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Lostsunrise [7]
2 years ago
5

A compound is 2.00% H by mass, 32.7% S by mass, and 65.3% O by mass. What is its empirical formula? The second step is to calcul

ate the number of moles of each element present in the sample. To do this, you must divide the mass of each element by its molar mass. The masses of the elements present are: mass H = g mass S = g mass O = g
Chemistry
2 answers:
Free_Kalibri [48]2 years ago
8 0
Lets take 100 g of this compound,
so it is going to be 2.00 g H, 32.7 g S and 65.3 g O.

2.00 g H *1 mol H/1.01 g H ≈ 1.98 mol H
32.7 g S *1 mol S/ 32.1 g S ≈ 1.02 mol S
65.3 g O * 1 mol O/16.0 g O ≈ 4.08 mol O

1.98 mol H : 1.02 mol S : 4.08 mol O = 2 mol H : 1 mol S : 4 mol O

Empirical formula
H2SO4
lbvjy [14]2 years ago
3 0

the masses of the elements present are:

mass H = 2.00 g

mass S = 32.7 g

mass O = 65.3 g

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<h3>Answer:</h3>

1 x 10^13 stadiums

<h3>Explanation:</h3>

We are given that;

1 stadium holds = 1 × 10^5 people

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Assuming the stadium would carry an equivalent number of atoms as people.

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Number of stadiums = Total number of atoms ÷ Number of atoms per stadium

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7 0
2 years ago
The ΔG for a particular enzyme-catalyzed reaction is -20 kcal/mol. If the amount of enzyme in the reaction is doubled, what will
LUCKY_DIMON [66]

Answer:

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