The easy part about this question is that it already gives you the equation to use. If you're trying to find the weight in g/cm^3, all you have to do is divide the weight in grams (g) by the volume in cubic centimeters (cm^3).
The problem already gives you the volume, so you just need to convert kilograms (kg) into grams (g).
Hint: "kilogram" means 1000 grams. There are 1,000 grams in each kilogram.
So find the weight of the object in grams, then divide that number by the volume in cm^3.
Answer : The enthalpy change for converting 1 mole of ice at
to water at
is, 7.712 KJ
Solution :
Process involved in the calculation of enthalpy change :

Now we have to calculate the enthalpy change.
![\Delta H=[m\times c_{ice}\times (T_2-T_1)]+\Delta H_{fusion}+[m\times c_{water}\times (T_3-T_2)]](https://tex.z-dn.net/?f=%5CDelta%20H%3D%5Bm%5Ctimes%20c_%7Bice%7D%5Ctimes%20%28T_2-T_1%29%5D%2B%5CDelta%20H_%7Bfusion%7D%2B%5Bm%5Ctimes%20c_%7Bwater%7D%5Ctimes%20%28T_3-T_2%29%5D)
where,
= enthalpy change
m = mass of water = 
= specific heat of ice = 2.09 J/gk
= specific heat of water = 4.18 J/gk
= enthalpy change for fusion = 6.01 KJ/mole = 0.00601 J/mole
conversion : 
= initial temperature of ice = 
= final temperature of ice = 
= initial temperature of water = 
= final temperature of water = 
Now put all the given values in the above expression, we get
![\Delta H=[18g\times 2.09J/gK\times (273-248)k]+0.00601J+[18g\times 4.18J/gK\times (363-273)k]](https://tex.z-dn.net/?f=%5CDelta%20H%3D%5B18g%5Ctimes%202.09J%2FgK%5Ctimes%20%28273-248%29k%5D%2B0.00601J%2B%5B18g%5Ctimes%204.18J%2FgK%5Ctimes%20%28363-273%29k%5D)
(1 KJ = 1000 J)
Therefore, the enthalpy change for converting 1 mole of ice at
to water at
is, 7.712 KJ
It is known that at if a gas is identified to be as ideal
gas then, at STP, the volume of 1 mole of that gas is equal to 22.4 L. Using
this fact and the given volume in this item, we determine the number of moles
as that below.
n =
(11.2 L of argon)(1 mol argon / 22.4 L of argon)
<span> n =
0.5 moles</span>
<span>Answer: 0.5 moles </span>
114.3%
Explanation:
Given parameters:
True amount of solid = 1.4g
Measured amount = 3.0g
Unknown:
Percentage error = ?
Solution:
The inaccuracy in the reading is termed uncertainty.
This is the error.
Error = true value - measured value.
The values of errors are absolute.
Percentage error = 
Percentage error =
x 100 = 114.3%
This is large amount of error
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