Answer:
333.7 g.
Explanation:
- The depression in freezing point of water (ΔTf) due to adding a solute to it is given by: <em>ΔTf = Kf.m.</em>
Where, ΔTf is the depression in water freezing point (ΔTf = 20.0°C).
Kf is the molal freezing point depression constant of the solvent (Kf = 1.86 °C/m).
m is the molality of the solution.
<em>∴ m = ΔTf/Kf</em> = (20.0°C)/(1.86 °C/m) = <em>10.75 m.</em>
molaity (m) is the no. of moles of solute per kg of the solvent.
∵ m = (no. of moles of antifreeze C₂H₄(OH)₂)/(mass of water (kg))
∴ no. of moles of antifreeze C₂H₄(OH)₂ = (m)(mass of water (kg)) = (10.75 m)(0.5 kg) = 5.376 mol.
∵ no. of moles = mass/molar mass.
<em>∴ mass of antifreeze C₂H₄(OH)₂ = no. of moles x molar mass </em>= (5.376 mol)(62.07 g/mol) =<em> 333.7 g.</em>
It would go B. A. E. D. C.
Hope I helped!
<span>When atoms lose or gain electrons in chemical reactions they form?
</span>Ions
Answer : 
Explanation : To convert amu i.e. atomic mass unit in grams we have the conversion factor as 1 amu = 
we know the mass of the proton is 1.0073 amu
So converting it into grams we have to multiply;
1.0073 amu X 
= 
Now, Volume = 1/6πd³ as diameter is given as 
converting it to cm will require to multiply with 100
∴ Volume = 1/6π 
Hence, volume = 
Therefore, Density = mass / volume
∴ Density = 
Therefore, Density will be .
