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mihalych1998 [28]
2 years ago
6

In an experiment, 0.42 mol of co and 0.42 mol of h2 were placed in a 1.00-l reaction vessel. at equilibrium, there were 0.29 mol

of co remaining. keq at the temperature of the experiment is __________.
Chemistry
1 answer:
Likurg_2 [28]2 years ago
4 0
To determine the Keq, we need the chemical reaction in the system. In this case it would be:

CO + 2H2 = CH3OH

The Keq is the ration of the amount of the product and the reactant. We use the ICE table for this. We do as follows:

          CO           H2             CH3OH
I         .42           .42                    0
C     -0.13      -2(0.13)            0.13
-----------------------------------------------
E =    .29           0.16               0.13

Therefore, 

Keq = [CH3OH] / [CO2] [H2]^2 = 0.13 / 0.29 (0.16^2)
Keq = 17.51
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b) If 35 grams of copper (II) chloride react with 20 grams of sodium nitrate, how much sodium chloride can be formed? what is th
charle [14.2K]

Answer:

CuCl₂ is the excessive reactant and NaNO₃ the limiting reactant, 13.7g of NaCl can be formed.

Explanation:

Based on the reaction:

CuCl₂ + 2NaNO₃ → 2NaCl + Cu(NO₃)₂

To solve the problem we must convert the mass of each reactant in order to find limiting reactant as follows:

<em>Moles CuCl₂ -Molar mass: 134.45g/mol-:</em>

35g * (1mol / 134.45g) = 0.26 moles

<em>Moles NaNO₃ -Molar mass: 84.99g/mol-:</em>

20g * (1mol / 84.99g) = 0.235 moles

For a complete reaction of 0.235 moles of NaNO₃ there are required:

0.235 moles NaNO₃ * (1 mol CuCl₂ / 2 mol NaNO₃) = 0.118 moles CuCl₂

As there are 0.26 moles CuCl₂,

<h3>CuCl₂ is the excessive reactant and NaNO₃ the limiting reactant</h3><h3 />

As 2 moles of NaNO₃ produce 2 moles of NaCl, he moles of NaCl produced are: 0.235 moles NaCl. The mass is:

<em>Mass NaCl -Molar mass: 58.44g/mol-:</em>

0.235 moles NaCl * (58.44g / mol) =

<h3>13.7g of NaCl can be formed</h3>
7 0
2 years ago
The molar mass of oxygen gas (O2) is 32.00 g/mol. The molar mass of C3H8 is 44.1 g/mol. What mass of O2, in grams, is required t
Ira Lisetskai [31]
The reaction formula of this is C3H8 + 5O2 --> 3CO2 + 4H2O. The ratio of mole number of C3H8 and O2 is 1:5. 0.025g equals to 0.025/44.1=0.00057 mole. So the mass of O2 is 0.00057*5*32=0.0912 g.
6 0
2 years ago
If 1.0 mole of CH4 and 2.0 moles of Cl2 are used in the reaction CH4 + 4Cl2 =&gt; CCl4 + 4HCl then which of these statements is
nikklg [1K]

Answer:

B,C,D

Explanation:

The yield of CCl4 depends on the amount of CH4 in a 1:1 ratio. The amount of Cl2 is twice that of CH4 hence some must be left over. To ensure that all the Cl2 is used up, more CH4 must added to the system.

4 0
2 years ago
f 23.6 mL of 0.200 M NaOH is required to neutralize 10.00 mL of a H3PO4 solution , what is the concentration of the phosphoric a
Eduardwww [97]

Answer:

Explanation:

H3PO4(aq) + 3NaOH(aq) → Na3PO4(aq) + 3H2O(l)

mole of NaOH = 23.6 * 10 ⁻³L * 0.2M

= 0.00472mole

let x be the no of mole of H3PO4 required of  0.00472mole of NaOH

3 mole of NaOH required ------- 1 mole of H3PO4

0.00472mole of NaOH ----------x

cross multiply

3x = 0.0472

x = 0.00157mole

[H3PO4] = mole of H3PO4 / Vol. of H3PO4

= 0.00157mole / (10*10⁻³l)

= 0.157M

<h3>The concentration of unknown phosphoric acid is  0.157M</h3>
7 0
1 year ago
Read 2 more answers
Gold has always been a highly prized metal, and it has been widely used from the beginning of history as a store of value. It do
Greeley [361]

Answer: The balanced equation is

Au(s) + 3HNO3(aq) + 4HCl(aq) ---> HAuCl4(aq) + 3NO2(g) +3H2O(l)

The function of HCl in a solution of Aqua regia, that is used to dissolve gold is to dissolve other metals like quartz or iron stone that surround the gold.

Explanation: To balance the equation, we check the ratio of each element in the reacting side and the product side ( left and right hand side). Let their ratio be equal be adding moles to the compound of the element or the element it's self in either side of the equation.

HCl which is called hydrochloric acid, is an acid that does not react with gold, but it react with every other substance, like your skin, metals etc. it is used to clean a gold, by dipping the gold inside it, all the metals on the surface of the gold will dissolve.

When dissolving a gold in aqua regia solution, HCL is added to prepare this solution because it will help to dissolve all other substance on the surface of the gold.

8 0
1 year ago
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