Question

Write a balanced equation for the reaction of NaCH3COO (also written as NaC2H3O2) and HCl.

Answer 1

The balanced equation is as follows:

$\boxed{{\text{NaC}}{{\text{H}}_3}{\text{COO}}+{\text{HCl}}\to{\text{NaCl}}+{\text{C}}{{\text{H}}_3}{\text{COOH}}}$

Further Explanation:

The chemical reaction that contains equal number of atoms of the different elements in the reactant as well as in the product side is known as balanced chemical reaction. The chemical equation is required to be balanced to follow the Law of the conservation of mass.

Displacement reactions:

These reactions are also known as replacement or metathesis reactions. These types of reactions occur when one of the reactant is replaced by the other one. Usually the more reactive element displaces the less reactive element. Both metals and non-metals can take part in displacement reactions.

Such reactions are generally expressed as follows:

${\text{A}}+{\text{B}}-{\text{C}}\to{\text{A}}-{\text{C}}+{\text{B}}$

Examples of displacement reactions are as follows:

(a) The reaction between copper metal and silver nitrate to form silver metal and copper nitrate as:

${\text{Cu}}+{\text{AgN}}{{\text{O}}_3}\to{\text{Ag}}+{\text{Cu}}{\left({{\text{N}}{{\text{O}}_3}}\right)_2}$

(b) The reaction between chlorine gas and potassium bromide to form potassium chloride and bromine gas as:

${\text{C}}{{\text{l}}_2}+{\text{KBr}}\to{\text{B}}{{\text{r}}_2}+{\text{KCl}}$

The steps to balance a chemical reaction are as follows:

Step1: Complete the reaction and write the unbalanced symbol equation.

In the displacement reaction, sodium acetate $\left({{\text{NaC}}{{\text{H}}_3}{\text{COO}}}\right)$ reacts with hydrochloric acid $\left({{\text{HCl}}}\right)$ to form NaCl and ${\text{C}}{{\text{H}}_3}{\text{COOH}}$. The physical state of ${\text{NaC}}{{\text{H}}_3}{\text{COO}}$ , HCl, NaCl and ${\text{C}}{{\text{H}}_3}{\text{COOH}}$  is aqueous. The unbalanced chemical equation is as follows:

${\text{NaC}}{{\text{H}}_3}{\text{COO}}+{\text{HCl}}\to{\text{NaCl}}+{\text{C}}{{\text{H}}_3}{\text{COOH}}$

Step2: Then we write the number of atoms of all the different elements that are present in a chemical reaction in the reactant side and product side separately.

• On reactant side,

Number of sodium atom is 1.

Number of carbon atoms is 2.

Number of oxygen atoms is 2.

Number of hydrogen atom is 4

Number of chlorine atoms is 1.

• On product side,

Number of sodium atom is 1.

Number of carbon atoms is 2.

Number of oxygen atoms is 2.

Number of hydrogen atom is 4.

Number of chlorine atoms is 1.

Step3: Initially, we try to balance the number of other atoms of elements except for carbon, oxygen, and hydrogen by multiplying with some number on any side.

Sodium and chlorine atoms are balanced on both sides. Now the reaction is,

${\text{NaC}}{{\text{H}}_3}{\text{COO}}+{\text{HCl}}\to{\text{NaCl}}+{\text{C}}{{\text{H}}_3}{\text{COOH}}$

Step 4: After this, we balance the number of atoms of carbon and then hydrogen atom followed by oxygen atoms.

Carbon, hydrogen, and oxygen atoms are balanced on both sides. Now the reaction is,

${\text{NaC}}{{\text{H}}_3}{\text{COO}}+{\text{HCl}}\to{\text{NaCl}}+{\text{C}}{{\text{H}}_3}{\text{COOH}}$

Step5: Finally, we check the number of atoms of each element on both the sides. If the number is same then the chemical equation is balanced.

The balanced chemical equation is as follows:

${\text{NaC}}{{\text{H}}_3}{\text{COO}}+{\text{HCl}}\to{\text{NaCl}}+{\text{C}}{{\text{H}}_3}{\text{COOH}}$

Learn more:

1. Balanced chemical equation: brainly.com/question/1405182

2. Number of covalent bonds does nitrogen formed with its unpaired: brainly.com/question/5974553

Answer details:

Grade: High School

Subject: Chemistry

Chapter: Chemical reaction and equation

Keywords: Balancing, displacement reaction, NaCl, CH3COOH, CH3COO, NaCH3COO, HCl, atoms, oxygen, carbon, hydrogen, chlorine.

Answer 2

The balance chemical equation is:

NaCH₃COO + HCl → NaCl + HCH₃COO

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