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mihalych1998 [28]
2 years ago
6

In an experiment, 0.42 mol of co and 0.42 mol of h2 were placed in a 1.00-l reaction vessel. at equilibrium, there were 0.29 mol

of co remaining. keq at the temperature of the experiment is __________.
Chemistry
1 answer:
Likurg_2 [28]2 years ago
4 0
To determine the Keq, we need the chemical reaction in the system. In this case it would be:

CO + 2H2 = CH3OH

The Keq is the ration of the amount of the product and the reactant. We use the ICE table for this. We do as follows:

          CO           H2             CH3OH
I         .42           .42                    0
C     -0.13      -2(0.13)            0.13
-----------------------------------------------
E =    .29           0.16               0.13

Therefore, 

Keq = [CH3OH] / [CO2] [H2]^2 = 0.13 / 0.29 (0.16^2)
Keq = 17.51
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Two species, A and B, are separated on a 2.00 m long column which has 5.000 x 103 plates when the flow rate is 15.0 mL/min. A sp
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Explanation:

The given data is as follows.

         t_{m} = 30.0 sec,     t_{r1} = 5 min = 5 \times 60 sec = 300 sec

         t_{r2} = 12.0 min = 12 \times 60 sec = 720 sec

Formula for adjusted retention time is as follows.

      t'_{r} = t_{r} - t_{m}

                 = 300 sec - 30.0 sec

                 = 270 sec

   t'_{r2} = 720 sec - 30 sec

                            = 690 sec

Formula for relative retention (\alpha) is as follows.

          \alpha = \frac{t'_{r2}}{t'_{r1}}

                     = \frac{690 sec}{270 sec}

                     = 2.56

Thus, we can conclude that the relative retention is 2.56.

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2 years ago
Jose wants to know the effects of mass, force, and surface type on the motion of a small box. He has one spring, one box, and an
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Answer:

He changed more than one variable at a time

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6 0
2 years ago
Complete combustion of a compound containing hydrogen and carbon produced 2.641 g of carbon dioxide and 1.442 grams of water as
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  The empirical   formula  of hydrocarbon is C₃H₈

The  molecular formula of hydrocarbon   is C₆H₁₆


<u><em> Empirical  formula  calculation</em></u>

Hydrocarbon  contain  carbon and hydrogen

  Step 1:  find the  mass  carbon (C) in carbon dioxide (CO₂)  and hydrogen (H )  in water

mass of  of element = molar mass  of element/ molar mass molecule x total mass of    molecule

From periodic table the molar mass  of C =12,    for CO₂ = 12+( 16 x2) =44 g/mol,     for H = 1.00 g/mol,    for H₂O = (2 x1)+16 = 18 g/mol

mass of C = 12/44 x 2.641 =0.7203 g

since there are 2 atom  of H in H₂O the molar mass of H = 1 x2 = 2 g/mol

mass of H  is therefore =  2/18 x 1.442 =0.1602 g


Step 2:  find the moles of C and H

moles = mass÷ molar mass

moles of C = 0.7203 g÷ 12 g/mol = 0.060  moles

moles of H  =  0.1602÷ 1 g/mol = 0.1602 moles


Step 3: find the mole ratio  of C and H by dividing  each  mole by smallest mole ( 0.06)

for C = 0.06/0.06 =1

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multiply   by 3  to remove the decimal

For C = 1 x3 =3

For H = 2.67 x3 =8

therefore the empirical formula = C₃H₈


<u><em>The molecular formula calculation</em></u>

[C₃H₈]n  = 88.1 g/mol

[12 x 3)+( 1 x8)]n =88.1 g/mol

44 n = 88.1

divide both side by 44

n=2

therefore [C₃H₈]₂   = C₆H₁₆



7 0
1 year ago
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An archaeologist discovers an ancient wooden bowl. which isotope would most likely be used to determine its age?
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Answer:

c

Explanation:

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2 years ago
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For each pair below, select the sample that contains the largest number of moles. Pair A 2.50 g O2 2.50 g N2
raketka [301]

Answer:

Explanation:

Pair  2.50g of O₂ and 2.50g of  N₂

The atoms sample with the largest number of moles since the masses are the same would be the one with lowest molar mass according the the equation below:

Number of moles = \frac{mass }{molarmass}

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Molar mass of N₂ = 14 x 2 = 28gmol⁻¹

Number of moles of O₂ = \frac{2.5}{32} = 0.078mole

Number of moles of N₂ = \frac{2.5}{28} =  0.089mole

We see that N₂ has the largest number of moles

4 0
2 years ago
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