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katovenus [111]
2 years ago
7

A vessel contains Ar(g) at a high pressure. Which of the following statements best helps to explain why the measured pressure is

significantly greater than the pressure calculated using the ideal gas law?
1. The molar mass of Ar is relatively large.2. A significant number of Ar2 molecules form.3. The attractive forces among Ar atoms cause them to collide with the walls of the container with less force.4. The combined volume of the Ar atoms is too large to be negligible compared with the total volume of the container.
Chemistry
1 answer:
Luda [366]2 years ago
5 0

Answer:

4. The combined volume of the Ar atoms is too large to be negligible compared with the total volume of the container.

Explanation:

Deviations from ideality are due to intermolecular forces and to the nonzero volume of the molecules themselves. At infinite volume, the volume of the molecules themselves is negligible compared with the infinite volume the gas occupies.

However, the volume occupied by the gas molecules must be taken into account. Each <u>molecule does occupy a finite, although small, intrinsic volume.</u>

The non-zero volume of the molecules implies that instead of moving in a given volume V they are limited to doing so in a smaller volume. Thus, the molecules will be closer to each other and repulsive forces will dominate, resulting in greater pressure than the one calculated with the ideal gas law, that means, without considering the volume occupied by the molecules.

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What is the molarity and molality of a solution that is 10.00 % by mass potassium hydrogen carbonate (KHCO3, 100.11 g/mol) and h
maksim [4K]

Answer: The molarity and molality of a solution is 1.06 M and 1.11 m respectively.

Explanation:

Molality of a solution is defined as the number of moles of solute dissolved per kg of the solvent.

Molality=\frac{n\times 1000}{W_s}

where,

n = moles of solute  =

W_s = weight of solvent in g

10.00 g of potassium hydrogen carbonate in 100 g of solution

mass of solvent = mass of solution - mass of solute = (100.0-10.00) = 90.0 g

Molality=\frac{0.09985\times 1000}{90.0}=1.11m

2. Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.

Molarity=\frac{n\times 1000}{V_s}

where,

n= moles of solute  = 0.09985

V_s = volume of solution in ml

Density of solution = 1036.5 g/L

Volume of solution =\frac{\text {mass of solution}}{\text {Density of solution}}=\frac{100.0g}{1.0650g/ml}=93.90ml

Molality= \frac{0.09985\times 1000}{93.90ml}=1.06M

4 0
2 years ago
A solution contains cr3+ ions. the addition of 0.063 l of 1.50 m naf solution was needed to completely precipitate the chromium
steposvetlana [31]

Cr{3+} + 3 NaF → CrF3 + 3 Na{+} <span>

First calculate the total mols of NaF. 

(0.063 L) x (1.50 mol/L NaF) = 0.0945 mol NaF total </span>

 

Using stoichiometric ratio:

<span>0.0945 mol NaF * (1 mol Cr3+ / 3 mol NaF) * (51.9961 g Cr3+/mol) = 1.6379 g Cr3+</span>
6 0
2 years ago
The Rydberg constant is 3.3 x 10 15 Hz. this value is also
mina [271]

Answer:

Rydberg constant 3.3 x 10¹⁵ Hertz is equal to 1.090 x 10⁷ m⁻¹

Explanation:

Given;

Rydberg constant as  3.3 x 10¹⁵ Hz

1 Rydberg constant = 3.3 x 10¹⁵ Hz

1 Rydberg constant  = 1.090 x 10⁷ m⁻¹

Therefore, Rydberg constant 3.3 x 10¹⁵ Hertz is equal to 1.090 x 10⁷ m⁻¹

7 0
2 years ago
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Consider the structure of the amino acid alanine. indicate the hybridization about each interior atom.
OLEGan [10]
The structure of Alanine is shown below,
Except the carbon atom of carbonyl group which is Sp² Hybridized, all remaining atoms are Sp³ Hybridized. The hybridization of each element is depicted in a box below,

5 0
2 years ago
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2. If 2.50g of sodium hydroxide is being reacted with 4.30g of magnesium chloride, how many grams of magnesium hydroxide would b
Virty [35]

Answer:

1.822 g of magnesium hydroxide would be produced.

Explanation:

Balanced reaction: 2NaOH+MgCl_{2}\rightarrow Mg(OH)_{2}+2NaCl

     Compound                                 Molar mass (g/mol)

         NaOH                                           39.997

         MgCl_{2}                                           95.211

        Mg(OH)_{2}                                        58.3197

So, 2.50 g of NaOH = \frac{2.50}{39.997} mol of NaOH = 0.0625 mol of NaOH

      4.30 g of MgCl_{2}  = \frac{4.30}{95.211} mol of MgCl_{2} = 0.0452 mol of MgCl_{2}

According to balanced equation-

2 mol of NaOH produce 1 mol of Mg(OH)_{2}    

So, 0.0625 mol of NaOH produce (\frac{0.0625}{2}) mol of NaOH or 0.03125 mol of NaOH

1 mol of MgCl_{2} produces 1 mol of Mg(OH)_{2}

So, 0.0452 mol of MgCl_{2} produce 0.0452 mol of Mg(OH)_{2}

As least number of moles of Mg(OH)_{2} are produced from NaOH therefore NaOH is the limiting reagent.

So, amount of Mg(OH)_{2} would be produced = 0.03125 mol

                                                                           = (0.03125\times 58.3197) g

                                                                           = 1.822 g

6 0
2 years ago
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