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2 years ago

Identify the precipitate (if any) that forms when KOH and Cu(NO3)2 are mixed

1 answer:

3 0

When KOH and Cu(NO3)2 are mixed it yields copper(II) hydroxide and potassium nitrate. The balanced reaction is:

Cu(No3)2(aq) + 2 KOH(aq) = Cu(OH)2(s) + 2 KNo3(aq)

As we can see from the equation a solid is formed therefore a precipitate is formed which is the copper (II) hydroxide which has a blue to purple appearance. This can be observed since copper (II) hydroxide has a low solubility in aqueous solution.

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Watch the video to determine which of the following relationships are correct according to Boyle’s law.

scoray [572]

Answer:

Part A

Boyle's Law is given mathematically as

P ∝(1/V) or V ∝(1/P)

Options 4 and 5, if they are properly written.

Part B

At constant temperature, and according to the Boyle's law for an ideal gas,

A. What can cause a Volume increase is a corresponding decrease in pressure.

B. What can cause a Volume decrease is a corresponding increase in pressure.

C. The Volume is unchanged if the pressure of the gas is unchanged too.

Part C

The pressure when the gas occupies a volume of 5.0 L = 40 atm

Part D

The pressure when the gas occupies a volume of 4.5 L = 36 atm

Explanation:

Part A

Boyle's Law states that at constant temperature, the pressure of an ideal gas is inversely proportional to the volume occupied by the gas.

So, mathematically, Boyle's Law is given as

P ∝(1/V) or V ∝(1/P)

Part B

Inverse relationship between two quantities means that the higher the value of one of the quantities go, the lower the value of the other quantity goes and vice versa.

So, at constant temperature, and according to the Boyle's law for an ideal gas.

A. What can cause a Volume increase is a corresponding decrease in pressure.

B. What can cause a Volume decrease is a corresponding increase in pressure.

C. The Volume is unchanged if the pressure of the gas is unchanged too.

Part C

A certain gas occupies a volume of 20 L when the applied pressure is 10 atm, find the pressure when the gas occupies a volume of 5.0 L.

According to Boyle's Law for an ideal gas,

P ∝(1/V)

P = (k/V)

where k is the constant of proportionality

PV = k

Therefore,

P₁V₁ = P₂V₂ = k

P₁ = 10 atm

V₁ = 20 L

P₂ = ?

V₂ = 5.0 L

10 × 20 = P₂ × 5

P₂ = 40 atm

Part D

If a certain gas occupies a volume of 18 L when the applied pressure is 9.0 atm , find the pressure when the gas occupies a volume of 4.5 L

P₁V₁ = P₂V₂ = k

P₁ = 9.0 atm

V₁ = 18 L

P₂ = ?

V₂ = 4.5 L

9 × 18 = P₂ × 4.5

P₂ = 36 atm

Hope this Helps!!!

3 0

1 year ago

15. Using the information below, calculate ΔHf° for PbO(s)

Svet_ta [14]

ΔH(reaction) = ΔH(formation of products) - ΔH(formation of reactants)
ΔH(reaction) = ( 1*ΔH(Pb(s)) + 1*ΔH(CO2(g)) ) - ( 1*ΔH(PbO(s)) + 1*ΔH(CO(g)) )
ΔH(reaction) = ( 0 + -393.5 ) - ( ΔH(PbO(s)) + -110.5 )
ΔH(reaction) = -283 - ΔH(PbO(s))
-131.4 = -283 -ΔH(PbO(s))
ΔH(PbO(s)) = -151.6 kJ

So, the best answer is A.

5 0

1 year ago

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In a coffee shop, the following coffee samples are prepared for customers. i. 10 g of sugar added to 100 g of coffee ii. 10 g of

dem82 [27]

So solve this we must know the amount of sugar per gram of coffee

i. 10 g sugar /100 g coffee = 0.1 g sugar/ 1 g coffee

ii. 10 g sugar / 200 g coffee = 0.05 g sugar / 1 g coffee

iii. 4 g sugar / 200 g coffee = 0.02 g sugar / 1 g coffee

iv. 4 g sugar / 100 g coffee = 0.04 g sugar / 1 g coffee

So the ranking from sweetest so the least is:

i, ii, iv, iii

4 0

1 year ago

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Calculate the number of grams of carbon dioxide produced from complete combustion of one liter of octane by placing the conversi

lesya [120]

Answer:

15.71g

Explanation:

The general combustion equation for all hydrocarbons is

CxHy + (x+y/4) O2 = xCO2 + (y/2) H2O

For octane, C8H18 :

C8H18 + ( 8 + 18/4 ) O2 = 8CO2 + 9H2O

C8H18 + 50/4 O2 = 8CO2 + 9H2O

C8H18 + 25/2 O2 = 8CO2 + 9H2O

2C8H18 + 25 O2 = 16 CO2 + 18H2O (balanced)

From the balanced equation,

2 x 22.4 L of octane produced 16 [ 12 + (16 x 2)] of carbon dioxide

That is,

44.8 L of octane produced 704g of carbon dioxide

So, 1L of octane will produce 1 L x 704g/44.8 L = 15.71g of carbon dioxide

Therefore, 15.71g of carbon dioxide will be produced by the complete combustion of 1 L of octane.

7 0

2 years ago

In a conductivity apparatus, like the one above, you should never touch the ___ while the power is on. A Light Bulb B Leads C Wi

laila [671]

Answer:

Leads

Explanation:

5 0

2 years ago

Read 2 more answers