Explanation:
It is known that 1 gram contains 1000 milligrams. And, mathematically we can represent it as follows.
or
So, when we have to convert grams into milligrams then we simply multiply the digit with 1000. And, if we have to convert a digit from milligrams to grams then we simply divide it by 1000.
<u>Answer:</u>
<u>For a:</u> Lead iodide is a yellow precipitate.
<u>For b:</u> Barium sulfate is a white precipitate.
<u>For c:</u> Ferric hydroxide is a brown precipitate.
<u>For d:</u> Copper (II) hydroxide is a blue precipitate.
<u>Explanation:</u>
Precipitation reaction is defined as the reaction where a solid precipitate (solid substance) is formed at the end of the reaction. It is insoluble in water.
For the given options:
The chemical reaction between KI and lead (II) nitrate follows:
The iodide of lead is generally insoluble in water. Thus, lead iodide is a yellow precipitate.
The chemical reaction between barium chloride and sulfuric acid follows:
The sulfate of barium is insoluble in water. Thus, barium sulfate is a white precipitate.
The chemical reaction between NaOH and ferric chloride follows:
The hydroxide of iron is insoluble in water. Thus, ferric hydroxide is a brown precipitate.
The chemical reaction between NaOH and copper sulfate follows:
The hydroxide of copper is insoluble in water. Thus, copper (II) hydroxide is a blue precipitate.
Answer : the correct answer for ksp = 1.59 * 10⁻⁹
Following are the steps to calculate the ksp of reaction
BaCO₃ →Ba ²⁺ + CO₃²⁻ :
Step 1 : To find ΔG° of reaction :
ΔG° of reaction can be calculates by taking difference between ΔG° of products and reactants as :
ΔG° reaction =Sum of ΔG° ( products ) - Sum of Δ G° ( reactants ) .
Given : ΔG° for Ba²⁺ ( product )= -560.7
ΔG° for CO₃²⁻ (product ) =- 528.1
ΔG° BaCO₃ ( reactant) = –1139
Plugging value in formula :
ΔG° for reaction = ( ΔG° of Ba ²⁺ + ΔG° of CO₃²⁻ ) - (ΔG° of BaCO₃ )
⁻ = ( -560.7 + 528.1
) - ( -1139
)
= ( -1088.8 ) - (-1139
)
= - 1088.8 + 1139
ΔG° of reaction = 50.2
Step 2: To calculate ksp from ΔG° of reaction .
The relation between Ksp and ΔG° is given as :
ΔG° = -RT ln ksp
Where ΔG° = Gibb's Free energy R = gas constant T = Temperature
Ksp = Solubility constant product .
Given : ΔG° of reaction = 50.2
T = 298 K R = 8.314
Plugging values in formula
((Converting 2477
Since , 1 KJ = 1000 J So , ))
Dividing both side by
ln ksp =
Removing ln :
ksp = 1. 59 * 10⁻⁹