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Troyanec [42]
1 year ago
9

Determine the molar mass of freon–11 gas if a sample weighing 0.597 g occupies 100. cm3 at 95°c, and 1,000. mmhg (r = 0.08206 l

• atm/k • mol, 1 atm = 760 mmhg).
Chemistry
1 answer:
Stells [14]1 year ago
5 0
We can first find the number of moles using the ideal gas law equation,
PV = nrT
where P - pressure - 1000 mmHg / 760 mmHg/atm = 1.32 atm 
V - volume -  100 x 10⁻³ L
n - number of moles 
r - universal gas constant - 0.08206 LatmK⁻¹mol⁻¹
T - temperature in Kelvin - 95 °C + 273 = 368 K
substituting these values 
1.32 atm x 100 x 10⁻³ L = n x 0.08206 LatmK⁻¹mol⁻¹ x 368 K
n = 0.00437 mol

molar mass can be determined as follows
molar mass = mass present / number of moles 
molar mass = 0.597 g / 0.00437 mol = 136.6 g/mol
molar mass of gas is 137 g/mol
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Explanation :

To calculate the temperature of gas we are using ideal gas equation:

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where,

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Conversion used : (1 atm = 760 torr)

V = volume of gas = 88.84 L

T = temperature of gas = ?

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w = mass of gas = 609.64 g

M = molar mass of F_2 gas = 38 g/mole

Now put all the given values in the ideal gas equation, we get:

(3.646atm)\times (88.84L)=\frac{609.64g}{38g/mole}\times (0.0821L.atm/mole.K)\times (T)

T=245.9K

Therefore, the temperature of the gas is, 245.9 K

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How many molecules of CBr4 are in 250 grams of CBr4
Kazeer [188]

Answer:- 4.54*10^2^3 molecules.

Solution:- The grams of tetrabromomethane are given and it asks to calculate the number of molecules.

It is a two step unit conversion problem. In the first step, grams are converted to moles on dividing the grams by molar mass.

In second step, the moles are converted to molecules on multiplying by Avogadro number.

Molar mass of CBr_4  = 12+4(79.9)  = 331.6 g per mol

let's make the set up using dimensional analysis:

250g(\frac{1mol}{331.6g})(\frac{6.022*10^2^3molecules}{1mol})

= 4.54*10^2^3 molecules

So, there will be 4.54*10^2^3 molecules in 250 grams of CBr_4 .


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Keith_Richards [23]

Answer:

\°C=5.8x10^3\°C

\°F=1.1x10^4\°F

Explanation:

Hello,

In this case, for the calculation of the temperature in degree Celsius we subtract 273.15 to the given temperature in kelvins:

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Next, by applying the following equation we compute it in degree Fahrenheit:

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Clearly, since the initial unit has two significant figures the computed units also show two significant figures.

Regards.

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2 years ago
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