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Gemiola [76]
2 years ago
14

You are given 100.0 ml of a 2.0 M solution of KOH. What would be the molarity of the solution if it is diluted to a volume of 10

00 ml?
Chemistry
1 answer:
Lostsunrise [7]2 years ago
8 0

Answer:

0.2M

Explanation:

Data obtained from the question include:

C1 = 2.0 M

V1 = 100mL

V2 = 1000mL

C2 =?

Using the dilution formula C1V1 = C2V2, the molarity of the diluted solution can be obtained as follows:

C1V1 = C2V2

2 x 100 = C2 x 1000

Divide both side by the 1000

C2 = (2 x 100) / 1000

C2 = 0.2M

The molarity of the diluted solution is 0.2M

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Bismuth(III) sulfate is an ionic compound formed from Bi3+ and SO42-. What is the correct way to represent the formula?
Hitman42 [59]

Answer:

Bi2(SO4)3

Explanation:

Bismuth(iii) sulfate is an ionic compound therefore, their is transfer of electron. Ionic compound has both cations and anions. The cations is positively charged ion while the anions is negatively charged ions. The cations loses electron to become positively charged while the anions gains electron to become negatively charged.

From the compound above, Bismuth(iii) sulfate the cations will be Bismuth ion which loses 3 electrons. The anions is the sulfate ion (S04)2- with a -2 charge.

The chemical formula can be computed from the charge configuration as follows

Bi3+  and (SO4)2-

cross multiply the charges living the sign behind to get the chemical formula

Bi2(SO4)3

Note the final chemical formula, the numbers are sub scripted

4 0
2 years ago
You are trying to make balloon sculptures. You twist the balloons gently, but they keep popping. Besides trimming your nails, ho
Maurinko [17]

Answer:

              By decreasing pressure.

Explanation:

                      In order to prevent balloons from popping while making sculptures, it is suggested to decrease the pressure of air in parent  balloon. Decreasing the pressure of parent balloon will allow it to twist easily and make designs.

This strategy will work according to Boyle's Law which states that, "Pressure and Volume are inversely proportional to each  other at constant temperature".

Mathematically,

                                       P ∝ 1/V

Or,

                                       P = k/V

Or,

                                       PV = k

Hence, as the new designs made after twisting are of less volume, therefore it is good to decrease the pressure in advance otherwise the resulting less volume will increase the pressure of daughter small balloons  and will explode them.

7 0
2 years ago
Read 2 more answers
An unknown solution has a pH of 8. How would you classify this solution?
ratelena [41]
The correct answer is B) Basic. Hope this helps.
6 0
2 years ago
Read 2 more answers
mastering chem If the experiment below is run for 60 s, 0.16 mol A remain. Which of the following statements is or are true? At
Dvinal [7]

Answer: All of the statements are true.

Explanation:

(a) Considering the system mentioned in the equation:-

The sum of total moles in the flask will always be equal to 1 which leads to confirmation of this statement as for 60 secs= 0.16 mol A and 0.84 mol B

(b) 0<t< 20s,  mole A got reduced from 1 mole to 0.54 moles while at 40s to 60s A got decreased from 0.30 moles to 0.16 moles.

0 to 20s is 0.46 (1 - 0.54 = 0.46)mol whereas,

40 to 60s is 0.14 (0.30-.16 = 0.14) mol

(0.46 > 0.14) mol leading this statement to be true as well.

(c) Average rate from t1 = 40 to t2 = 60 s is given by:

\delta moles/\delta time  = 0.30-0.16/60-40 = 0.007 Mol/s which is true as well

7 0
2 years ago
Determine the molar mass of freon–11 gas if a sample weighing 0.597 g occupies 100. cm3 at 95°c, and 1,000. mmhg (r = 0.08206 l
Stells [14]
We can first find the number of moles using the ideal gas law equation,
PV = nrT
where P - pressure - 1000 mmHg / 760 mmHg/atm = 1.32 atm 
V - volume -  100 x 10⁻³ L
n - number of moles 
r - universal gas constant - 0.08206 LatmK⁻¹mol⁻¹
T - temperature in Kelvin - 95 °C + 273 = 368 K
substituting these values 
1.32 atm x 100 x 10⁻³ L = n x 0.08206 LatmK⁻¹mol⁻¹ x 368 K
n = 0.00437 mol

molar mass can be determined as follows
molar mass = mass present / number of moles 
molar mass = 0.597 g / 0.00437 mol = 136.6 g/mol
molar mass of gas is 137 g/mol
5 0
2 years ago
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