Answer:
The volume of the container is 59.112 L
Explanation:
Given that,
Number of moles of Oxygen, n = 3
Temperature of the gas, T = 300 K
Pressure of the gas, P = 1.25 atm
We need to find the volume of the container. For a gas, we know that,
PV = nRT
V is volume
R is gas constant, R = 0.0821 atm-L/mol-K
So,

So, the volume of the container is 59.112 L
Answer: 178.9 g
Explanation:
Density = 
find volume of the cube: (5.80 cm) (5.80 cm) (5.80cm) = 195.112 cm³
1.0 cm³ = 1.0 mL
so 195.112 cm³ = 195.112 mL
plug value into density equation:
0.917 g/mL = (mass) / (195.112 mL)
and solve for mass!
Answer:
1.123x10⁻⁴ moles of alanine
Explanation:
In order to convert grams of alanine into moles, <em>we need to know its molecular weight</em>:
The formula for alanine is C₃H₇NO₂, meaning <u>its molecular weight would be</u>:
- 12*3 + 7*1 + 14 + 16*2 = 89 g/mol
Then we <u>divide the sample mass by the molecular weight</u>, to do the conversion:
- 1.0x10⁻² g ÷ 89 g/mol = 1.123x10⁻⁴ moles
1) ideal gas law: p·V = n·R·T.
p - pressure of gas.
V -volume of gas.
n - amount of substance.
R - universal gas constant.
T - temperature of gas.
n₁ = 0,04 mol, V₁ = 0,06 l.
n₂ = 0,07 mol, V₂ = 0,06 · 0,07 ÷ 0,04 = 0,105 l.
2) V₁ = 0,06 l, T₁ = 240,00 K.
T₂ = 340,00 K, V₂ = 340 · 0,06 ÷ 240 = 0,05 l.