Given:
7.20 g sample of Al2(SO4)3
Required:
Mass of oxygen
Solution:
Since you are not given a
chemical reaction, just base your solution to the chemical formula given.
Molar mass of Al2(SO4)3 = 342.15 g/mol
7.20 g Al2(SO4)3 (1 mol/342.15g)(3mol O/2 mol Al)(1 mol O2/1/2 mol
O2)(32g O2/1mol O2) = 4.04 g O2
Answer:
−2399.33 kJ
Explanation:
If NH₄NO₃ reacts with fuel oil to give a ΔH of -7198 for every 3 moles of NH₄NO₃
What is the enthalpy change for 1.0 mole of NH₄NO₃ in this reaction
∴ For every 1 mole, we will have
of the total enthaply of the 3 moles
so, to determine the 1 mole; we have:

= −2399.33 kJ
∴ the enthalpy change for 1.0 mole of NH₄NO₃ in this reaction = −2399.33 kJ
Al(s) + 2AgNO3(aq) = Al(NO3)3(aq) + 3 Ag (s)
is a single replacement reaction
A single replacement reaction is a type of chemical reaction were element react with a compound and the element take place of another element in that compound. In the reaction above Aluminium (Al) take the place of silver (Ag) from it compound.that is AgNO3. single replacement reaction is possible because aluminium is in high in reactivity series as compared to silver.
Answer:
Option A. 1 0n
Explanation:
Details on how to balanced the equation for the reaction given in the question above can be found in the attached photo.
Answer: 0.635 M
Explanation:
Molarity : It is defined as the number of moles of solute present per liter of the solution.
Formula used :

where,
n= Moles=
= volume of solution = 150 ml


as 1 mole of
gives 3 moles of
ions
Thus molarity of
= 
Molarity of
= 0.635 M