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egoroff_w [7]
2 years ago
13

The volume of an air bubble at the bottom of a lake is 1.35 mL. If the pressure at the bottom of the lake is 125 kPa and the air

pressure at the top of the lake is 105 kPa, what will the volume of the bubble be when it rises to the surface?
Chemistry
1 answer:
nikitadnepr [17]2 years ago
8 0

Answer:

1.61 mL

Explanation:

Step 1:

Data obtained from the question. This includes the following:

Initial volume (V1) = 1.35 mL

Initial pressure (P1) = 125 kPa

Final pressure (P2) = 105 kPa

Final volume (V2) =..?

Step 2:

Determination of the volume of the air bubble at the surface of the lake.

This can be obtained by use the Boyle's law equation as follow:

P1V1 = P2V2

125 x 1.35 = 105 x V2

Divide both side by 105

V2 = (125 x 1.35)/105

V2 = 1.61 mL

Therefore, the volume of the air bubble at the surface of the lake is 1.61 mL

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Dr. Franck cuts a bar of pure gold into smaller and smaller pieces. Will this action change the element that makes up the bar? E
Anvisha [2.4K]

Answer:

i believe this is a chemical or physical question? well your answer to that is no the element does not change because the gold is still gold it is still physical because you have just cut it into piece it is still gold

Explanation:

lmk if it was helpful :/

7 0
2 years ago
mastering chem If the experiment below is run for 60 s, 0.16 mol A remain. Which of the following statements is or are true? At
Dvinal [7]

Answer: All of the statements are true.

Explanation:

(a) Considering the system mentioned in the equation:-

The sum of total moles in the flask will always be equal to 1 which leads to confirmation of this statement as for 60 secs= 0.16 mol A and 0.84 mol B

(b) 0<t< 20s,  mole A got reduced from 1 mole to 0.54 moles while at 40s to 60s A got decreased from 0.30 moles to 0.16 moles.

0 to 20s is 0.46 (1 - 0.54 = 0.46)mol whereas,

40 to 60s is 0.14 (0.30-.16 = 0.14) mol

(0.46 > 0.14) mol leading this statement to be true as well.

(c) Average rate from t1 = 40 to t2 = 60 s is given by:

\delta moles/\delta time  = 0.30-0.16/60-40 = 0.007 Mol/s which is true as well

7 0
2 years ago
Jill is doing an experiment on the movement of pill bugs. She will place the pill bugs on flat surfaces covered with diffirent m
Ostrovityanka [42]

Answer:D

Explanation:

6 0
2 years ago
Lithium has an atomic mass of 6.941 amu. Lithium has two common isotopes. The one isotope has a mass of 6.015 amu and a relative
koban [17]

Answer:

The atomic mass of second isotope is 7.016

Explanation:

Given data:

Average Atomic mass of lithium = 6.941 amu

Atomic mass of first isotope = 6.015 amu

Relative abundance of first isotope = 7.49%

Abundance of second isotope = ?

Atomic mass of other isotope = ?

Solution:

Total abundance = 100%

100 - 7.49 = 92.51%

percentage abundance of second isotope = 92.51%

Now we will calculate the mass if second isotope.

Average atomic mass of lithium = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass)  / 100

6.941 = (6.015×7.49)+(x×92.51) /100

6.941 =  45.05235 + (x92.51) / 100

6.941×100 = 45.05235 + (x92.51)

694.1 - 45.05235   = (x92.51)

649.04765 = x 92.51

x = 485.583 /92.51

x = 7.016

The atomic mass of second isotope is 7.016

3 0
2 years ago
Under identical conditions of temperature, number of moles, and pressure, which of the following gases has the highest density:
sergey [27]
<span>The higher the molar mass is of the gas, the greater the density.

Cl2 is the answer</span>
6 0
2 years ago
Read 2 more answers
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