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Dmitriy789 [7]
2 years ago
14

A semipermeable membrane separates two solutions of different concentrations. Identify which of the following statements are cor

rect regarding osmosis and reverse osmosis.
A A solvent can ideally move in both directions through a semipermeable membrane.B A pressure equal to that of the osmotic pressure will result in reverse osmosis.C The movement of the solvent particles from a concentrated solution to a dilute solution is known as reverse osmosis.D Osmosis occurs when the solvent molecules move from a solution of higher solute concentration to a solution of lower solute concentration.E Solute particles can move in both directions through a semipermeable membrane.
Chemistry
2 answers:
GenaCL600 [577]2 years ago
5 0

Answer:

The correct options are A, and C.

Explanation:

Osmosis: It is defined as the movement of solvent with the help of selectively semipermeable membrane into a region of where high solute concentration is present to equalize the concentration of solute on the both compartments.

Reverse osmosis: It is defined as the movement of the high concentration solvent is forced onto the lighter concentration side with the help of mechanical pressure.

IRINA_888 [86]2 years ago
3 0

Answer:

C. The movement of the solvent particles from a concentrated solution to a dilute solution is known as reverse osmosis.

A. A solvent can ideally move in both directions through a semipermeable membrane

Explanation:

When osmosis occurs, solvent is moved from a region of lower concentration to a region of higher concentration through a semipermeable membrane. For example, if a fresh water fish is introduced into saline water, the fish quickly looses water due to osmosis and dies.

Osmosis is driven by osmotic pressure. Reverse osmosis is a process by which a solvent passes through a porous (semi permeable) membrane in the direction opposite to the direction for natural osmosis when subjected to a hydrostatic pressure greater than the osmotic pressure. Hence the answer choices above.

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analysis of a compound indicates that it contains 1.04 grams K 0.70 g Cr and 0.86 g O. Find its empirical formula
MrMuchimi
1.04gK*1molK/39.01g K= 0.0267 mol K
0.70gCr*1mol/52.0g Cr = <span>0.0135 mol Cr   
0.86 gO* 1 mol/16.0 g O = 0.0538 mol O
</span>0.0267 mol K/0.0135 = 2 mol K
0.0135 mol Cr  /0.0135= 1 mol Cr
 0.0538 mol O/0.035= 4 mol Cr
K2CrO4
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2 years ago
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What volume of a 0.716 m kbr solution is needed to provide 30.5 g of kbr?
Jlenok [28]
Answer is: volume of KBr is 357 mL.
c(KBr) = 0,716 M = 0,716 mol/L.
m(KBr) = 30,5 g.
n(KBr) = m(KBr) ÷ M(KBr).
n(KBr) = 30,5 g ÷ 119 g/mol.
n(KBr) = 0,256 mol.
V(KBr) = n(KBr) ÷ c(KBr).
V(KBr) = 0,256 mol ÷ 0,716 mol/L.
V(KBr) = 0,357 L · 1000 mL/L = 357 mL.
7 0
2 years ago
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C2H5OH(aq) + MnO− 4 (aq) → Mn2+(aq) + CH3COOH(aq) of acetic acid from ethanol by the action of permanganate ion in acidic soluti
Andreas93 [3]

Answer :

Ethanol (C_2H_5OH) act as reducing agent.

The smallest possible integer coefficient of MnO_4^- in the combined balanced equation is, 4

Explanation :

Redox reaction or Oxidation-reduction reaction : It is defined as the reaction in which the oxidation and reduction reaction takes place simultaneously.

Oxidation reaction : It is defined as the reaction in which a substance looses its electrons. In this, oxidation state of an element increases. Or we can say that in oxidation, the loss of electrons takes place.

Reduction reaction : It is defined as the reaction in which a substance gains electrons. In this, oxidation state of an element decreases. Or we can say that in reduction, the gain of electrons takes place.

Reducing agent : It is defined as the agent which helps the other substance to reduce and itself gets oxidized. Thus, it will undergo oxidation reaction.

Oxidizing agent : It is defined as the agent which helps the other substance to oxidize and itself gets reduced. Thus, it will undergo reduction reaction.

The given chemical reaction is,

C_2H_5OH(aq)+MnO_4^-(aq)\rightarrow CH_3COOH(aq)+Mn^{2+}(aq)

The oxidation-reduction half reaction will be :

Oxidation : C_2H_6O\rightarrow C_2H_4O_2

Reduction : MnO_4^-\rightarrow Mn^{2+}

  • Now balance oxygen atom on both side.

Oxidation : C_2H_6O+H_2O\rightarrow C_2H_4O_2

Reduction : MnO_4^-\rightarrow Mn^{2+}+4H_2O

  • Now balance hydrogen atom on both side.

Oxidation : C_2H_6O+H_2O\rightarrow C_2H_4O_2+4H^+

Reduction : MnO_4^-+8H^+\rightarrow Mn^{2+}+4H_2O

  • Now balance the charge.

Oxidation : C_2H_6O+H_2O\rightarrow C_2H_4O_2+4H^++4e^-

Reduction : MnO_4^-+8H^++5e^-\rightarrow Mn^{2+}+4H_2O

In order to balance the electrons, we multiply the oxidation reaction by 5 and reduction reaction by 4 and then added both equation, we get the balanced redox reaction.

Oxidation : 5C_2H_6O+5H_2O\rightarrow 5C_2H_4O_2+20H^++20e^-

Reduction : 4MnO_4^-+32H^++20e^-\rightarrow 4Mn^{2+}+16H_2O

The balanced chemical equation in acidic medium will be,

5C_2H_6O+4MnO_4^-+12H^+\rightarrow 5C_2H_4O_2+4Mn^{2+}+11H_2O

In the redox reaction ethanol act as reducing agent and permanganate ion act as an oxidizing agent.

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2 years ago
Even though we are well into the course Dumbledore notices some of the students are still having trouble with significant figure
Sphinxa [80]

Answer:

B) 2

Explanation:

Significant figures : The figures in a number which express the value -the magnitude of a quantity to a specific degree of accuracy is known as significant digits.

The rule apply for the multiplication and division is :

The least number of significant figures in any number of the problem determines the number of significant figures in the answer.

The rule apply for the addition and subtraction is :

The least precise number present after the decimal point determines the number of significant figures in the answer.

(3.478-2.31) = 1.168 ≅ 1.17 (Rounded to least decimal digit)

(4.428-3.56) = 0.868 ≅ 0.87 (Rounded to least decimal digit)

So,

1.17 * 0.87 = 1.0  (Rounded to least significant)

Answer - two significant digits

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2 years ago
A buffer is prepared by mixing hypochlorous acid ( HClO ) and sodium hypochlorite ( NaClO ) . If a strong base, such as NaOH , i
Dafna1 [17]

<u>Answer:</u> The balanced chemical equation is written below.

<u>Explanation:</u>

We are given:

A weak acid that is hypochlorous acid (HClO) and basic salt that is sodium hypochlorite (NaClO)

When a strong base is added to the buffer, the hydroxide ion will be neutralized by hydrogen ions from the acid.

So, the buffer component that neutralizes the additional hydroxide ions in the solution is HClO

The chemical equation for the neutralization of hydroxide ion with acid follows:

HClO+OH^-\rightarrow H_2O+ClO^-

Hence, the balanced chemical equation is written below.

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2 years ago
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