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klasskru [66]
2 years ago
10

Calculate the nuclear binding energy for 5525mn in megaelectronvolts per nucleon (mev/nucleon). express your answer numerically

in megaelectronvolts per nucleon.
Chemistry
1 answer:
VARVARA [1.3K]2 years ago
5 0

Answer:

8.533 Mev/nucleon

Explanation:

The given elements is:- ^{55}_{25}Mn

Atomic number : It is defined as the number of electrons or number of protons present in a neutral atom.

Thus, the number of protons = 25

Mass number is the number of the entities present in the nucleus which is the equal to the sum of the number of protons and electrons.

Mass number = Number of protons + Number of neutrons

55 =  25 + Number of neutrons

Number of neutrons = 30

Mass of neutron = 1.008665 amu

Mass of proton = 1.007825 amu

Calculated mass = Number of protons*Mass of proton + Number of neutrons*Mass of neutron

Thus,  

Calculated mass = (25*1.007277 + 30*1.008665) amu = 55.441875 amu

Actual mass = 54.9380451 amu

Mass defect = Δm = |54.9380451 - 55.441875| amu = 0.5038299 amu

The conversion of amu to MeV is shown below as:-

1 amu = 931.5 MeV

So, Energy = 0.5038299*931.5 MeV= 469.317552 MeV

Total number of nucleons in the atoms = 55

<u>So, Energy = 469.317552/55 MeV/nucleon = 8.533 Mev/nucleon</u>

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2 years ago
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When deducing the rate of reaction, concentration of the specie of interest is plotted on the y-axis against time on the x-axis.

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olga_2 [115]
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http://www.chemeddl.org/services/moodle/media/QBank/GenChem/Tables/EStandardTable.htm

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5 0
2 years ago
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irina1246 [14]

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Digits from 1 to 9 are always significant and have infinite number of significant figures.

All non-zero numbers are always significant.

All zero’s between integers are always significant.

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All zero’s preceding the first integers are never significant.

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7 0
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