All categories

1 year ago

A 0.12m solution of an acid that ionizes only slightly in solution would be termed _____.

2 answers:

5 0

A 0.12 M solution of an acid that only slightly ionizes in solution would be termed a weak acid. Weak acids are acids which do not completely dissociate in water. Thus lowering the presence of hydronium ions which measures the pH of an acid. <span />

Charra [1.4K]1 year ago

5 0

Explanation:

An acid is a specie that donates hydrogen ions, that is, $H^{+}$ ions.

When an acid gives or dissociates to produce more number of hydrogen ions then it is known as strong acid.

Whereas when an acid gives or dissociates to produce few or very less number of hydrogen ions then it is known as weak acid.

Therefore, when a 0.12m solution of an acid that ionizes only slightly in solution would be termed as weak acid because it is giving less number of hydrogen ions.

You might be interested in

Convert 1.71 × 1024 atoms of carbon to moles of carbon.

beks73 [17]

You need to use Avogadro's constant to convert from atoms of carbon to moles of carbon.

1.71*10^24 atoms C * (1 mole/6.022*10^23 atoms) = 2.84 moles of carbon

7 0

2 years ago

A substance has a density of 4.5gmL. What is this in kgL? Report your answer with two significant figures.

Ipatiy [6.2K]

Answer:

4.5 kg/L

Explanation:

Density is 4.5g/mL and it means that in 1 mL of volume, the mass contained is 4.5 g.

Let's make a rule of three

1L = 1000 mL

1 mL has a mass of 4.5 g

1000 mL would have 4500 g

Our new density would be 4500 g/L, but we may convert the g to kg

1 kg / 1000 g . 4500 g = 4.5 kg

In conclusion 4.5 g/mL = 4.5 kg/L

7 0

2 years ago

Los automóviles actuales tienen “parachoques de 5 mi/h (8 km/h)” diseñados para comprimirse y rebotar elásticamente sin ningún d

PilotLPTM [1.2K]

Answer:

k = 23045 N/m

Explanation:

To find the spring constant, you take into account the maximum elastic potential energy that the spring can support. The kinetic energy of the car must be, at least, equal to elastic potential energy of the spring when it is compressed to its limit. Then, you have:

$K=U\\\\\frac{1}{2}Mv^2=\frac{1}{2}kx^2$ (1)

M: mass of the car = 1050 kg

k: spring constant = ?

v: velocity of the car = 8 km/h

x: maximum compression of the spring = 1.5 cm = 0.015m

You solve the equation (1) for k. But first you convert the velocity v to m/s:

$v=8\frac{km}{h}*\frac{1000m}{1km}*\frac{1h}{3600s}=2.222\frac{m}{s}$

$k=\frac{Mv^2}{x^2}=\frac{(1050kg)(2.222m/s)^2}{(0.015m)^2}=23045\frac{N}{m}$

The spring constant is 23045 N/m

3 0

1 year ago

Standard Thermodynamic Quantities for Selected Substances at 25 ∘C Reactant or product ΔHf∘(kJ/mol) Al(s) 0.0 MnO2(s) −520.0 Al2

Svet_ta [14]

Answer:

-1815.4 kJ/mol

Explanation:

Starting with standard enthalpies of formation you can calculate the standard enthalpy for the reaction doing this simple calculation:

∑ n *ΔH formation (products) - ∑ n *ΔH formation (reagents)

This is possible because enthalpy is state function meaning it only deppends on the initial and final state of the system (That's why is also possible to "mix" reactions with Hess Law to determine the enthalpy of a new reaction). Also the enthalpy of formation is the heat required to form the compound from pure elements, then products are just atoms of reagents organized in a different form.

In this case:

ΔH rxn = [(2 * -1675.7) - (3 * -520.0)] kJ/mol = -1815.4 kJ/mol

4 0

2 years ago

How much energy is required to decompose 612 g of pcl3, according to the reaction below? the molar mass of pcl3 is 137.32 g/mol

Assoli18 [71]

The reaction is:

4 PCl3 (g) ---> P4(s) + 6 Cl2(g).

Now, you need to convert the mass of PCl3 into number of moles, for which you use the molar mass of PCl3 in this way:

number of moles = number of grams / molar mass =>

number of moles of PCl3 = 612 g / 137.32 g/mol = 4.4567 moles of PCl3.

Now use the proportion with the ΔH rxn given.

4 mol PCl3 / 1207 kJ = 4.4567 mol / x => x = 4.4567 mol * 1207 kJ / 4 mol = 1,344.8 kJ = 1.34 * 10^3 kJ.

Answer: 1.34 * 10 ^3 kJ (option d)

8 0

2 years ago

Read 2 more answers