How many atoms of fluorine are in ZrF4

Chemistry

1 answer:

harkovskaia [24]2 years ago

3 0

Answer:

Zirconium tetrafluoride has 4 atoms of flourine and 1 atom of Zirconium

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Explain how this lab simulates the various isotopes of an element

givi [52]

A trustable source was above to say that the first experiments will decide how many isotopes of this element exist. Isotopes are atoms of an element which bear chemically the identical but have dissimilar physical properties. One adaptable property among isotopes is their atomic mass.

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2 years ago

Fluorine gas is placed in contact with calcium metal at high temperatures to produce calcium fluoride powder. What is the formul

Mars2501 [29]

Answer:

Upper F subscript 2 (g) plus upper C a (s) right arrow with delta above upper C a upper F subscript 2 (s).

Explanation:

This is a chemical reaction problem.

In expressing any chemical reaction, we need to understand that there are reactants and products.

The reactants are the species on the left hand side that are combining.

The products are the species on the right hand side that are formed.

Every chemical reaction is obeys the law of conservation of matter i.e equal number of matter on both sides.

Using the statement of this problem, we can deduce that;

Reactants are Fluorine gas and Calcium metal

Product is Calcium Fluoride

Note: A metal is a solid(s) and powder is a solid(s). A gas is denoted as (g). They depict the state of the species reacting.

F₂ $_{(g)}$ + Ca $_{(s)}$ → CaF₂ $_{(s)}$

We can see that equal number of atoms are on both sides of the expression.

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2 years ago

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For the following dehydrohalogenation (E2) reaction, draw the Zaitsev product(s) resulting from elimination involving C3–C4 (i.e

Bond [772]

Answer:

2-methyl-butene

Explanation:

For the E2 mechanism, we have an anti-elimination. The Br leaves the molecule and the base removes the hydrogen in the anti position to form the double that's why only one structure is produced. (See figure 1)

Since we have 2 hydrogens on the right carbon, we cannot indicate a specific stereoisomer, in other words, it is not possible to assign a Z or E configuration for this alkene.