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xz_007 [3.2K]
2 years ago
12

The volume of a gas at 99.6 kPa and 24°C is 4.23 L. What volume will it occupy at 93.3 kPa ?

Chemistry
1 answer:
yuradex [85]2 years ago
6 0

The volume is increased to 4.52 L on decreasing the pressure to 93.3 kPa.

Explanation:

As per Boyle's law, the volume occupied by gas particles will be inversely proportional to the pressure experienced by those particles at constant temperature.

V=\frac{1}{P}

So in the present problem, the volume of gas at pressure P₁ = 99.6 kPa is given as V₁ = 4.23 L. The temperature is kept constant at 24°C. Then, if the pressure is decreased to 93.3 kPa, then the volume is tend to increase due to Boyle's law.

So let us consider the new pressure be P₂ = 93.3 kPa and the new volume has to be found.

Then using Boyle's law, P_{1} V_{1} = P_{2}  V_{2}

Then, V_{2}=\frac{P_{1} V_{1} }{P_{2} }

So, V_{2}=\frac{99.6*1000*4.23}{93.3*1000}=4.52 L

Thus, the volume is increased to 4.52 L on decreasing the pressure to 93.3 kPa.

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Calculate δg o for each reaction using δg of values:(a) h2(g) + i2(s) → 2hi(g) kj (b) mno2(s) + 2co(g) → mn(s) + 2co2(g) kj (c)
steposvetlana [31]
Part (a) :
H₂(g) + I₂(s) → 2 HI(g)
From given table:
G HI = + 1.3 kJ/mol
G H₂ = 0
G I₂ = 0
ΔG = G(products) - G(reactants) = 2 (1.3) = 2.6 kJ/mol

Part (b):
MnO₂(s) + 2 CO(g) → Mn(s) + 2 CO₂(g)
G MnO₂ = - 465.2
G CO = -137.16
G CO₂ = - 394.39
G Mn = 0
ΔG = G(products) - G(reactants) = (1(0) + 2*-394.39) - (-465.2 + 2*-137.16) = - 49.3 kJ/mol

Part (c):
NH₄Cl(s) → NH₃(g) + HCl(g)
ΔG = ΔH - T ΔS
ΔG = (H(products) - H(reactants)) - 298 * (S(products) - S(reactants))
      = (-92.31 - 45.94) - (-314.4) - (298 k) * (192.3 + 186.8 - 94.6) J/K
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6 0
2 years ago
Read 2 more answers
A brick has dimensions of 15 cm by 6.0 CM by 12 CM what is the volume of the brick in cubic meters
VLD [36.1K]

 The  volume   of  the brick  in cubic   meters  is 0.00108 m³


 <u><em>calculation</em></u>

<u><em> </em></u> volume of a brick  =length  x  width   x  height

-length = 15 cm

width = 6.0 cm

height = 12 cm

volume is therefore= 15 cm x 6.0 cm   x 12 cm =1080 cm³

convert  1080 cm³ into m³


that  is  1 cm³  =  1  x 10^-6m³

        1080  cm³ = ? m³

by cross multiplication

=[ (1080 cm³  x 1 x10^-6 m³)  /  1 cm³]  =  0.00108 m³

7 0
2 years ago
Enough water is added to 50.0 mL of a 0.660 M NaOH solution in order to bring the total volume to 450.0 mL. What is the molarity
g100num [7]

Answer:

0.073 M

Explanation:

M1*V1 = M2*V2

M1 = 0.660 M

V1 = 50.0 mL

V2 = 450.0 mL

0.660M * 50.0 mL = M2*450.0 mL

M2 = 0.660M*50.0/450.0 = 0.073 M

5 0
2 years ago
Magnesium oxide decomposes into magnesium and oxygen. if 12.09 g of magnesium oxide decomposes to form 7.29 g of magnesium, what
Vlada [557]
 the mass of oxy gas would be 4.03 did i calculate that right?
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2 years ago
Select all statements that correctly describe hemoglobin and myoglobin structure. a. Molecular oxygen binds irreversibly to the
DIA [1.3K]

Answer:

c. By itself, heme is not a good oxygen carrier. It must be part of a larger protein to prevent oxidation of the iron.

e. Both hemoglobin and myoglobin contain a prosthetic group called heme, which contains a central iron ( Fe ) (Fe) atom.

f. Hemoglobin is a heterotetramer, whereas myoglobin is a monomer. The heme prosthetic group is entirely buried within myoglobin.

Explanation:

The differences between hemoglobin and myoglobin are most important at the level of quaternary structure. Hemoglobin is a tetramer composed of two each of two types of closely related subunits, alpha and beta. Myoglobin is a monomer (so it doesn't have a quaternary structure at all). Myoglobin binds oxygen more tightly than does hemoglobin. This difference in binding energy reflects the movement of oxygen from the bloodstream to the cells, from hemoglobin to myoglobin.

Myoglobin binds oxygen

The binding of O 2 to myoglobin is a simple equilibrium reaction:

7 0
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