answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
arsen [322]
2 years ago
14

To plan ahead using REPS and Checks, choose the minimum space cushion needed to maintain folloying distance traveling at 25 MPH

(for a cargo van)?
Chemistry
1 answer:
BaLLatris [955]2 years ago
3 0

The <em>minimum space cushion</em> defines the required amount of space which vehicles should maintain in other to afford them the time and space to gain control in emergency scenarios. Hence, the minimum space cushion required in the scenario is 4 seconds.

In cases of mishaps or accidents, the space cushion might just afford other cars the space to maneuver their way to safety rather than being caught up in the collison or accident.

The required space cushion in most scenario is usually between 2 - 5 seconds, with additional space afforded depending on the <em>length and type of the vehicle</em>.

Therefore, to ensure safety, the required minimum space cushion to be left when driving being a cargo van traveling at a <em>speed of 25mph is 4 seconds</em>.

Learn more :brainly.com/question/24535523

You might be interested in
Compound w , c6h13cl, undergoes base-promoted e2 elimination to give a single c6h12 alkene, y. compound x, c6h13br, undergoes a
CaHeK987 [17]
<span>Answer: W must be 5-chloro-2-methylpentane. It can give only 4-methy-1-pentene (Y) upon dehydrohalogenation: X must be 4-chloro-2-methylpentane. Dehydrohalogenation yields both Y and 4-methyl-2-pentene. (Z)</span>
5 0
2 years ago
When 0.610 g of titanium is combusted in a bomb calorimeter, the temperature of the calorimeter increases from 25.00 °C to 50.50
PtichkaEL [24]

Answer:

(ΔHrxn)= 0.15kJ/mol

Explanation:

(ΔHrxn) = mc∆t

=0.00061×9.84×(50.5-25)

= 0.153kJ/mol

8 0
2 years ago
A solution has a concentration of 0.6mol/dm³. If a container of this solution holds 3 moles of solute, what volume of solution i
FinnZ [79.3K]

Answer: 3 moles solute x  1 dm^3/0.60 moles solute = 5 dm^3

Explanation:

6 0
2 years ago
Choose the molecule(s) that will only show two signals, with an integration ratio of 2:3, in their 1H NMR spectrum.
mrs_skeptik [129]

The question is missing the molecules in which the integration ratio of 2:3 will be observed. The complete question is given in the attachment.

Answer:

Molecule (a), (c), and (f) will show two peaks with the integration ratio of 2:3 in their 1H NMR spectrum

Explanation:

In the 1H NMR spectrum, the peak area is dependent on the number of hydrogen in a specific chemical environment. Hence, the ratio of the integration of these signals provides us with the relative number of hydrogen in two peaks. This rationale is used for the assignment of molecules that will give 2:3 integration ratio in the given problem.

  • Molecule (a) have two CH₂ and three CH₃ groups. Hence, it will give two peaks and their integration ratio becomes 2:3 (Answer)
  • Molecule (b) contains three chemical environments for its hydrogen atoms
  • Molecule (c) have a single CH₂ and CH₃ group giving integration ratio of 2:3 (Answer)
  • Molecule (d) will give two peaks but their ratio will be 1:3 because of two hydrogens of CH₂ and six hydrogens from two CH₃ groups
  • Molecule (e) have three CH and three CH₃ groups, so their ratio will become 1:3
  • Molecule (f) contains four CH and two CH₃ groups, giving two peaks. So, the integration ratio of their peaks is 2:3 (Answer)
  • Molecules
  • (g)
  • and
  • (h)
  • both have two CH and two CH₃ groups giving two peaks with the integration ratio of 1:3

3 0
2 years ago
The value of ka for nitrous acid (hno2) at 25 ∘c is 4.5×10−4. what is the value of δg at 25 ∘c when [h+] = 5.9×10−2m , [no2-] =
LuckyWell [14K]
To get the value of ΔG we need to get first the value of ΔG°:

when ΔG° = - R*T*㏑K

when R is constant in KJ = 0.00831 KJ

T is the temperature in Kelvin = 25+273 = 298 K

and K is the equilibrium constant = 4.5 x 10^-4

so by substitution:

∴ ΔG° = - 0.00831 * 298 K * ㏑4.5 x 10^-4

        = -19 KJ

then, we can now get the value of ΔG when:

ΔG = ΔG° - RT*㏑[HNO2]/[H+][NO2]

when ΔG° = -19 KJ

and R is constant in KJ = 0.00831 

and T is the temperature in Kelvin = 298 K

and [HNO2] = 0.21 m & [H+] = 5.9 x 10^-2 & [NO2-] = 6.3 x 10^-4 m  

so, by substitution:

ΔG = -19 KJ - 0.00831 * 298K* ㏑(0.21/5.9x10^-2*6.3 x10^-4 )

       = -40

     
8 0
2 years ago
Other questions:
  • The Lewis structure for a chlorate ion, ClO3-, should show ____ single bond(s), ____ double bond(s), and ____ lone pair(s).
    15·2 answers
  • A 0.216 g sample of an aluminium compound X reacts with an excess of water to produce a single hydrocarbon gas. This gas burns c
    14·1 answer
  • What is the difference between calorie and Calorie?
    14·1 answer
  • Your task is to measure the amount of energy evolved during the combustion of some hydrocarbon. Which of the following would be
    10·1 answer
  • The target diol is synthesized in one step from 1-methylcyclopentene, but your lab partner exhausted the supply of that alkene.
    9·1 answer
  • Li Ming thinks that chlorophyll is a reactant of photosynthesis, but her classmate Julian disagrees. Who is correct, and why?
    9·2 answers
  • Albus Dumbledore provides his students with a sample of 19.3 g of sodium sulfate. How many oxygen atoms are in this sample
    6·1 answer
  • Sodium reacts with chlorine gas according to the following reaction: 2Na(s)+Cl2(g)→2NaCl(s) What volume of Cl2 gas, measured at
    10·1 answer
  • Consider the reaction: 2 Al + 3Br2 → 2 AlBr3 Suppose a reaction vessel initially contains 5.0 mole Al and 6.0 mole Br2. What is
    7·1 answer
  • Use the internet or your textbook as a reference to compare and contrast the Arrhenius Theory of acids and bases vs. the Brønste
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!