Answer:
See explaination
Explanation:
Please kindly check attachment for the step by step solution of the given problem
Answer is: directly up.
Neon (Ne) is noble gas with atomic number 10 and atomic mass around 20.
1) directly up is noble gas helium (He) with atomic mass around 4.
2) directly down is noble gas argon (Ar) with atomic mass around 40.
3) directly to the left is florine (F), with smaller atomic mass, but also from different group.
4) directly to the right there no elements, because noble gases are far right in 18. group of Periodic table.
Answer : The enthalpy change is, 104.5327 KJ
Solution :
The conversions involved in this process are :
Now we have to calculate the enthalpy change.
![\Delta H=[m\times c_{p,s}\times (T_{final}-T_{initial})]+n\times \Delta H_{fusion}+[m\times c_{p,l}\times (T_{final}-T_{initial})]+n\times \Delta H_{vap}+[m\times c_{p,g}\times (T_{final}-T_{initial})]](https://tex.z-dn.net/?f=%5CDelta%20H%3D%5Bm%5Ctimes%20c_%7Bp%2Cs%7D%5Ctimes%20%28T_%7Bfinal%7D-T_%7Binitial%7D%29%5D%2Bn%5Ctimes%20%5CDelta%20H_%7Bfusion%7D%2B%5Bm%5Ctimes%20c_%7Bp%2Cl%7D%5Ctimes%20%28T_%7Bfinal%7D-T_%7Binitial%7D%29%5D%2Bn%5Ctimes%20%5CDelta%20H_%7Bvap%7D%2B%5Bm%5Ctimes%20c_%7Bp%2Cg%7D%5Ctimes%20%28T_%7Bfinal%7D-T_%7Binitial%7D%29%5D)
where,
= enthalpy change = ?
m = mass of water = 25 g
= specific heat of solid water = 2.09 J/gk
= specific heat of liquid water = 4.18 J/gk
= specific heat of liquid water = 1.84 J/gk
n = number of moles of water = 
= enthalpy change for fusion = 6.01 KJ/mole = 6010 J/mole
= enthalpy change for vaporization = 40.67 KJ/mole = 40670 J/mole
Now put all the given values in the above expression, we get
![\Delta H=[25g\times 4.18J/gK\times (273-277)k]+1.39mole\times 6010J/mole+[25g\times 2.09J/gK\times (373-273)k]+1.39mole\times 40670J/mole+[25g\times 1.84J/gK\times (383-373)k]](https://tex.z-dn.net/?f=%5CDelta%20H%3D%5B25g%5Ctimes%204.18J%2FgK%5Ctimes%20%28273-277%29k%5D%2B1.39mole%5Ctimes%206010J%2Fmole%2B%5B25g%5Ctimes%202.09J%2FgK%5Ctimes%20%28373-273%29k%5D%2B1.39mole%5Ctimes%2040670J%2Fmole%2B%5B25g%5Ctimes%201.84J%2FgK%5Ctimes%20%28383-373%29k%5D)
(1 KJ = 1000 J)
Therefore, the enthalpy change is, 104.5327 KJ
True
-They’re made up of more than one substance.
-They have the same or similar properties as the materials used to make them.
