option choices.

Is it possbile that the pressure is 13.0 kPa instead 130. kPa? If so the answer would be 18 g/L

Note that the mass is not used. You do not need it unless you are asked for the volume, which is not the case.



 
4 0
2 years ago
Read 2 more answers
According to the law of conservation of mass, if an element A has an atomic mass of 2 mass units and element B has an atomic mas
LenaWriter [7]
The law of conservation of mass states that mass is neither created nor destroyed. Since we have 2 g/mol of A and 3 g/mol of B then AB should be equal to the sum of their molar mass that is 

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for the case of A2B3

A2 = 2 * 2 = 4 g/mol
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5 0
2 years ago
If the pH of a phosphoric acid (H3PO4) solution is adjusted to 6.50, what is the most abundant species and which is the second m
maria [59]

Explanation:

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As,        pK_{a} = -log K_{a}

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Now, at pH 6.50

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At pH = 2.15;  H_{3}PO_{4} = H_{2}PO^{-}_{4}

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At pH 7.20;  H_{2}PO^{-}_{4} = HPO^{2-}_{4}

        HPO^{2-}_{4} \rightarrow PO^{3-}_{4} + H^{+};     K_{a3}

Hence, we can conclude that most abundant species is H_{2}PO^{-}_{4} and the second most abundant species is HPO^{2-}_{4}.

3 0
2 years ago
Name the type of reaction and give the coefficients needed to balance the following skeleton reaction: ___Mg + ___Fe2O3 → ___Fe
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the answer is c a tries to trick people by using the same numbers


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