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Dmitriy789 [7]
2 years ago
14

A semipermeable membrane separates two solutions of different concentrations. Identify which of the following statements are cor

rect regarding osmosis and reverse osmosis.
A A solvent can ideally move in both directions through a semipermeable membrane.B A pressure equal to that of the osmotic pressure will result in reverse osmosis.C The movement of the solvent particles from a concentrated solution to a dilute solution is known as reverse osmosis.D Osmosis occurs when the solvent molecules move from a solution of higher solute concentration to a solution of lower solute concentration.E Solute particles can move in both directions through a semipermeable membrane.
Chemistry
2 answers:
GenaCL600 [577]2 years ago
5 0

Answer:

The correct options are A, and C.

Explanation:

Osmosis: It is defined as the movement of solvent with the help of selectively semipermeable membrane into a region of where high solute concentration is present to equalize the concentration of solute on the both compartments.

Reverse osmosis: It is defined as the movement of the high concentration solvent is forced onto the lighter concentration side with the help of mechanical pressure.

IRINA_888 [86]2 years ago
3 0

Answer:

C. The movement of the solvent particles from a concentrated solution to a dilute solution is known as reverse osmosis.

A. A solvent can ideally move in both directions through a semipermeable membrane

Explanation:

When osmosis occurs, solvent is moved from a region of lower concentration to a region of higher concentration through a semipermeable membrane. For example, if a fresh water fish is introduced into saline water, the fish quickly looses water due to osmosis and dies.

Osmosis is driven by osmotic pressure. Reverse osmosis is a process by which a solvent passes through a porous (semi permeable) membrane in the direction opposite to the direction for natural osmosis when subjected to a hydrostatic pressure greater than the osmotic pressure. Hence the answer choices above.

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Vanyuwa [196]

Answer: 770 g water are needed to dissolve 27.8 g of ammonium nitrate NH_4NO_3 in order to prepare a 0.452 m solution

Explanation:

Molality : It is defined as the number of moles of solute present per kg of solvent

Formula used :

Molality=\frac{n\times 1000}{W_s}

where,

n= moles of solute

Moles of NH_4NO_3=\frac{\text{Given mass}}{\text{Molar mass}}=\frac{27.8g}{80.0g/mol}=0.348moles  

W_s = weight of the solvent in g = ?

0.452=\frac{0.348\times 1000}{W_s}

W_s=770g

Thus 770 g water are needed to dissolve 27.8 g of ammonium nitrate NH_4NO_3 in order to prepare a 0.452 m solution

5 0
2 years ago
What is the percent composition by mass of nitrogen in the compound N2H4 (gram-formula mass = 32 g/mol)?
Alex

Answer:

\large \boxed{93\, \% }

Explanation:

1. Calculate the molar mass of N₂H₄

2N = 2 × 14 = 28

4H = 2 ×  1  = <u>  4</u>

           Tot. = 32

2. Calculate the mass percent of N

\text{\% of element} = \dfrac{\text{mass of element}}{\text{mass of compound}} \times 100 \, \% = \dfrac{\text{28}}{\text{32}} \times 100 \, \% =\mathbf{88 \, \%}\\\\\text{The percentage of N in N$_{2}$H$_{4}$ is $\large \boxed{\mathbf{88\, \% }}$}}

3 0
2 years ago
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Iodine is 80% 127I, 17% 126I, and 3% 128I. Calculate the average atomic mass of Iodine.
trasher [3.6K]
<h3>The average atomic mass of Iodine : 126.86 amu</h3><h3>Further explanation</h3>

Given

80% 127I, 17% 126I, and 3% 128I.

Required

The average atomic mass

Solution

The elements in nature have several types of isotopes

Atomic mass is the average atomic mass of all its isotopes

Mass atom X = mass isotope 1 . % + mass isotope 2.% + ... mass isotope n.%

Atomic mass of Iodine = 0.8 x 127 + 0.17 x 126 + 0.03 x 128

Atomic mass of Iodine = 101.6 + 21.42 + 3.84

Atomic mass of Iodine = 126.86 amu

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2 years ago
1.562 g sample of the alcohol CH3CHOHCH2CH3 is burned in an excess of oxygen. What masses of H2O and CO2 should be obtained
Diano4ka-milaya [45]

Answer:

m_{CO_2}=3.709gCO_2 \\\\m_{H_2O}=1.898gH_2O

Explanation:

Hello.

In this case, since the molecular formula of the given alcohol is C₄H₁₀O (molar mass = 74.14 g/mol), we can write its combustion reaction as shown below:

C_4H_1_0O+6O_2\rightarrow 4CO_2+5H_2O

Thus, since there is a 1:4 mole ratio with carbon dioxide (molar mass = 44..01 g/mol) and a 1:5 mole ratio with water (molar mass = 18.02 g/mol), we can compute the obtained masses as shown below:

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1 year ago
How many moles of xenon gas are necessary to exert a 0.64atm pressure in an 8.5L container at 300.0K?
Sindrei [870]

Answer:

0.026 moles

Explanation:

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1 year ago
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