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timama [110]
2 years ago
7

Arrange these compounds by their expected vapor pressure: H2O NCl3 Br2

Chemistry
1 answer:
Tamiku [17]2 years ago
6 0

Answer: Given compounds are arranged in decreasing order of their vapor pressure as follows.

        Br_{2} > NCl_{3} > H_{2}O

Explanation:

Vapor pressure is defined as the pressure exerted by the vapors which are present on the surface of a liquid. Less is the intermoecular forces present within the molecules of a substance more will be its vapor pressure.

For example, Br_{2} is a gas and there exists Vander waal forces between its molecules. Hence, it has more vapor pressure than NCl_{3} and H_{2}O.

In H_{2}O, there exists hydrogen bonding which is stronger than bonding present in NCl_{3}. So, H_{2}O has low vapor pressure.

In NCl_{3}, there exists dipole-dipole interaction which is stronger than Vander waal forces but weaker than hydrogen bonding.

Therefore, given compounds are arranged in decreasing order of their vapor pressure as follows.

        Br_{2} > NCl_{3} > H_{2}O

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Recall that your hypothesis is that these values are the fraction of atoms that are still radioactive after n half-life cycles.
jolli1 [7]

Answer : A= 0.5, B = 0.25 , C = 0.125, D = 0.015625 and E = 0.00390625

Explanation :

Half life of a substance is defined as the amount of time taken by the substance to reduce to half of its original amount.

Here n represents the number of half lives.

The amount of substance that remains after n half lives can be calculated using the given formula, 0.5^{n}

So when we have n =1,

Fraction of substance that remains = 0.5¹ = 0.5.

That means after first half life over, the amount of substance that remains is 0.5 times that of original.

Therefore we have A = 0.5

When n = 2, we have 0.5² = 0.25

So when 2 half lives are over, the amount of substance that remains is 0.25 times that of original

Therefore B = 0.25

When n = 3, we have 0.5³ = 0.125

So when 3 half lives are over, the amount of substance that remains is 0.125 times that of original.

Therefore we have C = 0.125

When n = 6 , we have 0.5⁶ = 0.015625

So D = 0.015625

When n = 8, we have 0.5⁸ = 0.00390625

Therefore E = 0.00390625

The values for A, B, C, D and E are 0.5, 0.25, 0.125, 0.015625 and 0.00390625 respectively.

8 0
2 years ago
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A sample is prepared by completely dissolving 10.0 grams of NaCl in 1.0 liter of H2O. Which classification best describes this s
ipn [44]
(4) homobegenous mixture is your answer.
3 0
2 years ago
Sodium oxide (Na2O) crystallizes in a structure in which the O2– ions are in a face - centered cubic lattice and the Na+ ions ar
melisa1 [442]

We have to know the number of Na⁺ ions in the unit cell.

The number of Na⁺ ions in the unit cell is (D) 8.

Sodium oxide (Na2O) crystallizes in a structure in which the O2– ions are in a face - centered cubic lattice and the Na+ ions are in tetrahedral holes.

O²⁻ ions are in a face centred cubic lattice, so the number of O²⁻ ions per unit cell is equal to 4. The number of  tetrahedral hole= 2 X 4=8. Na+ ions are present in tetrahedral holes, which indicates there are 8 number of Na+ ions in the unit cell.


3 0
2 years ago
When an electron in a 2p orbital of a particular atom makes a transition to the 2s orbital, a photon of approximate wavelength 6
Mariulka [41]

Answer:

The energy difference between these 2p and 2s orbitals is 3.07\times 10^{-19} J

Explanation:

Wavelength of the photon emitted = \lambda =646.3 nm =646.3\times 10^{-9} m

Energy of the photon will corresponds to the energy difference between 2p and 2s orbital = E

Energy of the photon is given by Planck's equation:

E=\frac{hc}{\lambda }

h = Planck's constant = 6.626\tiomes 10^{-34} Js

c = Speed of the light = 3\times 10^8 m/s

E=\frac{6.626\tiomes 10^{-34} Js\times 3\times 10^8 m/s}{646.3\times 10^{-9} m}

E=3.07\times 10^{-19} J

The energy difference between these 2p and 2s orbitals is 3.07\times 10^{-19} J

3 0
2 years ago
The density of methanol is 0.7918g/mL. Calculate the mass of 89.9mL of this liquid.
Novosadov [1.4K]
The mass is 71.2 g.

Mass = 89.9 mL × \frac{0.7918 g}{1 mL} = 71.2 g
4 0
2 years ago
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