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vekshin1
2 years ago
14

Does the result of the calculation in question 3 justify your original assumption that all of the SCN^- is in the form of FeNCS^

2+
Chemistry
1 answer:
Naddik [55]2 years ago
5 0
Fe 3+ + SCN- --> FeSCN 2+ 

<span>.......Fe 3+ .......SCN-.........FeSCN 2+ </span>
<span>I.......0.04..........0.001.............. </span>
<span>C........-x...............-x............. </span>
<span>E.....0.04-x.....0.001-x...........x </span>

<span>Keq = 203.4 = x / (0.04-x)(0.001-x) </span>
<span>203.4 = x / (x^2 - 0.041x + 4x10^-5) </span>
<span>203.4x^2 - 8.34x + 0.00094 = x </span>
<span>203.4x^2 - 9.34x + 0.00094 = 0 </span>
<span>x = -0.0001M or 0.0458M </span>
<span>so, using your Keq, there would be no SCN- or Fe 3+ left.....all would be in the form of FeSCN 2+</span>
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Jane and Jack have a bicycling competition Jane rides a constant speed of 12 miles per hour while Jack rides at a constant speed
MariettaO [177]

Answer:

Explanation:

I don't know how you want the conversion done. I use dimensional analysis.

Jane

12 miles / hour [1.6 km/1 mile][1000 m/1 km][1 hour / 3600 sec]

12 * [1.6 * 3600 / 1000  m/s] = 69.12 m/s

5.33 m/s      This answer is a bit shorter than using 5280 feet.

Using 5280 feet

12 miles / hour [5280 ft/1 mile] [1 m/3.281 feet] * [1 hr/3600 sec]

12 * 5280 / (3.281 * 3600)

12 *. 4470

5.36

Jack

330 feet / minute [ 1 meter / 3.281 feet] [1 minute / 60 seconds]

330 * 1/(3.281 * 60)

330 * 1/(196.86)

1.676 m/s

She's going faster than he is, no matter which method is used to do the calculation

4 0
1 year ago
What is the mass of nickel(ii) nitrate (182.71 g/mol) dissolved in 25.0 ml of 0.100 m ni(no3)2 solution?
Studentka2010 [4]
The mass  of  ni(NO3)2  that  dissolved  in  25.0 ml  of 0.100m  ni(NO3)2  solution  is  calculated  as   follows

fin  the  number  of  moles   =  molarity   x  volume in  liters

=25  x0.100/ 1000= 2.5  x10^-3  moles
mass  =  mass  x  molar  mass
= 2.5  x10^-3 moles x  182.71 g/mol  = 0.457  grams
4 0
2 years ago
Read 2 more answers
Give a possible explanation for the relative amounts of the isometric methyl nitrobenzoates formed in the nitration reaction. Co
vovikov84 [41]

Answer:

The electrophilic aromatic substitution reaction nitration is used to nitrate methyl benzoate and acetanilide with a nitronium ion. Crystallization was used to purify the product. The melting point was used to determine its purity and the regiochemistry of the products.

Explanation:

Methyl m-Nitrobenzoate is formed in this

reaction rather that ortho/para isomers

because of the ester group of your starting

product of methylbenzoate. The functional

group of ester is a electron withdrawing group

causing nitrobenzene (N02) to become in the

meta position. Thus N02 is a deactivating

group causing itself to be a meta director.

Basically you must look at the substituents

that are attached to your starting benzene ring

in order to figure out whether your reaction

with be ortho/para directors or meta

directors. If the substituents are electron

withdrawing groups then you will be left with

meta as your product but if your substituents

are electron donating groups then your

product will be ortho/para.

4 0
2 years ago
What is the molarity of a solution that contains 0.500 mole of kno3 dissolved in 0.500-liter of solution?
belka [17]

Answer : The molarity of solution is, 1.00 M

Explanation : Given,

Moles of KNO_3 = 0.500 mol

Volume of solution = 0.500 L

Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.

Formula used :

\text{Molarity}=\frac{\text{Moles of }KNO_3}{\text{Volume of solution (in L)}}

Now put all the given values in this formula, we get:

\text{Molarity}=\frac{0.500mol}{0.500L}=1.00mole/L=1.00M

Therefore, the molarity of solution is, 1.00 M

7 0
2 years ago
Which choice(s) correctly rank(s) the bonds in terms of increasing polarity?
Marina CMI [18]

Answer:

(II) only correctly rank the bonds in terms of increasing polarity.

Explanation:

Bond polarity is proportional to difference in electronegativity between bonded atoms.

Atoms    Electronegativity          Bond        Electronegativity difference

Cl                          3.0                       Cl-F                      1.0

Br                          2.8                       Br-Cl                     0.2

F                            4.0                       Cl-Cl                      0

H                            2.1                       H-C                       0.4

C                            2.5                       H-N                       0.9

N                             3.0                      H-O                       1.4

O                             3.5                      Br-F                       1.2

I                               2.7                      I-F                         1.3

Si                             1.9                      Cl-F                       1.0  

P                              2.2                      Si-Cl                      1.1

                                                          Si-P                        0.3

                                                          Si-C                        0.6

                                                           Si-F                        2.1

So, clearly, order of increasing polarity : O-H > N-H > C-H

So, (II) only correctly rank the bonds in terms of increasing polarity

4 0
2 years ago
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