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tankabanditka [31]
2 years ago
14

If the coefficient 2 is placed in front of the product tetraiodine nonaoxide (I4O9), then, how many atoms of each element must b

e accounted for on the otherside of the equation?8 iodine atoms and 18 oxygen atoms
4 iodine atoms and 9 oxygen atoms
8 iodine atoms and 9 oxygen atoms
9 iodine atoms and 4 oxygen atoms
18 iodine atoms and 9 oxygen atoms
Chemistry
1 answer:
Svetlanka [38]2 years ago
3 0
The coefficient of any substance in a chemical equation indicates the number of moles of that substance which are present. We can see from its chemical formula that tetraiodine nonaoxide contains four iodine atoms and nine oxygen atoms. If the coefficient is two, then the total iodine atoms will be eight and  the total oxygen atoms will be 18. Because the law of conservation of mass holds, an equal amount must be accounted for on the other side of the chemical equation. Therefore, the first option is correct.
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Answer: The molar mass of H2S is greater than the molar mass of NH3, making the velocity and effusion rate of NH3 particles faster.

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4 0
2 years ago
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Three compounds containing potassium and oxygen are compared. Analysis shows that for each 1.00 g of O, the compounds have 1.22
kicyunya [14]
<span>The law of proportion states that elements combine in whole number ratios. The gram readings for K are multiples of each other, both in grams and moles.
Let us compare the ratios:
</span>2.44 grams/1.22 grams = 2
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4 0
2 years ago
Quinine, an antimalarial drug, is 8.63% nitrogen. There are two nitrogen atoms per molecule. What is the molecular weight of qui
Furkat [3]

Answer:

324.18 g/mol

Explanation:

Let the molecular mass of the antimalarial drug, Quinine is x g/mol

According to question,

Nitrogen present in the drug is 8.63% of x

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Also, according to the question,

2 atoms are present in 1 molecule of the drug.

Mass of nitrogen = 14.01 amu = 14.01 g/mol (grams for 1 mole)

So, mass of nitrogen = 14.01×2 = 28.02

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\frac {8.63}{100}\times x=28.02

solving for x, we get:

<u>x = 324.18 g/mol</u>

6 0
2 years ago
iron combines with 4.00 g of copper (11) nitrate to form 6.01 g of Iron (l) nitrate and 0.400 g copper metal. how much iron did
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7 0
2 years ago
Compute the end-to-end separation (direct distance between molecule ends), in Angstroms, of a coiled PVC molecule with a number-
MArishka [77]

Answer:

5156  Â

Explanation:

Chains of monomers that are being linked together constitute what is called polymers. in this question; we are to compute the end to end separation (direct distance between molecule ends), in Angstroms, of a coiled PVC molecule.

Using the following approach:

The first step is to determine the repeating units in polymer

The number of repeating unit = average molecular weight/  atomic weight of PVC

Given that:

average molecular weight = 256,131 g/mol

atomic weight of PVC = 62.498 g

Then;

The number of repeating unit = 256,131 g/mol /  62.498 g = 4098.227143 mol

Now the distance is calculated by using the formula:

d = (C-C) × sin 109.5/2

C-C bond length = 1.54 angstroms

tetrahedral bond angle = 109.5°

Then d = (1.54)  × sin 109.5/2

d = 1.258

Thus ; the end to end separation  is :

4098.227143  × 1.258 = 5155.57 Â

The answer is 5156  Â (since no decimal should be included )

6 0
2 years ago
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