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iVinArrow [24]
2 years ago
14

If water’s density is 1.0 g/mL, then would the perfume be more or less dense than water? Would the perfume float on top or sink

to the bottom of the water?
Help me out rq!!!!!
Chemistry
1 answer:
Alex17521 [72]2 years ago
5 0

Answer:

usually the perfumes are made of aromatic hydrocarbons invloving

cetone, ethanol, benzaldehyde, formaldehyde, limonene, methylene chloride, camphor, ethyl acetate, linalool and benzyl alcohol. which have density lower than the water hence they will float on the top of the water.

Hope this helps you

Explanation:

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How many acidic protons are there in 0.6137 g of KHP?
andreyandreev [35.5K]

0.6137 g of KHP contains 1.086 × 10^21 acidic protons.

Number of moles of KHP = mass of KHP/molar mass of KHP

Molar mass of KHP = 204.22 g/mol

Mass of KHP = 0.6137 g

Number of moles of KHP = 0.6137 g/204.22 g/mol = 0.003 moles of KHP

Now,  1 each molecule of KHP contains 1 acidic proton.

For 0.003 moles of KHP there are; 0.003 × 1 × NA

Where NA is Avogadro's number.

So;  0.003 moles of KHP contains 0.003 × 1 × 6.02 × 10^23

= 1.086 × 10^21 acidic protons.

Learn more: brainly.com/question/16672114

7 0
1 year ago
A hot gas flowing through a pipeline can be considered as a:________
k0ka [10]

Answer:

B) irreversible process

Explanation:

The process given here is irreversible.

7 0
2 years ago
USATEST PREP QUESTION HELP ! Really appreciate it !
Novosadov [1.4K]

Answer is A Access pictures of the area taken by satelites.

Explanation: Satelites are the only thing out of these four answers that does not requir power supply from the town. Hope it helped!

5 0
2 years ago
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A compound composed of only c and f contains 17.39 c by mass. what is its empirical formula
Ostrovityanka [42]

Since the Carbon C is 17.39% by mass hence the Fluorine F is 82.61% by mass. Divide each mass % by the respective molar masses, that is:

 

C = 17.39 / 12 = 1.45

F = 82.61 / 19 = 4.35

 

Divide the two by the smaller number, so divide by 1.45

 

C = 1.45 / 1.45 = 1

F = 4.35 / 1.45 = 3

 

So the empirical formula is:

CF3 

4 0
2 years ago
Which of the following statements is not true of the combustion of an organic compound?
Novay_Z [31]

<em>The following statements are not true of the combustion of an organic compound is </em>

<em>C. it can also be described as a synthesis reaction </em>

<h3><em>Further explanation</em></h3>

Organic compounds have a characteristic that there is a chain of carbon atoms, while in inorganic does not have a chain of carbon atoms

The reaction of a substance with oxygen is called a combustion reaction

Perfect combustion of carbon compounds will get CO2 gas, whereas if it is not perfect it will produce CO gas

Identification of carbon compounds can usually be done by flowing it into lime water which produces turbid water because of the reaction of CO2 with Ca(OH)₂ to form CaCO₃

Burning organic samples will convert C atoms to CO₂ and H to H₂O

We see the answer choices

1. Oxygen is included in the reactants in the combustion process

So the  answer is correct

2. Energy is released during combustion because the reaction is exothermic or releases heat with a negative enthalpy of combustion

So the  answer is correct

3. A decomposition reaction is the decomposition reaction of a compound into its constituent elements. In combustion reactions, occur decomposition, not a formation reaction

So the  answer is wrong

4. CO₂ is the result of combustion,

So the  answer is correct

<h3><em>Learn more</em></h3>

properties of hydrocarbons brainly.com/question/4619751

<h3><em>Answer details </em></h3>

Grade: Senior High School

Subject: Chemistry

Chapter: Hydrocarbons

Keywords: combustion, organic, inorganic, a carbon chain

7 0
2 years ago
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