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2 years ago

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Calculate the internal energy of 2 moles of argon gas (assuming ideal behavior) at 298 K. Suggest two ways to increase its inter

nal energy by 10 J.

1 answer:

Dominik [7]2 years ago

5 0

I hope this helps you.

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(2 pts) The solubility of InF3 is 4.0 x 10-2 g/100 mL. a) What is the Ksp? Include the chemical equation and Ksp expression. MW

Aleonysh [2.5K]

Answer:

a) Ksp = 7.9x10⁻¹⁰

b) Solubility is 6.31x10⁻⁶M

Explanation:

a) InF₃ in water produce:

InF₃ ⇄ In⁺³ + 3F⁻

And Ksp is defined as:

Ksp = [In⁺³] [F⁻]³

4.0x10⁻²g / 100mL of InF₃ are:

4.0x10⁻²g / 100mL ₓ (1mol / 172g) ₓ (100mL / 0.1L) = <em>2.3x10⁻³M InF₃. </em>Thus:

[In⁺³] = 2.3x10⁻³M InF₃ × (1 mol In⁺³ / mol InF₃) = 2.3x10⁻³M In⁺³

[F⁻] = 2.3x10⁻³M InF₃ × (3 mol F⁻ / mol InF₃) = 7.0x10⁻³M F⁻

Replacing these values in Ksp formula:

Ksp = [2.3x10⁻³M In⁺³] × [7.0x10⁻³M F⁻]³ = <em>7.9x10⁻¹⁰</em>

<em></em>

b) 0.05 moles of F⁻ produce solubility of InF₃ decrease to:

7.9x10⁻¹⁰ = [x] [0.05 + 3x]³

Where x are moles of In⁺³ produced from solid InF₃ and 3x are moles of F⁻ produced from the same source. That means x is solubility in mol / L

Solving from x:

x = -0.018 → False solution, there is no negative concentrations.

x = 6.31x10⁻⁶M → Right answer.

Thus, <em>solubility is 6.31x10⁻⁶M</em>

3 0

2 years ago

Determine the empirical formula of a compound containing 47.37 grams of carbon, 10.59 grams of hydrogen, and 42.04 grams of oxyg

Svetlanka [38]

Answer:

any more info?

Explanation:

3 0

1 year ago

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Sam buys a package of chips and notices that hydrogenated vegetables oil is one of the ingredients. This ingredient primarily:

Vladimir [108]

Hydrogenated vegetable oil is a preservative, thus, the correct option is D. Hydrogenated vegetable oil are used by food industries to prevent fat rancidity in order to give their product a longer shelf life. Hydrogenated oils are very good preservatives because all the enzymatic activities in the oil has been neutralized during the hydrogenating process.

6 0

2 years ago

The incomplete table below shows selected characteristics of gas laws.

Elenna [48]

Explanation :

In the given case different law related to gas is given. The attached figure shows the required solution.

Boyle's law states that the pressure is inversely proportional to the volume of the gas i.e.

$P\propto \dfrac{1}{V}$

$PV=k$

k is a constant.

Charle's law states that the volume of directly proportional to the temperature of the gas.

$V\propto T$

$V=kT$

Combined gas law is the combination of the pressure, volume and the temperature of the gas i.e.

$\dfrac{PV}{T}=k$

Hence, this is the required solution.

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2 years ago

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**PLATO QUESTION, PLEASE ANSWER CORRECTLY**

Ivenika [448]

The corect answers will be:
1) A
2) B
3) D

Hope this helped :)

7 0

2 years ago