A substance is followed by the symbol (1) in a chemical equation. What does the symbol represent?

Jeff wants to find the volume of a gas in a cylinder. He knows that at 28°C and a pressure of 1 atm, the volume of the gas was 6

emmasim [6.3K]

Answer:

by using ideal gas law

Explanation:

ideal gas law:

PV=nRT

where:

P is pressure measured in Pascal (pa)

V is volume measured in letters (L)

n is number of moles

R is ideal gas constant

T is temperature measured in Kelvin (K)

by applying the given:

P(initial) V(initial)=nRT(initial)

P(final) V(final)=nRT(final)

nR is constant in both equations since same gas

then,

P(initial) V(initial) / T(initial) = P(final) V(final) / T(final)

then by crossing multiply both equations

V (final)= { (P(initial) V(initial) / T(initial)) T(final) } /P (final)

P(initial)=P(final)= 1 atm = 101325 pa

V(initial)= 6 L

T(initial) = 28°c = 28+273 kelvin

T(final) = 39°c = 39+273 kelvin

by substitution

V(final) = 6.21926 L

6 0

1 year ago

Read 2 more answers

Approximately ____ days have passed when 20% of Cobalt (Co) remains? A) 19 B) 20 C) 21 D) 29

Brums [2.3K]

The answer to this is A i think.

3 0

1 year ago

12. Penny can knit 4 rows of a sweater in 5

Evgesh-ka [11]

Answer:

6.25 hours

Explanation:

From the question;

Penny can knit 4 rows in 5 minutes

We need to determine the time it will take for her to knit 300 rows

4 rows = 5 minutes

300 rows = ?

= (300 × 5 ) ÷ 4

= 375 minutes

But, 1 hour = 60 minutes

Therefore;

= 375 ÷ 60

= 6.25 hours

Thus, it will take penny 6.25 hours to knit 300 rows

8 0

1 year ago

What is the value of ΔGo in kJ at 25 oC for the reaction between the pair: Mn(s) and Ag+(aq) to give Ag(s) and Mn2+(aq) Use the

Leni [432]

Answer: $-3.8\times 10^{5}J$

Explanation:

$Mn+2Ag^{+}\rightarrow Mn^{2+}+2Ag$

Here Mn undergoes oxidation by loss of electrons, thus act as anode. silver undergoes reduction by gain of electrons and thus act as cathode.

$E^0=E^0_{cathode}- E^0_{anode}$

Where both $E^0$ are standard reduction potentials.

$E^0_{[Mn^{2+}/Mn]}= -1.18V$

$E^0_{[Ag^{2+}/Ag]}=+0.80V$

$E^0=E^0_{[Ag^{+}/Ag]}- E^0_{[Mn^{2+}/Mn]}$

$E^0=+0.80- (-1.18V)=1.98V$

The standard emf of a cell is related to Gibbs free energy by following relation:

$\Delta G^0=-nFE^0$

$\Delta G^0$ = gibbs free energy

n= no of electrons gained or lost = 2

F= faraday's constant

$E^0$ = standard emf = 1.98V

$\Delta G^0=-2\times 96500\times (1.98)=-3.8\times 10^{5}J$

Thus the value of $\Delta G^0$ is $-3.8\times 10^{5}J$

8 0

1 year ago

A scientist performs an experiment in which they create an artificial cell with a selectively permeable membrane through which o

lozanna [386]

Answer:

Water moves into the cell

Explanation:

As shown in the question above, the cell is high in glucose and placed in a glass filled with water. This cell has a semi permeable membrane that allows only water to pass through, as the concentration of water within the cell is low, the cell will attempt to strike a balance with the medium it is inserted into. For this reason, what is likely to happen is the passage of water from the most concentrated to the least concentrated medium, that is, the water will pass from the cup to the cell.

water moves into the cell through osmosis.during osmosis water moves from a region of low concentration of solute to a region of high concentration of solute.the glucose introduced into the cell makes it more concentrated.

In this case the cell is hypertonic and water would enter into the cell through the semi permeable membrane.this membrane allows water to pass through but not glucose.this movement of water into the cell causes the cell to become turgid.

8 0

1 year ago