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olchik [2.2K]
2 years ago
10

when a calcium atom loses its valence electrona the ion formed has an electron configuration that is the same as an atom of. (1)

Cl (2) Ar (3) K (4) Sc
Chemistry
2 answers:
Nikolay [14]2 years ago
4 0

Answer:

When a calcium atom loses a single valence electron, the formed ion has an electronic configuration that is the same as a potassium atom (K). This configuration does not generate stability.

When a calcium atom loses its two valence electrons, the formed ion has an electronic configuration that is the same as an argon atom (Ar ), thus achieving stability.

Explanation:

Valencia electrons are the electrons found in the last electronic layer (called valence orbitals). These electrons are what determine the ability of the atom to form bonds. When an element joins another, it does so through its valence electrons.

The noble gases are placed in group 18 of the periodic table. The seven gases are helium (He), neon (Ne), argon (Ar), krypton (Kr), xenon (Xe), radon (Rn) and oganeson (Og).  These gases have a very low chemical reactivity, that is, little combination with other elements of the periodic table because they have eight valencia electrons. For that reason they are called inert gases.

The reactivity of an element measures the tendency to combine with others. In the formation of compounds there is a tendency to catch, lose or share electrons between atoms.  The elements tend to react to resemble the closest noble gases in terms of their electronic configuration of the last layer (valencia electrons), that is, having eight electrons in the last layer to be stable. Then, the reactivity of an element measures the tendency to combine with others to generate the mentioned stability.

Calcium is in group 2 and period 4. Potassium is in group 1 and period 4. Given the above, <u><em>when a calcium atom loses a single valence electron, the formed ion has an electronic configuration that is the same as a potassium atom (K). However, this configuration does not generate stability because a noble gas configuration was not reached. </em></u>The nearest noble gas is Argon, located in group 18 and period 3. Then, <u><em>when a calcium atom loses its two valence electrons, the formed ion has an electronic configuration that is the same as an argon atom (Ar ), thus achieving stability.</em></u>

andrew-mc [135]2 years ago
3 0
(2) argon. This is because Ca originally has 20 total electrons with a configuration of 2,8,8,2. When it looses its valence electrons it remains with 18 electrons total (2,8,8 config). Argon has 18 electrons total too (2,8,8 config).
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Gnoma [55]
An r-selected species reproduces much faster than K-selected species.

r-selected species focuses on maturing and reproducing quickly. r-selected species will probably reproduce when the water supply is there for the short period of time; thus, increasing the chance of the r-selected species of surviving.

K-selected species, on the other hand, focus on raising their young and reproduce later. Since the K-selected species take long to mature before reproducing, water supply may run out before they have a chance of fully maturing; thus, K-selected species have a lower chance of survival.

Hope this helps.
If you need anything more, feel free to comment! Have an awesome day! :)

~Collinjun0827, Junior Moderator
6 0
2 years ago
Read 2 more answers
A 3.96x10^-24 M solution of compound A exhibited an absorbance of 0.624 at 238 nm in a 1.000-cm cuvet; a blank solution containi
viktelen [127]

Actual question from source:-

A 3.96x10-4 M solution of compound A exhibited an absorbance of 0.624 at 238 nm in a 1.000 cm cuvette.  A blank had an absorbance of 0.029.  The absorbance of an unknown solution of compound A was 0.375.  Find the concentration of A in the unknown.

Answer:

Molar absorptivity of compound A = 1502.53\ {Ms}^{-1}

Explanation:

According to the Lambert's Beer law:-

A=\epsilon l c

Where, A is the absorbance

 l is the path length  

\epsilon is the molar absorptivity

c is the concentration.  

Given that:-

c = 3.96\times 10^{-4}\ M

Path length = 1.000 cm

Absorbance observed = 0.624

Absorbance blank = 0.029

A = 0.624 - 0.029 = 0.595

So, applying the values in the Lambert Beer's law as shown below:-

0.595=\epsilon\times 1.000\ cm\times 3.96\times 10^{-4}\ M

\epsilon=\frac{0.595}{3.96\times 10^{-4}}\ {Ms}^{-1}=1502.53\ {Ms}^{-1}

<u>Molar absorptivity of compound A = 1502.53\ {Ms}^{-1}</u>

4 0
2 years ago
Type in the correct values to correctly represent the valence electron configuration of oxygen: AsB2pC
valkas [14]

Answer:

2s²2p⁴

Explanation:

Oxygen is an element on the periodic table with a total of 8 electrons. It's electronic configuration is given as 2,6.

Using the orbital notation we write as 1s²2s²2p⁴

Also, the valence electrons are the electrons in the outermost shell of an atom. These electrons mostly determine the chemical properties of an atom.

Oxygen has a total of 6 electrons in its outermost shell and it is given as 2s²2p⁴

7 0
2 years ago
Read 2 more answers
How much heat must be removed from 25.0g of steam at 118.0C in order to form ice at 15C
NemiM [27]

Answer:

-10778.95 J heat must be removed in order to form the ice at 15 °C.

Explanation:

Given data:

mass of steam = 25 g

Initial temperature = 118 °C

Final temperature = 15 °C

Heat released = ?

Solution:

Formula:

q = m . c . ΔT

we know that specific heat of water is 4.186 J/g.°C

ΔT = final temperature - initial temperature

ΔT = 15 °C - 118 °C

ΔT = -103 °C

now we will put the values in formula

q = m . c . ΔT

q = 25 g × 4.186 J/g.°C × -103 °C

q = -10778.95 J

so, -10778.95 J heat must be removed in order to form the ice at 15 °C.

3 0
2 years ago
A saturated solution of potassium iodide contains, in each 100 mL, 100 g of potassium iodide. The solubility of potassium iodide
Oksanka [162]

Answer:

Specific gravity of the saturated solution is 2

Explanation:

The specific gravity is defined as the ratio between density of a solution (In this case, saturated solution of potassium iodide, KI) and the density of water. Assuming density of water is 1:

Specific gravity  = Density

The density is the ratio between the mass of the solution and its volume.

In 100mL of water, the mass of KI that can be dissolved is:

100mL * (1g KI / 0.7mL) = 143g of KI

That means all the 100g of KI are dissolved (Mass solute)

As the volume of water is 100mL, the mass is 100g (Mass solvent)

The mass of the solution is 100g + 100g = 200g

In a volume of 100mL, the density of the solution is:

200g / 100mL = 2g/mL.

The specific gravity has no units, that means specific gravity of the saturated solution is 2

5 0
1 year ago
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