Answer:
By decreasing pressure.
Explanation:
In order to prevent balloons from popping while making sculptures, it is suggested to decrease the pressure of air in parent balloon. Decreasing the pressure of parent balloon will allow it to twist easily and make designs.
This strategy will work according to Boyle's Law which states that, "Pressure and Volume are inversely proportional to each other at constant temperature".
Mathematically,
P ∝ 1/V
Or,
P = k/V
Or,
PV = k
Hence, as the new designs made after twisting are of less volume, therefore it is good to decrease the pressure in advance otherwise the resulting less volume will increase the pressure of daughter small balloons and will explode them.
Answer:
1.73 atm
Explanation:
Given data:
Initial volume of helium = 5.00 L
Final volume of helium = 12.0 L
Final pressure = 0.720 atm
Initial pressure = ?
Solution:
"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"
Mathematical expression:
P₁V₁ = P₂V₂
P₁ = Initial pressure
V₁ = initial volume
P₂ = final pressure
V₂ = final volume
Now we will put the values in formula,
P₁V₁ = P₂V₂
P₁ × 5.00 L = 0.720 atm × 12.0 L
P₁ = 8.64 atm. L/5 L
P₁ = 1.73 atm
Following reactions are involved in present reaction
1) A<span>g+(aq) + Li(s) → Ag(s) + Li+(aq) </span><span>− 384.4kJ
2) </span><span>2Fe(s) + 2Na+(aq) → Fe2+(aq) + 2Na(s) + 392.3kJ
</span>3) <span>2K(s) + 2H2O(l) → 2KOH(aq) +H2(g) −393.1kJ
In above reaction, reaction 1 and 3 has negative value of </span>δh∘f, while reaction 2 has posiyive value of <span>δh∘f. As per the sign convention positive sign indicates that heat is given out during the reaction, while negative sign indicates heat is to be supplied for reaction to occur. In alternative words, product formed in reaction 2 is stable as compared to reactant. Hence, it is thermodynamically favorable. </span>
Answer:
CRYSTAL
MANY ATOMS THAT ARE ARRANGE IN A REGULAR PATTERN
1:1
Explanation:
Answer:
The answer to your question is: C₁₈ H₂₇ N O₃
Explanation:
Data
Carbon = 70.79 g
Hydrogen = 8.91 g
Nitrogen = 4.58 g
Oxygen = 15.72 g
Process
AT C = 12 g
AT H = 1 g
AT N = 14 g
AT O = 16 g
Carbon
12 g ------------------------ 1 mol
70.79 g ------------------------- x
x = (70.79 x 1) / 12
x = 5.9 mol of C
Hydrogen
1 g ----------------------- 1 mol
8.91 g --------------------- x
x = (8.91 x 1) / 1
x = 8.91 mol of H
Nitrogen
14 g ---------------------- 1 mol
4.58 g ------------------- x
x = (4.58 x 1) / 14
x = 0.33 mol
Oxygen
16 g ------------------------ 1 mol
15.72 g -------------------- x
x = (15.72 x 1)/16
x = 0.98
Divide by the lowest number of moles
Carbon 5.9 / 0.33 = 17.9 ≈ 18
Hydrogen 8.91 / 0.33 = 27
Nitrogen 0.33 / 0.33 = 1
Oxygen 0.98 / 0.33 = 2.9 ≈ 3
C₁₈ H₂₇ N O₃
