It requires 0.0780L of a 0.12 M HCl solution to completely neutralize 0.0280L of an unknown LiOH solution. What is the concentra
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Answer:
a) 11.55 moles of carbon dioxide gas are formed from 3.85 mole of propane.
15.4 moles of water are formed from 3.85 mole of propane.
b)0.5176 moles of water are formed from 0.647 mole of oxygen gas.
0.1294 moles of propane are consumed.
Explanation:
a) Moles of propane = 3.85 moles
According to reaction, 1 mole of propane gives 3 moles of carbon dioxide gas.
Then 3.85 moles of propane will give:
of carbon dioxide gas.
11.55 moles of carbon dioxide gas are formed from 3.85 mole of propane.
According to reaction, 1 mole of propane gives 4 moles of water gas.
Then 3.85 moles of propane will give:
of water .
15.4 moles of water are formed from 3.85 mole of propane.
b) Moles of oxygen gas = 0.647 moles
According to reaction, 5 mole of oxygen gas gives 4 moles of water.
Then 0.647 moles of oxygen will give:
of water.
0.5176 moles of water are formed from 0.647 mole of oxygen gas.
According to reaction, 5 mole of oxygen gas reacts with 1 mole of propane.
Then 0.647 moles of oxygen will give:
of propane.
0.1294 moles of propane are consumed.
Answer : The cell emf for this cell is 0.118 V
Solution :
The half-cell reaction is:
In this case, the cathode and anode both are same. So, is equal to zero.
Now we have to calculate the cell emf.
Using Nernest equation :
where,
n = number of electrons in oxidation-reduction reaction = 1
= ?
= 0.0222 M
= 2.22 M
Now put all the given values in the above equation, we get:
Therefore, the cell emf for this cell is 0.118 V