Answer:
The Moon weighs about 7.349*10^22 kg
How much does “an elephant” weigh? Grown-up elephants vary between 1.7 tons (small wood elephant cow) and 6 tons (big African elephant bull). Let us pick 2.720 tons or 2720 kg as an average weigh one, this is valid for Asian elephants.
A mole of elephants weighs 6.022 * 10^23 x 2720 kg = 1.638 * 10^27 kg.
That is 1,638 * 10^27 / 7,349*10^22 = 22289 times more.
The answer to this question is "carrying capacity." The term "growth
rate," refers to how fast a population grows, and the term "population
density," refers to the number of organisms located within a specific
area. Carrying capacity is correct because is directly addresses the
maximum number of organisms that an ecosystem can handle, as opposed to
how fast they are growing or how many there currently are.
Answer: 8.12 g NaCl
Explanation: Use Avogadro's number to find the number of m
moles of NaCl:
8.24x10²² molecules NaCl / 1 mole NaCl/ 6.022x10²³ molecules NaCl
= 0.14 mole NaCl
Next convert moles to grams NaCl using its molar mass;
0.14 mole NaCl x 58g NaCl / 1 mole NaCl
= 8.12 g NaCl
Answer:
The answer to your question is: C₁₈ H₂₇ N O₃
Explanation:
Data
Carbon = 70.79 g
Hydrogen = 8.91 g
Nitrogen = 4.58 g
Oxygen = 15.72 g
Process
AT C = 12 g
AT H = 1 g
AT N = 14 g
AT O = 16 g
Carbon
12 g ------------------------ 1 mol
70.79 g ------------------------- x
x = (70.79 x 1) / 12
x = 5.9 mol of C
Hydrogen
1 g ----------------------- 1 mol
8.91 g --------------------- x
x = (8.91 x 1) / 1
x = 8.91 mol of H
Nitrogen
14 g ---------------------- 1 mol
4.58 g ------------------- x
x = (4.58 x 1) / 14
x = 0.33 mol
Oxygen
16 g ------------------------ 1 mol
15.72 g -------------------- x
x = (15.72 x 1)/16
x = 0.98
Divide by the lowest number of moles
Carbon 5.9 / 0.33 = 17.9 ≈ 18
Hydrogen 8.91 / 0.33 = 27
Nitrogen 0.33 / 0.33 = 1
Oxygen 0.98 / 0.33 = 2.9 ≈ 3
C₁₈ H₂₇ N O₃
Answer: The concentration of the reactants and products remain constant!
Explanation: <em>remember that </em><em>a dynamic equilibrium is a state of balance in which the rates of the forward and reverse reactions are equal,</em><em> and they continue to occur at an equivalent and constant rate with the same amount of product and reactants!</em>
