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Serggg [28]
2 years ago
14

1. Calculate the molar enthalpy of solidification (ΔHsolidification) when 10.00kJ of energy are lost as 30.00g of water are froz

en at 0ºC. Remember that this value will be negative, because energy is lost when water freezes. (Hint: start by finding out how many moles of water that are freezing)
Chemistry
1 answer:
kompoz [17]2 years ago
3 0

Answer:

The snow gains heat to melt (endothermic), then the water releases heat to freeze (exothermic). ... Beaker becomes hot because the reaction is pushing heat out from itself onto .... solidification (ΔHsolidification) when 10.00kJ of energy are lost as 30.00g of water.

Explanation:

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An aluminum ion has a charge of +3, and an oxide has a charge of -2. What would be the product of a reaction between these two e
kozerog [31]

The product of a reaction between these two elements is Al_{2} O_{3}.

Explanation:

The oxidation state of an ion in a compound is equal to its charge.

The aluminum having a charge of +3 because oxidation state is +3

The oxide is having charge of -2

The product of these reactants will produce a chemical compound.

The compound formed is Al_{2} O_{3}  i.e Aluminium oxide. The compound while getting formed will share the charge and cation A+ will have the charge of anion and anion will have the charge of cation. This will result in a compound as there should be a neutral charge on the compound formed.

The <em>+</em><em>3 charge of the cation Al+ will go to anion oxide O2- and the charge of anion -2 will go with cation Al+. </em>

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2 years ago
Linda threw two stones, one in a horizontal direction and another one straight up. She observed that both stones fell back to th
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If 32.0 g of MgSO4⋅7H2O is thoroughly heated, what mass of anhydrous magnesium sulfate will remain?
Arada [10]
Find moles of MgSO4.7H2O

molar mass = 246
so moles  = 32 / 246  = 0.13 moles.

When heated, all 7 H2O from 1 molecule will be gone. 
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Complete combustion of a 0.600-g sample of a compound in a bomb calorimeter releases 24.0 kJ of heat. The bomb calorimeter has a
JulijaS [17]

Answer : The correct option is, 30.9^oC

Explanation :

Formula used :

q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})

where,

q = heat released = 24 KJ

m = mass of bomb calorimeter = 1.30 Kg

c = specific heat = 3.41J/g^oC

T_{final} = final temperature = ?

T_{initial} = initial temperature = 25.5^oC

Now put all the given values in the above formula, we get  the final temperature of the calorimeter.

q=m\times c\times (T_{final}-T_{initial})

24KJ=1.30Kg\times 3.41J/g^oC\times (T_{final}-25.5)^oC

T_{final}=30.9^oC

Therefore, the final temperature of the calorimeter is, 30.9^oC

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