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Sati [7]
2 years ago
6

in collecting the precipitate, why would it be inappropriate to heat the reacted mixture and evaporate off the water?

Chemistry
1 answer:
djverab [1.8K]2 years ago
6 0
In collecting the precipitate, it is inappropriate to heat <span>the reacted mixture and evaporate off the water because it is possible that the mixture contains other substances that precipitates as well when the mixture is being heated so you will not be able to collect what you want.</span>
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You try to measure out exactly 5.0 milliliters of water by eye into each of five test tubes. When you go back to check the volum
jeka94

Answer:

The volumes are both, accurate and precise.

Explanation:

In the measurement of a set, precision refers to how much coincidence exists in the measurements of an specific value, as the measurements are close, we can say the volumes are precise.

Accuracy means the agreement that exists between the average of one

large series of measurements and the value of  measurement

Media is 4,96 ml and I wanted to measure 5 ml. It is also close.

6 0
2 years ago
Be sure to answer all parts. liquid ammonia autoionizes like water: 2nh3(l) → nh4+(am) + nh2−(am) where (am) represents solvatio
Genrish500 [490]
Answer is: concentration of ammonium ions are 7,14·10⁻¹⁴ M.
Chemical reaction: 2NH₃(l) → NH₄⁺(am) + NH₂⁻(am).
Kam = 5,1·10⁻²⁷.
[NH₄⁺] · [NH₂⁻] = x; equilibrium concentration of cations and anions.
Kam = [NH₄⁺] · [NH₂⁻].
Kam = x².
x = [NH₄⁺] = √5,1·10⁻²⁷.
[NH₄⁺] = 7,14·10⁻¹⁴ M.

5 0
2 years ago
4. a student is shown a Diagram which shows gas bubbles being made by water plant that has been exposed to light. which gas is m
lisov135 [29]
Carbon dioxide is in the bubbles
5 0
2 years ago
Determine the equilibrium constant, keq, at 25°c for the reaction 2br– (aq) + i2(s) br2(l) + 2i– (aq).
Travka [436]
Electrochemical cell representation for above reaction is,

Br-/Br2//I2/I-

Reaction at Anode: Br2 + 2e-   →    2Br-               (1)
Reaction at Cathode: 2I-            →  I2   + 2e-          (2)

Standard reduction potential for Reaction 1 =  Ered(anode) = 1.066 v
Standard reduction potential for Reaction 2 = Ered(cathode) = 0.535 v

Eo cell = Ered(cathode)  -  Ered(anode)
            = 0.535 - 1.066
            = -0.531v

Now, we know that ΔGo = -nF (Eo cell)        ..............(3)
Also, ΔGo = RTln(K)         ..........(4)

Equation 3 and 4 we get,

ln (K)   = nF (Eo cell)  / RT
           = 2 X 96500 X (-0.531)/ (8.314 X 298)

∴ K = 1.085 X 10^-18.


5 0
2 years ago
For which applications would you choose a liquid over a gas or solid?
DedPeter [7]

Answer:

Washing Clothes & Dissolving Sugar

Explanation:

Think about each application:

1) Washing clothes: You kind of need water to do this, or not much washing can be done.

2) Linking brake pedals to the brake pads: You don't need any liquids for this. You need solids.

3) Deodorizing a room: You would problem choose an aerosol, which is sprayed, thus a gas.

4) Carving a sculpture: You would use solid tool and a sold sculpture.

5) Dissolving sugar: You need a liquid to dissolve sugar!

6) Painting a wall: Perhaps, you COULD say that the paint is a liquid... but I'm not sure if that really counts. I believe this application would still be solids.

7) A gear for a machine is a solid!

5 0
2 years ago
Read 2 more answers
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