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bogdanovich [222]
2 years ago
9

This is a document that each chemical manufacturer, distributor, or importer must provide for each hazardous chemical. It contai

ns detailed information such as the properties of each chemical; the physical, health, and environmental health hazards; protective measures; and safety precautions for handling, storing, and transporting the chemical. This document is typically stored in the work space but is likely not attached to the container containing the chemical.
Chemistry
2 answers:
Yuliya22 [10]2 years ago
8 0
I believe this document being described is called MSDS or Material Safety Data Sheet. It <span> is a document that contains information on the potential hazards (health, fire, reactivity and environmental) and how to work safely with the chemical product. Hope this answers the question.</span>
kkurt [141]2 years ago
7 0

Answer : HazCom

Explanation : Hazard communication which is also known as HazCom, is a set of processes and procedures that every employers and importers must implement in their workplace to effectively communicate hazards associated with chemicals during handling, shipping, and any form of exposure.

The OSHA Hazard Communication Standard is a U.S. regulation which governs the evaluation and communication of hazards associated with chemicals at the workplace. It is typically not attached to any specific chemical container but is stored in the workplace.

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What is the 2s in 42,256
MissTica

42,256 = 2,000

42,256 = 200

together they'd be 2,200 (if that's what you needed as well)

5 0
2 years ago
Read 2 more answers
Calculate the molarity of sodium chloride in a half-normal saline solution (0.45% NaCl). The molar mass of NaCl is
Rus_ich [418]

Answer:

0.077 M

Explanation:

Data Given :

The concentration of half normal (NaCl) saline = 0.45g / 100 g

So,

Volume of Solution = 100 g = 100 mL

Volume of Solution in Liter = 100 mL / 1000

Volume of Solution = 0.1 L

molar mass of NaCl = 58.44 g/mol

Molarity:

Molarity is the representation of the solution. It is amount of solute in moles per liter of solution and represented by M

Formula used for Molarity

                M = moles of solute / Liter of solution . . . . . . . . . . (1)

Now to find number of moles of Nacl

                no. of moles of NaCl = mass of NaCl / molar mass

                no. of moles of NaCl = 0.45g / 58.44 g/mol

               no. of moles of NaCl = 0.0077 g

Put values in the eq (1)

                  M = moles of solute / Liter of solution . . . . . . . . . . (1)

                  M = 0.0077 g / 0.1 L

                  M = 0.077 M

So the molarity of half-normal saline solution (0.45% NaCl) = 0.077 M

3 0
2 years ago
A 2.0% (w/v) solution of sodium hydrogen citrate, Na2C6H6O7, which also contains 2.5% (w/v) of dextrose, C6H12O6, is used as an
tamaranim1 [39]

Answer:

0.0847M is molarity of sodium hydrogen citrate in the solution

Explanation:

The 2.0%(w/v) solution of sodium hydrogen citrate contains 2g of the solute in 100mL of solution. To find the molarity of the solution we need to convert the mass of solute to moles using molar mass and the mL of solution to Liters because molarity is the ratio between moles of sodium hydrogen citrate and liters of solution.

<em>Moles Na2C6H6O7:</em>

<em>Molar Mass:</em>

2Na: 2*22.99g/mol: 45.98g/mol

6C: 6*12.01g/mol: 72.01g/mol

6H: 6*1.008g/mol: 6.048g/mol

7O: 7*16g/mol: 112g/mol

45.98g/mol + 72.01g/mol + 6.048g/mol + 112g/mol = 236.038g/mol

Moles of 2g:

2g * (1mol / 236.038g) = <em>8.473x10⁻³ moles</em>

<em />

<em>Liters solution:</em>

100mL * (1L / 1000mL) = <em>0.100L</em>

<em>Molarity:</em>

8.473x10⁻³ moles / 0.100L =

<h3>0.0847M is molarity of sodium hydrogen citrate in the solution</h3>
3 0
1 year ago
Read 2 more answers
Find the concentration of H+ ions at a pH = 11 and pH = 6. Then divide the concentration of H+ ions at a pH = 11 by the of H+ io
andrew11 [14]

Explanation:

When pH of the solution is 11.

pH=-\log[H^+]

11=-\log[H^+]

[H^+]=1\times 10^{-11} M..(1)

At pH = 11, the concentration of H^+ ions is 1\times 10^{-11} M.

When the pH of the solution is 6.

pH=-\log[H^+]'

6=-\log[H^+]'

[H^+]'=1\times 10^{-6} M..(2)

At pH = 6, the concentration of H^+ ions is 1\times 10^{-6} M.

On dividing (1) by (2).

\frac{[H^+]}{[H^+]'}=\frac{1\times 10^{-11} M}{1\times 10^{-6}}=1\times 10^{-5}

The ratio of hydrogen ions in solution of pH equal to 11 to the solution of pH equal to 6 is 1\times 10^{-5}.

Difference between the H^+ ions at both pH:

1\times 10^{-6} M-1\times 10^{-11} M=9.99\time 10^{-7} M

This means that Hydrogen ions in a solution at pH = 7 has 9.99\time 10^{-7} M ions fewer than in a solution at a pH = 6

6 0
2 years ago
Read 2 more answers
The balanced reaction equation for combustion of heptane, C 7 H 16 , is C 7 H 16 + 11 O 2 ⟶ 7 CO 2 + 8 H 2 O If the reaction pro
Scorpion4ik [409]

Answer:

1) There were 7.65 grams of heptane burned

2) There reacted 38.94 grams of HCl

Explanation:

<em>1) The combustion of heptane</em>

Step 1: Data given

Mass of CO2 = 23.5 grams

Molar mass of CO2 = 44.01 g/mol

Step 2: The balanced equation:

C7H16  + 11O2 ⟶ 7CO2 + 8H2O

Step 3: Calculate moles of CO2

Moles CO2 = mass CO2 / molar mass CO2

Moles CO2 = 23.5 grams / 44.01 g/mol

Moles CO2 = 0.534 moles

Step 4: Calculate moles heptane

For 1 mole of Heptane , we need 11 moles of O2 to produce 7 moles of CO2 and 8 moles of H2O

For 0.534 moles of CO2 we have 0.534/7 = 0.0763 moles of  heptane

Step 5: Calculate mass of heptane

Mass of heptane = moles heptane * molar mass heptane

Mass heptane = 0.0763 moles * 100.21 g/mol

Mass heptane = 7.65 grams

<em></em>

<em>2) The reaction of limestone with hydrochloric acid</em>

Step 1: Data given

Mass of CO2 = 23.5 grams

Step 2: The balanced equation:

CaCO3 + 2HCl ⟶ CaCl2 + CO2 + H2O

Step 3: Calculate moles of CO2

Moles CO2 = mass CO2 / molar mass CO2

Moles CO2 = 23.5 grams / 44.01 g/mol

Moles CO2 = 0.534 moles

Step 4: Calculate moles of HCl

For 1 mol of CaCO3 we need 2 moles of HCl to produce 1 mol of CaCl2, 1 mol of CO2 and 1 mol of H2O

For 0.534 moles of CO2 we have 2*0.534 = 1.068 moles of HCl

Step 5: Calculate mass of HCl

Mass HCl = moles HCl * molar mass HCl

Mass HCl = 1.068 moles * 36.46 g/mol

Mass HCl = 38.94 grams

3 0
2 years ago
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